a) PT: CH₃COOH + (CH₃)₂CHCH₂CH₂OH \(\rightleftharpoons\) CH₃COOCH₂CH₂CH(CH₃)₂ + H₂O

b) n_{(CH3)2CHCH2CH2OH} = \(\frac{2,2}{88}\) = 0,025 (mol)

n_CH3COOH = \(\frac{2,2}{60}\) = 0,037 (mol)

Vì phản ứng xảy ra theo tỉ lệ 1:1 => n_{CH3COOCH2CH2CH(CH3)2} = n_{(CH3)2CHCH2CH2OH} = 0,025(mol)

=> m_{CH3COOCH2CH2CH(CH3)2} = 0,025*130*70% = 2,275(g)

V_C2H5OH = \(\frac{2\cdot10}{0,8}\) = 25 (mL)

=>V_rượu = \(\frac{25}{36}\cdot100\) = 69,4 (mL)

CH₃CH₂CH₂CH₂CHO \(\underrightarrow{NaBH4}\) CH₃CH₂CH₂CH₂CH₂OH

CH₃CH₂CH(CH₃)CHO \(\underrightarrow{NaBH4}\) CH₃CH₂CH(CH₃)CH₂OH

CH₃CH(CH₃)CH₂CHO \(\underrightarrow{NaBH4}\) CH₃CH(CH₃)CH₂CH₂OH

CH₃C(CH₃)₂CHO \(\underrightarrow{NaBH4}\) CH₃C(CH₃)₂CH₂OH