Vũ Thùy Ngân
Giới thiệu về bản thân
a,x-\(\frac23\) =\(-\frac{5}{12}\)
x=\(\frac{-5}{12}\) +\(\frac23\)
x=\(-\frac{5}{12}\) +\(\frac{8}{12}\)
x=\(\frac{3}{12}\)
x=\(\frac14\)
Vậy x=\(\frac14\)
b,\(\frac85\) :x = \(-\frac23\)
x = \(\frac85\) : \(-\frac23\)
x=\(\frac85\) •\(\frac{-3}{2}\)
x=\(\frac{-12}{5}\)
Vậy x=\(\frac{-12}{5}\)
c,1-\(\frac37\) •x=\(\frac{-2}{7}\)
\(\frac37\) •x=1-\(\frac{-2}{7}\)
\(\frac37\) •x = 1+ \(\frac27\)
\(\frac37\) • x = \(\frac77\) + \(\frac27\)
\(\frac37\) •x = \(\frac99\)
\(\frac37\) •x = 1
x= 1 :\(\frac37\)
x = 1 • \(\frac37\)
x= \(\frac37\)
Vậy x= \(\frac37\)
a,\(\frac{-2}{7}\) +\(\frac{2}{\overline{7}}\) :\(\frac35\)
=\(\frac{-2}{7}\) +\(\frac27\) . \(\frac53\)
=\(\frac{-2}{7}\) +\(\frac{15}{21}\)
=\(\frac{-6}{21}\) +\(\frac{15}{21}\)
= \(\frac{9}{21}\)
= \(\frac37\)
b,\(-\frac{8}{19}\) + \(-\frac{4}{21}\) - \(\frac{17}{21}\) + \(\frac{27}{19}\)
= \(-\frac{8}{19}\) + \(-\frac{4}{21}\) + \(-\frac{17}{21}\) + \(\frac{27}{19}\)
=(\(-\frac{8}{19}\) + \(\frac{27}{19}\) )+ ( \(-\frac{4}{21}\) + \(-\frac{17}{21}\) )
=1+(-1)
= 0
c,\(\frac65\) •\(\frac{3}{13}\) - \(\frac65\) • \(\frac{16}{13}\)
= \(\frac65\) •(\(\frac{3}{13}\) - \(\frac{16}{13}\) )
= \(\frac65\) • (-1)
= \(-\frac{6}{13}\)