\(\frac{x}{8}< \frac{3}{5}< \frac{x+1}{8}\Rightarrow\frac{5x}{40}< \frac{24}{40}< \frac{5x+5}{40}\Rightarrow5x< 24< 5x+5\)

+)5x+1=24=>5x=23=>x=23/5 (loại)

+)5x+2=24=>5x=22=>x=22/5 (loại)

+)5x+3=24=>5x=21=>x=21/5 (loại)

+)5x+4=24=>5x=20=>x=4 (nhận)

Vậy x=4

tich mik mik tich lai cho

các bạn giải hẳn cho mình đi

A=1-1/4+1/4-1/7+1/7-1/10+....+1/n-1/(n+3)

A=1-1/(n+3)

vì 1/(n+3)lớn hơn 0 nên 1-1/(n+3)<1

=>A<1

(x-1+3)/9=1/y+2

(x+2)/9=1/(y+2)

tích chéo:x.y+2x+2y=5

phân phối ra rồi tìm ước của 5 sau đó lập bảng là ra

c.\(\dfrac{3}{7}+\dfrac{5}{7}:x=\dfrac{1}{3}\)

\(\dfrac{5}{7}:x=\dfrac{1}{3}-\dfrac{3}{7}\)

\(\dfrac{5}{7}:x=-\dfrac{2}{21}\)

\(x=\dfrac{5}{7}:-\dfrac{2}{21}\)

\(x=-\dfrac{15}{2}\)

d.\(3\dfrac{1}{4}:\left|2x-\dfrac{5}{12}\right|=\dfrac{39}{16}\)

\(\left|2x-\dfrac{5}{12}\right|=3\dfrac{1}{4}:\dfrac{39}{16}\)

\(\left|2x-\dfrac{5}{12}\right|=\dfrac{4}{3}\)

\(\rightarrow\left[{}\begin{matrix}2x-\dfrac{5}{12}=\dfrac{4}{3}\\2x-\dfrac{4}{12}=-\dfrac{4}{3}\end{matrix}\right.\) \(\rightarrow\left[{}\begin{matrix}2x=\dfrac{7}{4}\\2x=-\dfrac{11}{12}\end{matrix}\right.\) \(\rightarrow\left[{}\begin{matrix}x=\dfrac{7}{8}\\x=-\dfrac{11}{24}\end{matrix}\right.\)

A, \(\dfrac{4}{9}+x=\dfrac{5}{3}\)

\(x\)\(=\dfrac{5}{3}-\dfrac{4}{9}\)

\(x\)\(=\dfrac{11}{9}\)

B,\(\dfrac{3}{4}.x=\dfrac{-1}{2}\)

\(x=\dfrac{-1}{2}:\dfrac{3}{4}\)

\(x=\)\(\dfrac{-2}{3}\)

mk ko bt 123

quy đồng lên
\(\frac{40}{70}< \frac{x}{70}< \frac{50}{70}\)
x thuộc {41;42;43;44;45;46;47;48;49}

\(\frac{41}{70};\frac{42}{70}\frac{43}{70}\frac{44}{70}\frac{45}{70}\frac{46}{70}\frac{47}{70}\frac{48}{70}\frac{49}{70}\)