a)

Phương trình đã cho:

X(x+1)-(x+1)^2=5

Khai triển vế trái:

X^2+x-(x^2+2x+1)=5

Rút gọn: x^2+x-x^2-2x-1=5

-x-1=5

b)

Cộng 1 vào hai vế:

-x=6

Nhân -1 vào hai vế:

X=-6

a)

X^3+8y^3=x^3+(2y^3)

X^3+8y^3=(x+2y)(x^2-x(2y)+(2y)^2)

X^3+8y^3=(x+2y)(x^2-2xy+4y^2)

b)

(X+y)^2-2^2=(x+y-2)(x+y+2)

a)

X^3+8y^3=x^3+(2y^3)

X^3+8y^3=(x+2y)(x^2-x(2y)+(2y)^2)

X^3+8y^3=(x+2y)(x^2-2xy+4y^2)

b)

(X+y)^2-2^2=(x+y-2)(x+y+2)

a)

X^3+8y^3=x^3+(2y^3)

X^3+8y^3=(x+2y)(x^2-x(2y)+(2y)^2)

X^3+8y^3=(x+2y)(x^2-2xy+4y^2)

b)

(X+y)^2-2^2=(x+y-2)(x+y+2)

A)

(2x-3)^2=2x^2-2(2x)(3)+3^2

(2x-3)^2=4x^2-12x+9

b)

(x-2)^3=x^3-3(x^2)(2)+3(x)(2^2)-2^3.

(x-2)^3=x^3-6x^2+12x-8

A)

(2x-3)^2=2x^2-2(2x)(3)+3^2

(2x-3)^2=4x^2-12x+9

b)

(x-2)^3=x^3-3(x^2)(2)+3(x)(2^2)-2^3.

(x-2)^3=x^3-6x^2+12x-8

A)

(2x-3)^2=2x^2-2(2x)(3)+3^2

(2x-3)^2=4x^2-12x+9

b)

(x-2)^3=x^3-3(x^2)(2)+3(x)(2^2)-2^3.

(x-2)^3=x^3-6x^2+12x-8

A)

(2x-3)^2=2x^2-2(2x)(3)+3^2

(2x-3)^2=4x^2-12x+9

b)

(x-2)^3=x^3-3(x^2)(2)+3(x)(2^2)-2^3.

(x-2)^3=x^3-6x^2+12x-8

A)

(2x-3)^2=2x^2-2(2x)(3)+3^2

(2x-3)^2=4x^2-12x+9

b)

(x-2)^3=x^3-3(x^2)(2)+3(x)(2^2)-2^3.

(x-2)^3=x^3-6x^2+12x-8

A)

(2x-3)^2=2x^2-2(2x)(3)+3^2

(2x-3)^2=4x^2-12x+9

b)

(x-2)^3=x^3-3(x^2)(2)+3(x)(2^2)-2^3.

(x-2)^3=x^3-6x^2+12x-8