Vũ Nguyễn Hoàng Tùng
Giới thiệu về bản thân
1
S=31+321+331+...+3202213S=1+31+321+...+3202113S−S=(1+31+321+...+320211)−(31+321+331+...+320221)2S=1−320221S=21(1−320221)
Ta có: \(1 - \frac{1}{3^{2022}} < 1 = > S < \frac{1}{2} \cdot 1 = \frac{1}{2}\)
S=31+321+331+...+3202213S=1+31+321+...+3202113S−S=(1+31+321+...+320211)−(31+321+331+...+320221)2S=1−320221S=21(1−320221)
Ta có: \(1 - \frac{1}{3^{2022}} < 1 = > S < \frac{1}{2} \cdot 1 = \frac{1}{2}\)
S=31+321+331+...+3202213S=1+31+321+...+3202113S−S=(1+31+321+...+320211)−(31+321+331+...+320221)2S=1−320221S=21(1−320221)
Ta có: \(1 - \frac{1}{3^{2022}} < 1 = > S < \frac{1}{2} \cdot 1 = \frac{1}{2}\)
A=(15/12+(-3/12) + (5/13 +(-18/13)=1+(-1)=0
B=11/15.(-19/13+(-7/13)= 11/15.(-2)=-22/15
C=1-1/16807.16807=1-(1/16807.16807)=1-1=0