Vũ Minh Tú
Giới thiệu về bản thân
a) \(\frac{5}{17} - \frac{25}{31} + \frac{12}{17} + \frac{- 6}{31}\)
\(= \left(\right. \frac{5}{17} + \frac{12}{17} \left.\right) + \left(\right. \frac{- 25}{31} + \frac{- 6}{31} \left.\right)\)
\(= \frac{17}{17} + \frac{- 31}{31}\)
\(= 1 + \left(\right. - 1 \left.\right) = 0\)
b) \(\frac{17}{8} : \left(\right. \frac{27}{8} + \frac{11}{4} \left.\right)\)
\(= \frac{17}{8} : \left(\right. \frac{27}{8} + \frac{22}{8} \left.\right)\)
\(= \frac{17}{8} : \frac{49}{8} = \frac{17}{8} \cdot \frac{8}{49} = \frac{17}{49}\)
c) \(\frac{1}{5} \cdot \frac{11}{16} + \frac{1}{5} \cdot \frac{5}{16} + \frac{4}{5}\)
\(= \frac{1}{5} \cdot \left(\right. \frac{11}{16} + \frac{5}{16} + 4 \left.\right)\)
\(= \frac{1}{5} \cdot \left(\right. \frac{16}{16} + 4 \left.\right)\)
\(= \frac{1}{5} \cdot \left(\right. 1 + 4 \left.\right) = \frac{1}{5} \cdot 5 = 1\)
d) \(\frac{5}{6} : 25 - 2 + \frac{- 7}{3} \cdot \frac{2}{7}\)
\(= \frac{5}{6} \cdot \frac{1}{25} - 2 + \frac{- 2}{3}\)
\(= \frac{1}{30} - \frac{6}{3} + \frac{- 2}{3}\)
\(= \frac{1}{30} - \frac{8}{3} = \frac{1}{30} - \frac{80}{30} = \frac{- 79}{30}\)
+ =131+132+133+…+160S=311+321+331+…+601
<(130+130+…+130)+(140+140+…+140)+(150+150+…+150)S<(301+301+…+301)+(401+401+…+401)+(501+501+…+501)
<1030+1040+1050<4860=45;S<3010+4010+5010<6048=54;
+ >(140+140+…+140)+(150+150+…+150)+(160+160+…+160)S>(401+401+…+401)+(501+501+…+501)+(601+601+…+601)
>1040+1050+1060>35.S>4010+5010+6010>53.