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2026-03-17 23:12:10
bo
2026-03-17 23:12:01
bo
2026-03-17 23:11:25
\(𝑡 2 − 𝑡 1 = 0 , 75\)
\(\frac{d}{12}-\frac{d}{15}=0,75\)
2026-03-17 23:03:31
a,=\(\frac{3x+15}{\left(x-3\right)\left(x+3\right)}+\frac{1\left(x-3\right)}{\left(x-3\right)\left(x+3\right)}-\frac{2\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}\)
=\(\frac{3x+15+\left(1x-3\right)-\left(2x+6\right)}{\left(x-3\right)\left(x+3\right)}\)
=\(\frac{3x+15+1x-3-2x-6}{\left(x-3\right)\left(x+3\right)}\)
=\(\frac{2𝑥+6}{(𝑥-3)(𝑥+3)}\)
=\(\frac{2(𝑥+3)}{(𝑥-3)(𝑥+3)}\)=\(\frac{2}{x-3}\)
b,=\(𝑥 − 3 = 3\)
x=6