\(\frac{\sqrt{6\left(\sum_{n=1}^{\infty}\frac{1}{n^2}\right)}}{\lim_{s\rarr1^{+}}\left(s-1\right)\zeta\left(s\right)\cdot\Gamma\left(\frac12\right)^2}\cdot\Pi\left(\frac12\right)^2\cdot4\)

rất phức tạp đúng ko

\(\left(\sum_{i=0}^{63}2^{i}\right)\cdot\left(e^{i\pi}+2\right)\cdot\left(\int_0^{\infty}\!e^{-x}\,\mathrm{d}x\right)\cdot\left(\sin^2\left(\theta\right)+\cos^2\left(\theta\right)\right)\cdot\left(\lim\limits_{x\to0}\frac{\sin x}{x}\right)\cdot\frac{e^{i\pi}}{-1}\cdot1^{\infty}\)

18.446.744.073.709.551.615 hạt, tương đương với \(2^{64}-1\) hạt

tặng coin cho tui đi

quá dễ

\(\sqrt{8100}\)

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