Đặng Vũ Hằng
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2025-11-29 18:42:33
2025-11-29 18:37:58
2025-11-29 18:11:57
(5x 3 y 2 −3x 2 y+xy):xy=5x 2 y−3x+1. b) Ta có: A + 2 M = P A+2M=P A = P − 2 M A=P−2M A = 3 x 3 − 2 x 2 y − x y + 3 − 2 ( x 3 − x 2 y + 2 x y + 3 ) A=3x 3 −2x 2 y−xy+3−2(x 3 −x 2 y+2xy+3) A = 3 x 3 − 2 x 2 y − 2 x y + 3 − 2 x 3 + 2 x 2 y − 4 x y − 6 A=3x 3 −2x 2 y−2xy+3−2x 3 +2x 2 y−4xy−6 A = x 3 − 6 x y − 3 A=x 3 −6xy−3.
2025-11-29 18:11:51
a) 2 ( 3 x − 1 ) = 10 2(3x−1)=10 6 x − 2 = 10 6x−2=10 6 x = 12 6x=12 x = 2 x=2 Vậy x = 2 x=2 b) ( 3 x + 4 ) 2 − ( 3 x − 1 ) ( 3 x + 1 ) = 49 (3x+4) 2 −(3x−1)(3x+1)=49 9 x 2 + 24 x + 16 − 9 x 2 + 1 = 49 9x 2 +24x+16−9x 2 +1=49 24 x = 32 24x=32 x = 4 3 x= 3 4 Vậy x = 4 3 x= 3 4 .