(x-5)⁴ = (x-5)⁶

(x-5)⁴ - ( x-5)⁶ = 0

(x-5)⁴.{ 1 - (x-5)² }= 0

\(\left[{}\begin{matrix}x-5=0\\(x-5)^2=1\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=5\\x-5=1\\x-5=-1\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=5\\x=6\\x=4\end{matrix}\right.\)

\(x\in\) { 4; 5; 6}

dễ thế mà cũng ko bik chia phan so = nhan đảo ngược

A. \(\frac{2}{5}\div\frac{2}{3}=\frac{2}{5}\times\frac{3}{2}=\frac{2\times3}{5\times2}=\frac{3}{5}\text{ }\)

B. \(\frac{4}{7}\div\frac{4}{5}=\frac{4}{7}\times\frac{5}{4}=\frac{4\times5}{7\times4}=\frac{5}{7}\)

C. \(\frac{1}{6}\div\frac{1}{3}=\frac{1}{6}\times\frac{3}{1}=\frac{3}{6}=\frac{1}{2}\)

D. \(\frac{1}{4}\div\frac{1}{8}=\frac{1}{4}\times\frac{8}{1}=\frac{8}{4}=2\)

Tự chép đề bài nhé

=\(\frac{11.11.25.3.65.2.169}{3.13.2.30.11.18.11}\)

=\(\frac{25.65.13.13}{13.30.18}\)

=\(\frac{5.5.65.13.13}{13.6.5.18}\)

=\(\frac{5.65.13}{6.18}\)

=\(\frac{65.65}{108}\)

tự tính tiếp

\(\frac{121.75.130.169}{39.60.11.198} \)​= \(\frac{11^2.5^2.3.13.5.2.13^2}{3.13.2^2.3.5.11.2.3^2}\)

                                      = \(\frac{11.5^2.13^2}{2^2.3^3}\)

Bài 6:

a)(x-15).15=0

⇔x-15=0

⇔x=15

b)32(x-10)=32

⇔x-10=1

⇔x=11

c)(x-5)(x-7)=0

⇔x-5=0 hay x-7=0

⇔x=5 hay x=7

d)(x-35)35=35

⇔x-35=1

⇔x=36

a: \(\left(x-15\right)\cdot15=0\)

=>x-15=0

=>x=0+15

=>x=15

b: 32(x-10)=32

=>x-10=32/32=1

=>x=1+10=11

c: (x-5)(x-7)=0

=>\(\left[\begin{array}{l}x-5=0\\ x-7=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=5\\ x=7\end{array}\right.\)

d: \(\left(x-35\right)\cdot35=35\)

=>\(x-35=\frac{35}{35}=1\)

=>x=1+35

=>x=36

4/5 + 3/15 = 1

2/3 + 32/24 = 2

5/6 + 15/18 = 5/3

k nhé:))

\(\frac{4}{5}+\frac{3}{15}=\frac{4}{5}+\frac{1}{5}=\frac{4+1}{5}=\frac{5}{5}=1\)

\(\frac{2}{3}+\frac{32}{24}=\frac{2}{3}+\frac{4}{3}=\frac{2+4}{3}=\frac{6}{3}=2\)

\(\frac{5}{6}+\frac{15}{18}=\frac{5}{6}+\frac{5}{6}=\frac{5+5}{6}=\frac{10}{6}\)

                 HT

Câu hỏi của Nguyễn Thư - Toán lớp 5 - Học toán với OnlineMath

ta nhận thấy

1/2=1-1/2

1/6=1/2-1/3

1/12=1/3-1/4

1/20=1/4-1/5

1/30=1/5-1/6

1/42=1/6-1/7

ta có:

1/2+1/6+1/12+1/20+1/30+1/42

=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7

=1-1/7

=6/7

bn tự hiểu nha

1/2+1/6+1/12+1/20+1/30+1/42 = \(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}\)

= \(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\) = 1-1/7=6/7

Ta có :  A = 1 + 6 + 6^2 + .... + 6^9 .

                = 1 + 6 . ( 1 + 6 + ..... + 6^8 ) .

Do đó A chia cho 6 dư 1 

Cảm ơn nhé!

N S R I

\(i=i'\Leftrightarrow i'=50^o\)

\(a=50^o+50^o=100^o\)

\(i=i'\Leftrightarrow i'=0^o\)

\(\Rightarrow\) i luôn luôn bằng i'