a. 96 : 8 : 2 = 6

96 : ( 8 x 2 ) = 6

96 : 8 : 2 = 96 : ( 8 x 2 )

b. 81 : 9 : 3 = 3

81 : ( 9 x 3 ) = 3

81 : 9 : 3 = 81 : ( 9x 3)

D

D

a)

160 : (4 × 8) = 160 : 32 = 5

160 : 4 : 8 = 40 : 8 = 5

Vậy 160 : (4 × 8) = 160 : 4 : 8.

96 : (3 × 8) = 96 : 24 = 4

96 : 3 : 8 = 32 : 8 = 4

Vậy 96 : (3 × 8) = 96 : 3 : 8.

105 : (5 × 7) = 105 : 35 = 3

105 : 5 : 7 = 21 : 7 = 3

Vậy 105 : (5 × 7) = 105 : 5 : 7.

Nhận xét: a : (b × c) = a : b : c

b)

270 : (9 × 6) = 270 : 9 : 6 = 30 : 6 = 5

420 : (7 × 3) = 420 : 7 : 3 = 60 : 3 = 20

144 : (2 × 8) = 144 : 2 : 8 = 72 : 8 = 9

\(3\cdot\left(x+23\right)+6=96\)

\(\Rightarrow3\cdot\left(x+23\right)=90\)

\(\Rightarrow x+23=\dfrac{90}{3}\)

\(\Rightarrow x+23=30\)

\(\Rightarrow x=30-23\)

\(\Rightarrow x=7\)

\(3\times\left(x+23\right)+6=96\)

\(\Rightarrow3\times\left(x+23\right)=96-6\)

\(\Rightarrow3\times\left(x+23\right)=90\)

\(\Rightarrow x+23=90:3\)

\(\Rightarrow x+23=30\)

\(\Rightarrow x=30-23\)

\(\Rightarrow x=7\)

Vậy x = 7

`@` `\text {Ans}`

`\downarrow`

\(\dfrac{3}{5}\times\dfrac{96}{59}+\dfrac{3}{5}\times\dfrac{22}{59}\)

\(=\dfrac{3}{5}\times\left(\dfrac{96}{59}+\dfrac{22}{59}\right)\)

\(=\dfrac{3}{5}\times2\)

\(=\dfrac{6}{5}\)

\(\dfrac{3}{5}.\dfrac{96}{59}+\dfrac{3}{5}.\dfrac{22}{59}\)

\(=\dfrac{3}{5}\left(\dfrac{96}{59}+\dfrac{22}{59}\right)\)

\(=\dfrac{3}{5}.2=\dfrac{6}{5}\)

a) Đúng

b) Sai

c) Đúng

a) Đ

b) S

c) Đ

96 = 2\(^5.3\)

2\(^{x+1}\).3\(^{y}\) = 2\(^5\).3

\(x+1=\) 5 và y = 1

\(x+1=5\)

\(x=5-1\)

\(x=4\)

Vậy (\(x;y\)) = (5; 1)

Ta có: \(x+\frac{x}{3}=96-12.5\)

\(\Rightarrow\frac{2x}{3}=96-60\)

\(\Rightarrow2x:3=36\)

\(\Rightarrow2x=36.3=108\)

\(\Rightarrow x=108:2=54\)

Vậy x = 54

\(x+\frac{x}{3}=96-60=36\)

\(x+x\times\frac{1}{3}=36\)

\(x\times\frac{4}{3}=36\)

\(x=36:\frac{4}{3}=27\)

\(x+x\times\frac{1}{3}=\frac{96}{108}\)

\(x\times\left(1+\frac{1}{3}\right)=\frac{8}{9}\)

\(x\times\frac{4}{3}=\frac{8}{9}\)

\(x=\frac{8}{9}\div\frac{4}{3}\)

\(x=\frac{2}{3}\)

Vậy .............

Ta có :  \(x\)+ \(x\)x \(\frac{1}{3}\)= \(\frac{96}{108}\)

            \(x\)x \(\left(1+\frac{1}{3}\right)\)= \(\frac{96}{108}\)

            \(x\)x \(\frac{4}{3}\)= \(\frac{96}{108}\)

            \(x\)           = \(\frac{96}{108}\): \(\frac{4}{3}\)

            \(x\)           = \(\frac{96}{108}\)x \(\frac{3}{4}\)

            \(x\)           = \(\frac{24}{27}\)x  \(\frac{3}{4}\)

            \(x\)           = \(\frac{6}{9}\)