Bài 2:

\(a,45+170+25+30\)

\(=\left(45+25\right)+\left(170+30\right)\)

\(=60+200=260\)

Bài 3:

\(a,\left(x-6\right).5=150\)

\(x-6=150:5\)

\(x-6=30\)

\(x=30+6\)

\(x=36\)

\(b,2^5.\left(3x-2\right)=2^3.2^6\)

\(2^5.\left(3x-2\right)=2^{3+6}\)

\(2^5.\left(3x-2\right)=2^9\)

\(3x-2=2^9:2^5\)

\(3x-2=2^4=16\)

\(3x=16+2\)

\(3x=22\)

\(x=22:3\)

\(x\approx7,3\)

\(c,100-7.\left(x-5\right)=51\)

\(7.\left(x-5\right)=100-51\)

\(7.\left(x-5\right)=49\)

\(x-5=49:7\)

\(x-5=7\)

\(x=7+5\)

\(x=12\)

Phần d) bạn thiếu dữ liệu ạ.

Giúp với ạ 

a, -12(x-5)+7(3-x)=15

=> -12x+60+21-7x=15

=>-19x+81=15

=>-19x=15-81

=>-19x=....

tách ra rồi tính

a/ => -12x + 60 + 21 - 7x = 15

    => -19x = -66

    => x = 66/19

b/ => 30x + 60 - 6x + 30 - 24x = 100

    => 0x = 10

     => vô nghiệm

a.  -12 (x-5) +7(3-x) = -12x+60+21-7x=-19x+81=15

=> -19x=15-81=-66

=> x=66/19

b. 30(x+2) - 5 (x-5) - 24x = 30x+60-5x+25-24x =(30x-5x-24x)+(60+25)=x+85=100

=> x=100-85=15

a)<=>(-12)(x-5)+7(3-x)=-(19x-81)

=>-(19x-81)=3.5

=>81-19x=15

=>19x=-66

=>x=\(\frac{66}{19}\)

b)30(x+2)-6(x-5)+(-24)x=2.3^235

=>2.3^2.5=2^2.5^2

=>x vô nghiệm hoặc đề sai

tui mới học lớp 5 thui à

duyệt nha^_^ ^_^

a, Ta có :\(-30+\left(25-x\right)=-1\)

               \(\Leftrightarrow\left(-30\right)+25-x=-1\)

                \(\Leftrightarrow25-x=\left(-1\right)-\left(-30\right)\)

                \(\Leftrightarrow25-x=29\\ \Leftrightarrow x=25-29\)

                    \(\Leftrightarrow x=\left(-4\right)\)

     Vậy \(x=-4\)

b,Ta có :\(\left(x+5\right)+\left(x-9\right)=x+2\)

            \(\Leftrightarrow x+5+x-9=x+2\)

            \(\Leftrightarrow2.x+\left(5-9\right)=x+2\)

           \(\Leftrightarrow\)   \(2.x+\left(-4\right)=x+2\)

            \(\Leftrightarrow2.x-x=4+2\)

                 \(\Leftrightarrow x=6\)

Vậy \(x=6\)

a) -12x + 60 + 21 - 7x =15

-12x - 7x + 81 = 15

-19x = 15 - 81

-19x = -66

x= -66 : (-19)

x = \(\frac{66}{19}\)

Vậy x = \(\frac{66}{19}\)

b) 30x + 60 - 6x + 30 - 24x= 100

30x - 6x - 24x + 60 +30= 100

x ( 30 - 6- 24 ) + 90 = 100

x. 0 + 90 =100

x. 0 =10 ( vô lý )

\(\Rightarrow\) x \(\in\phi\)

k đi mình lamf cho

a) \(100-99+100-98+100-97+100-96\)

\(=1+2+3+4\)

\(=10\)

b) \(\left(x+15\right):15-30=100\)

\(\left(x+15\right):15=100+30\)

\(\left(x+15\right):15=130\)

\(x+15=130.15\)

\(x+15=1950\)

\(x=1935\)

vậy \(x=1935\)

a) 100−99+100−98+100−97+100−96

=1+2+3+4

=10

b) (x+15):15−30=100

(x+15):15=100+30

(x+15):15=130

x+15=130.15

x+15=1950

x=1935

vậy x=1935

k mình nha

a, 35 ⋮ (x+3) => (x+3) ∈ Ư(35) = {1;5;7;35} => x ∈ {2;4;32}

b, (x+7) ⋮ 25 và x < 100

Vì (x+7) ⋮ 25 => x+7 ∈ B(25) = {0;25;50;75;...}

Mà x < 100 => x+7 ∈ {0;25;50;75}

=> x ∈ {18;43;68}

c, (x+13) ⋮ (x+1)

Ta có: x+13 = x+1+12

Vì (x+1) ⋮ (x+1) nên để (x+13) ⋮ (x+1) thì 12 ⋮ (x+1)

=> (x+1) ∈ Ư(12) = {1;2;3;4;6;12} => x ∈ {0;1;2;3;5;11}

d, 91 ⋮ x; 26 ⋮ x và 10 < x < 30

Vì 91 ⋮ x; 26 ⋮ x => x ∈ ƯC(26;91)

Ta có: 26 = 2.13; 91 = 7.13

=> ƯCLN(26;91) = 13

=> x ∈ Ư(13) = {1;13}

Mà 10 < x < 30 => x = 13

e, (x+2) ⋮ 10, (x+2) ⋮ 15, (x+2) ⋮ 25 và x < 200

Vì (x+2) ⋮ 10, (x+2) ⋮ 15, (x+2) ⋮ 25 nên (x+2) ∈ BC(10;15;25)

Ta có: 10 = 2.5; 15 = 3.5; 20 =  2 2 . 5

=> BCNN(10;15;20) =  2 2 . 3 . 5 = 60

=> (x+2) ∈ B(60) = {0;60;120;180;...}

Mà x < 200 => x ∈ {58;118;178}

\(\text{30.(x+2)-6.(x+5)-24x=100}\)

\(30x+60-6x-30-24x=100\)

\(30x-6x-24x=100+30-60\)

\(0=70\\ \Rightarrow x\in\varnothing\)

\(\text{-12.(x-15)+7.(3-x)=15}\)

\(-12x+180+21-7x=15\)

\(-12x-7x=15-21-180\)

\(-19x=-186\)

\(x=\frac{186}{19}\)

\(\text{-(574+x)=(x-12-741)-23}\)

\(-574-x=x-12-741-23\)

\(-x-x=-752+574\)

\(-2x=-178\)

\(x=89\)

chúc bạn học tốt !!!

cảm ơn Nguyễn ngọc linh nhiều nha