1. Phương trình điện phân

\(2 A l_{2} O_{3} \rightarrow 4 A l + 3 O_{2}\)

Theo phương trình:

• \(2 A l_{2} O_{3}\) (204 g) → \(4 A l\) (108 g)

⇒ \(1\) mol \(A l_{2} O_{3}\) tạo \(2\) mol \(A l\).

2. Tính khối lượng \(A l_{2} O_{3}\) cần theo lí thuyết

Tỉ lệ khối lượng:

\(\frac{m_{A l_{2} O_{3}}}{m_{A l}} = \frac{204}{108}\)

Với \(4\) tấn Al:

\(m_{Al_2O_3\textrm{ }lt}=4\times\frac{204}{108}=7,56\text{ t}\overset{ˊ}{\hat{\text{a}}}\text{n}\)

3. Tính theo hiệu suất 95%

\(m_{Al_2O_3\textrm{ }thực}=\frac{7 , 56}{0 , 95}\approx7,96\text{ t}\overset{ˊ}{\hat{\text{a}}}\text{n}\)

4. Tính khối lượng quặng bauxite

Quặng chứa 48% \(A l_{2} O_{3}\):

\(m_{quặng}=\frac{7 , 96}{0 , 48}\approx16,6\text{ t}\overset{ˊ}{\hat{\text{a}}}\text{n}\)

• \(2 N a C l + 2 H_{2} O \overset{đ i ệ n \&\text{nbsp}; p h \hat{a} n}{\rightarrow} 2 N a O H + H_{2} + C l_{2}\)
• \(N a O H + C O_{2} \rightarrow N a H C O_{3}\)
• \(2 N a H C O_{3} \overset{\Delta}{\rightarrow} N a_{2} C O_{3} + C O_{2} + H_{2} O\)
• \(N a_{2} C O_{3} + 2 H N O_{3} \rightarrow 2 N a N O_{3} + C O_{2} + H_{2} O\)

• \(2 N a C l + 2 H_{2} O \overset{đ i ệ n \&\text{nbsp}; p h \hat{a} n}{\rightarrow} 2 N a O H + H_{2} + C l_{2}\)
• \(N a O H + C O_{2} \rightarrow N a H C O_{3}\)
• \(2 N a H C O_{3} \overset{\Delta}{\rightarrow} N a_{2} C O_{3} + C O_{2} + H_{2} O\)
• \(N a_{2} C O_{3} + 2 H N O_{3} \rightarrow 2 N a N O_{3} + C O_{2} + H_{2} O\)

• \(2 N a C l + 2 H_{2} O \overset{đ i ệ n \&\text{nbsp}; p h \hat{a} n}{\rightarrow} 2 N a O H + H_{2} + C l_{2}\)
• \(N a O H + C O_{2} \rightarrow N a H C O_{3}\)
• \(2 N a H C O_{3} \overset{\Delta}{\rightarrow} N a_{2} C O_{3} + C O_{2} + H_{2} O\)
• \(N a_{2} C O_{3} + 2 H N O_{3} \rightarrow 2 N a N O_{3} + C O_{2} + H_{2} O\)

• \(2 N a C l + 2 H_{2} O \overset{đ i ệ n \&\text{nbsp}; p h \hat{a} n}{\rightarrow} 2 N a O H + H_{2} + C l_{2}\)
• \(N a O H + C O_{2} \rightarrow N a H C O_{3}\)
• \(2 N a H C O_{3} \overset{\Delta}{\rightarrow} N a_{2} C O_{3} + C O_{2} + H_{2} O\)
• \(N a_{2} C O_{3} + 2 H N O_{3} \rightarrow 2 N a N O_{3} + C O_{2} + H_{2} O\)

• \(2 N a C l + 2 H_{2} O \overset{đ i ệ n \&\text{nbsp}; p h \hat{a} n}{\rightarrow} 2 N a O H + H_{2} + C l_{2}\)
• \(N a O H + C O_{2} \rightarrow N a H C O_{3}\)
• \(2 N a H C O_{3} \overset{\Delta}{\rightarrow} N a_{2} C O_{3} + C O_{2} + H_{2} O\)
• \(N a_{2} C O_{3} + 2 H N O_{3} \rightarrow 2 N a N O_{3} + C O_{2} + H_{2} O\)

• \(2 N a C l + 2 H_{2} O \overset{đ i ệ n \&\text{nbsp}; p h \hat{a} n}{\rightarrow} 2 N a O H + H_{2} + C l_{2}\)
• \(N a O H + C O_{2} \rightarrow N a H C O_{3}\)
• \(2 N a H C O_{3} \overset{\Delta}{\rightarrow} N a_{2} C O_{3} + C O_{2} + H_{2} O\)
• \(N a_{2} C O_{3} + 2 H N O_{3} \rightarrow 2 N a N O_{3} + C O_{2} + H_{2} O\)

• \(2 N a C l + 2 H_{2} O \overset{đ i ệ n \&\text{nbsp}; p h \hat{a} n}{\rightarrow} 2 N a O H + H_{2} + C l_{2}\)
• \(N a O H + C O_{2} \rightarrow N a H C O_{3}\)
• \(2 N a H C O_{3} \overset{\Delta}{\rightarrow} N a_{2} C O_{3} + C O_{2} + H_{2} O\)
• \(N a_{2} C O_{3} + 2 H N O_{3} \rightarrow 2 N a N O_{3} + C O_{2} + H_{2} O\)

• \(2 N a C l + 2 H_{2} O \overset{đ i ệ n \&\text{nbsp}; p h \hat{a} n}{\rightarrow} 2 N a O H + H_{2} + C l_{2}\)
• \(N a O H + C O_{2} \rightarrow N a H C O_{3}\)
• \(2 N a H C O_{3} \overset{\Delta}{\rightarrow} N a_{2} C O_{3} + C O_{2} + H_{2} O\)
• \(N a_{2} C O_{3} + 2 H N O_{3} \rightarrow 2 N a N O_{3} + C O_{2} + H_{2} O\)

• \(2 N a C l + 2 H_{2} O \overset{đ i ệ n \&\text{nbsp}; p h \hat{a} n}{\rightarrow} 2 N a O H + H_{2} + C l_{2}\)
• \(N a O H + C O_{2} \rightarrow N a H C O_{3}\)
• \(2 N a H C O_{3} \overset{\Delta}{\rightarrow} N a_{2} C O_{3} + C O_{2} + H_{2} O\)
• \(N a_{2} C O_{3} + 2 H N O_{3} \rightarrow 2 N a N O_{3} + C O_{2} + H_{2} O\)