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2025-12-29 21:25:32
ê ý là ai hỏi
2025-12-29 21:25:05
a. Rút gọn biểu thức A Biểu thức ban đầu:
A=(1x−3−1x+3)+xx−9cap A equals open paren the fraction with numerator 1 and denominator the square root of x end-root minus 3 end-fraction minus the fraction with numerator 1 and denominator the square root of x end-root plus 3 end-fraction close paren plus the fraction with numerator the square root of x end-root and denominator x minus 9 end-fraction𝐴=1𝑥√−3−1𝑥√+3+𝑥√𝑥−9(với x≥0,x≠9x is greater than or equal to 0 comma x is not equal to 9𝑥≥0,𝑥≠9) Bước 1: Quy đồng mẫu thức hai phân số đầu tiên
Mẫu thức chung là: (x−3)(x+3)=(x)2−32=x−9open paren the square root of x end-root minus 3 close paren open paren the square root of x end-root plus 3 close paren equals open paren the square root of x end-root close paren squared minus 3 squared equals x minus 9(𝑥√−3)(𝑥√+3)=(𝑥√)2−32=𝑥−9. Ta có:
1x−3−1x+3=(x+3)−(x−3)(x−3)(x+3)the fraction with numerator 1 and denominator the square root of x end-root minus 3 end-fraction minus the fraction with numerator 1 and denominator the square root of x end-root plus 3 end-fraction equals the fraction with numerator open paren the square root of x end-root plus 3 close paren minus open paren the square root of x end-root minus 3 close paren and denominator open paren the square root of x end-root minus 3 close paren open paren the square root of x end-root plus 3 close paren end-fraction1𝑥√−3−1𝑥√+3=(𝑥√+3)−(𝑥√−3)(𝑥√−3)(𝑥√+3) =x+3−x+3x−9equals the fraction with numerator the square root of x end-root plus 3 minus the square root of x end-root plus 3 and denominator x minus 9 end-fraction=𝑥√+3−𝑥√+3𝑥−9 =6x−9equals the fraction with numerator 6 and denominator x minus 9 end-fraction=6𝑥−9 Bước 2: Cộng với phân số cuối cùng
A=6x−9+xx−9cap A equals the fraction with numerator 6 and denominator x minus 9 end-fraction plus the fraction with numerator the square root of x end-root and denominator x minus 9 end-fraction𝐴=6𝑥−9+𝑥√𝑥−9 A=x+6x−9cap A equals the fraction with numerator the square root of x end-root plus 6 and denominator x minus 9 end-fraction𝐴=𝑥√+6𝑥−9 Kết quả rút gọn: A=x+6x−9cap A equals the fraction with numerator the square root of x end-root plus 6 and denominator x minus 9 end-fraction𝐴=𝑥√+6𝑥−9
b. Tính giá trị của A tại x=100x equals 100𝑥=100 Bước 1: Kiểm tra điều kiện
x=100x equals 100𝑥=100 thỏa mãn điều kiện x≥0x is greater than or equal to 0𝑥≥0 và x≠9x is not equal to 9𝑥≠9. Bước 2: Thay giá trị vào biểu thức đã rút gọn
Thay x=100x equals 100𝑥=100 vào biểu thức A=x+6x−9cap A equals the fraction with numerator the square root of x end-root plus 6 and denominator x minus 9 end-fraction𝐴=𝑥√+6𝑥−9, ta được:
A=100+6100−9cap A equals the fraction with numerator the square root of 100 end-root plus 6 and denominator 100 minus 9 end-fraction𝐴=100√+6100−9 A=10+691cap A equals the fraction with numerator 10 plus 6 and denominator 91 end-fraction𝐴=10+691 A=1691cap A equals 16 over 91 end-fraction𝐴=1691 Kết luận:
a. Biểu thức rút gọn là A=x+6x−9cap A equals the fraction with numerator the square root of x end-root plus 6 and denominator x minus 9 end-fraction𝐴=𝑥√+6𝑥−9.
b. Tại x=100x equals 100𝑥=100, giá trị của biểu thức A=1691cap A equals 16 over 91 end-fraction𝐴=1691.
