a) (125 - x) + 25 = 98

125 - x = 98 - 25

125 - x = 73

x = 125 - 73

x = 52

b) 100 : (x + 20) = 68 : 34

100 : (x + 20) = 2

x + 20 = 100 : 2

x + 20 = 50

x = 50 - 20

x = 30

c) (3x + 12) . 5 = 25 . 4 - 10

(3x + 12) . 5 = 100 - 10

(3x + 12) . 5 = 90

3x + 12 = 90 : 5

3x + 12 = 18

3x = 18 - 12

3x = 6

x = 6 : 2

x = 3

d) 210 : (2x - 3) - 20 = 10

210 : (2x - 3) = 10 + 20

210 : (2x - 3) = 30

2x - 3 = 210 : 30

2x - 3 = 70

2x = 70 + 3

2x = 73

x = 73/2

a, ( 125 - x ) + 25 = 98

⇒ 125 - x = 73

⇒ x = 52.

Vậy..

b, 100 : ( x + 20 ) = 68 : 34

⇒ 100 : ( x + 20 ) = 2

⇒ x + 20 = 50

⇒ x = 30

Vậy...

c, ( 3 . x + 12 ) . 5 = 25 . 4 - 10

⇒ ( 3 . x + 12 ) . 5 = 90

⇒ 3 .x + 12 = 18

⇒ 3x = 6

⇒ x = 2.

Vậy...

d, 210 : ( 2 .x - 3 ) - 20 = 10

⇒ ( 2 .x - 3 ) - 20 = 21

⇒ 2x - 3 = 41

⇒ 2x = 44

⇒ x = 22.

Vậy..

\(\Rightarrow10x+\left(1+2+...+20\right)=210\\ \Rightarrow10x+\dfrac{21\cdot20}{2}=210\\ \Rightarrow10x+210=210\\ \Rightarrow x=0\)

21x chứ a

b: \(\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)

\(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+3^8\cdot2^{10}\cdot5}\)

\(=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{11}\cdot3^9}\)

\(=\dfrac{1}{2}\cdot\dfrac{-2}{3}=\dfrac{-1}{3}\)

Sửa đề câu a) phải là (-2020/2021)⁰

Xin lỗi mn

A = \(\dfrac{1}{2}\) + \(\dfrac{1}{6}\) + \(\dfrac{1}{12}\) + \(\dfrac{1}{20}\) + \(\dfrac{1}{30}\)+...+\(\dfrac{1}{182}\)+ 210

 A = \(\dfrac{1}{1\times2}\) + \(\dfrac{1}{2\times3}\)+\(\dfrac{1}{3\times4}\)+ \(\dfrac{1}{4\times5}\)+...+ \(\dfrac{1}{13\times14}\)+ 210

A = \(\dfrac{1}{1}\) - \(\dfrac{1}{2}\)+ \(\dfrac{1}{2}\) - \(\dfrac{1}{3}\)+ \(\dfrac{1}{3}\)- \(\dfrac{1}{4}\)+ \(\dfrac{1}{4}\) - \(\dfrac{1}{5}\)+...+\(\dfrac{1}{13}\) - \(\dfrac{1}{14}\) + 210

A = 1 - \(\dfrac{1}{14}\) + 210

A = 211 - \(\dfrac{1}{14}\)

A = \(\dfrac{2953}{14}\)

a/ \(=\frac{21}{23}+\frac{125}{143}-\frac{101.21}{101.23}-\frac{1001.125}{1001.143}=0\)

b/ \(=\frac{4}{20}+\frac{8}{21}+\frac{2}{5}-\frac{3}{5}+\frac{2}{21}-\frac{10}{21}+\frac{3}{20}=\frac{7}{20}-\frac{1}{5}=\frac{4}{20}\)

c/ \(\frac{C}{2}=\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{420}=\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{20.21}\)

\(\frac{C}{2}=\frac{3-2}{2.3}+\frac{4-3}{3.4}+\frac{5-4}{4.5}+...+\frac{21-20}{20.21}=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{20}-\frac{1}{21}\)

\(\frac{C}{2}=\frac{1}{2}-\frac{1}{21}=\frac{19}{42}\Rightarrow C=\frac{19}{21}\)

a)210-5x=200

5x=210-200

5x=10

x=10:2

x=5

B)210-5(x-10)=200

5(x-10)=210-200

5(x-10)=10

x-10=10:5=2

x=2+10=12

c)450:[41-(2x-5)]=3 mũ 2 .5

450:[41+5-2x]=45

41+5-2x=450:45

41+5-2x=10

2x=36

x=18

D)210:x-10=20

210:x=20+10

210:x=30

x=210:30

x=7

E)(5x-39).7+3=80

(5x-39).7=77

5x-39=11

5x=50

x=10

F(2x+1):7=2 mũ 2 nhân 3 mũ 2

(2x+1):7=36

2x+1=252

2x=251

x=251/2

=>S=1+1+1+...+1 (19 số 1)

=>S=19

Tick nha vì mình đang cần

mik đang tính đừng làm phiền

a) 210 -5.x= 200

<=> 5.x    = 210 - 200

<=> 5.x     = 10

<=> x         = 10 : 5

<=> x         = 2

Vậy x = 2

b) 210 - 5 . ( x-10 ) = 200

<=> 5. (x-10)          = 210 - 200

<=> 5.(x-10)           = 10

<=> x -10                = 10 : 5

<=> x - 10              = 2

<=>x                     = 12

Vậy x = 12

d)350 : x + 10 = 20

<=> 350 : x       = 20 - 10

<=> 350 : x         = 10

<=> x                 = 350 : 10

<=> x               = 35

Vậy x = 35

e)36 : ( x - 5 ) = 2²

<=> 36 : ( x-5) = 4

<=> x - 5        = 36 : 4

<=> x - 5          = 9

<=> x                = 9 + 5

<=> x               = 14

Vậy x =14

e) [3 . (70-x) + 5 ] : 2 = 46

<=>  [3 . (70-x) + 5 ]  = 46 . 2 

<=>  [3 . (70-x) + 5 ]  = 92

<=> 210 - 3.x + 5        = 92

<=>210- 3.x              = 92 - 5

<=> 210 - 3.x            = 87

<=> 3.x                       = 210 - 87

<=> 3.x                    = 123

<=> x                      = 123 : 3

<=> x                     = 41

Vậy x = 41