a x×(3xy+6x²+x)

=3x²y+6x³+x²

-2y×(3xy+6x²+x)

=-6x²y²-12x³y-2x²y

=3x²y+6x³+x²-6x²y²-12x³y-2x²y

=(3x²y-2x²y)+6x³+x²-6x²y²-12x³y

=x²y+6x³+x²-6x²y²-12x³y

b -6x²y³÷(18x⁴y³-24x³y⁴+12x³y³)

=-3x²y-4xy-2x

a x×(3xy+6x²+x)

=3x²y+6x³+x²

-2y×(3xy+6x²+x)

=-6x²y²-12x³y-2x²y

=3x²y+6x³+x²-6x²y²-12x³y-2x²y

=(3x²y-2x²y)+6x³+x²-6x²y²-12x³y

=x²y+6x³+x²-6x²y²-12x³y

b -6x²y³÷(18x⁴y³-24x³y⁴+12x³y³)

=-3x²y-4xy-2x

1 a) bậc2 bật-1 bật2 bật0

b)2×(-1)-0,5-3×(-1)+8×0,25-1

=2×[(-1)-1-1-3]+8×[(-0,5)×0,25]

=2×(-6)+8×0,125

=(2×0,125)-6+8

=0,25+2

=2,25

2

A+B=5xy²-3x²+2y-1-xy²+9x²y-2y+6

=(5xy²-xy²)+(2y-2y)+[(-1)+6]-3x²+9x²y

=4xy²-5-3x²+9x²y

A-B=5xy²-3x²+2y-1-xy²-9x²y+2y-6

=(5xy²-xy²)+(2y+2y)+[(-1)-6]-3x²-9x²y

=4xy²+4y-7-3x²y

1 a) bậc2 bật-1 bật2 bật0

b)2×(-1)-0,5-3×(-1)+8×0,25-1

=2×[(-1)-1-1-3]+8×[(-0,5)×0,25]

=2×(-6)+8×0,125

=(2×0,125)-6+8

=0,25+2

=2,25

2

A+B=5xy²-3x²+2y-1-xy²+9x²y-2y+6

=(5xy²-xy²)+(2y-2y)+[(-1)+6]-3x²+9x²y

=4xy²-5-3x²+9x²y

A-B=5xy²-3x²+2y-1-xy²-9x²y+2y-6

=(5xy²-xy²)+(2y+2y)+[(-1)-6]-3x²-9x²y

=4xy²+4y-7-3x²y