A=(1x−3−1x+3)+xx−9cap A equals open paren the fraction with numerator 1 and denominator the square root of x end-root minus 3 end-fraction minus the fraction with numerator 1 and denominator the square root of x end-root plus 3 end-fraction close paren plus the fraction with numerator the square root of x end-root and denominator x minus 9 end-fraction𝐴=1𝑥√−3−1𝑥√+3+𝑥√𝑥−9(với x≥0,x≠9x is greater than or equal to 0 comma x is not equal to 9𝑥≥0,𝑥≠9) Bước 1: Quy đồng mẫu thức hai phân số đầu tiên
Mẫu thức chung là: (x−3)(x+3)=(x)2−32=x−9open paren the square root of x end-root minus 3 close paren open paren the square root of x end-root plus 3 close paren equals open paren the square root of x end-root close paren squared minus 3 squared equals x minus 9(𝑥√−3)(𝑥√+3)=(𝑥√)2−32=𝑥−9. Ta có:
1x−3−1x+3=(x+3)−(x−3)(x−3)(x+3)the fraction with numerator 1 and denominator the square root of x end-root minus 3 end-fraction minus the fraction with numerator 1 and denominator the square root of x end-root plus 3 end-fraction equals the fraction with numerator open paren the square root of x end-root plus 3 close paren minus open paren the square root of x end-root minus 3 close paren and denominator open paren the square root of x end-root minus 3 close paren open paren the square root of x end-root plus 3 close paren end-fraction1𝑥√−3−1𝑥√+3=(𝑥√+3)−(𝑥√−3)(𝑥√−3)(𝑥√+3) =x+3−x+3x−9equals the fraction with numerator the square root of x end-root plus 3 minus the square root of x end-root plus 3 and denominator x minus 9 end-fraction=𝑥√+3−𝑥√+3𝑥−9 =6x−9equals the fraction with numerator 6 and denominator x minus 9 end-fraction=6𝑥−9 Bước 2: Cộng với phân số cuối cùng
A=6x−9+xx−9cap A equals the fraction with numerator 6 and denominator x minus 9 end-fraction plus the fraction with numerator the square root of x end-root and denominator x minus 9 end-fraction𝐴=6𝑥−9+𝑥√𝑥−9 A=x+6x−9cap A equals the fraction with numerator the square root of x end-root plus 6 and denominator x minus 9 end-fraction𝐴=𝑥√+6𝑥−9 Kết quả rút gọn: A=x+6x−9cap A equals the fraction with numerator the square root of x end-root plus 6 and denominator x minus 9 end-fraction𝐴=𝑥√+6𝑥−9
b. Tính giá trị của A tại x=100x equals 100𝑥=100 Bước 1: Kiểm tra điều kiện
x=100x equals 100𝑥=100 thỏa mãn điều kiện x≥0x is greater than or equal to 0𝑥≥0 và x≠9x is not equal to 9𝑥≠9. Bước 2: Thay giá trị vào biểu thức đã rút gọn
Thay x=100x equals 100𝑥=100 vào biểu thức A=x+6x−9cap A equals the fraction with numerator the square root of x end-root plus 6 and denominator x minus 9 end-fraction𝐴=𝑥√+6𝑥−9, ta được:
A=100+6100−9cap A equals the fraction with numerator the square root of 100 end-root plus 6 and denominator 100 minus 9 end-fraction𝐴=100√+6100−9 A=10+691cap A equals the fraction with numerator 10 plus 6 and denominator 91 end-fraction𝐴=10+691 A=1691cap A equals 16 over 91 end-fraction𝐴=1691 Kết luận:
a. Biểu thức rút gọn là A=x+6x−9cap A equals the fraction with numerator the square root of x end-root plus 6 and denominator x minus 9 end-fraction𝐴=𝑥√+6𝑥−9.
b. Tại x=100x equals 100𝑥=100, giá trị của biểu thức A=1691cap A equals 16 over 91 end-fraction𝐴=1691.
2025-12-29 21:23:49
uk
2025-12-29 21:19:41
có cái ............
2025-12-29 21:17:58
để tìm hiểu mọi thứ khó khăn
2025-12-29 21:17:15
1+1=2
2025-12-29 21:16:53
mik
2025-12-29 17:54:18
113
2025-12-29 17:53:21
loại từ ghép nhé !
2025-12-29 17:53:01
mik bt nek bạn !