y x 25 - 107 = 3968

y x 25          = 3968 + 107

y x 25          = 4075

y                  = 4075 : 25

y                 = 163

\(y\times25-107=3968\)

\(y\times25=3968+107\)

\(y\times25=4075\)

\(y=4075:25\)

\(y=163\)

=>3(x-2)=4(x+5)

=>4x+20=3x-6

=>x=-26

`(x-2):4 = (5+x) :3`

`(x-2)*3 = 4*(5+x)`

`3x -6 = 20 +4x`

`3x -4x = 20 +6`

`-x =26`

`x=26`

25<15x<35

mà x là số nguyên

nên 15x=30

hay x=2

c: (x-y+4)^2

=x^2+y^2+16+2*x*(-y)-2*y*4+2*x*4

=x^2+y^2+16-2xy-8y+8x

h; x^3y^6z^9-125

\(=\left(xy^2z^3\right)^3-5^3\)

\(=\left(xy^2z^3-5\right)\left(x^2y^4z^6+5xy^2z^3+25\right)\)

Bạn nên gõ đề bằng công thức toán (biểu tượng $\sum$ góc trái khung soạn thảo) để mọi người hiểu đề của bạn hơn nhé.

Bài 2:

a) \(2\sqrt{125}+\dfrac{3}{2}\sqrt{80}-\sqrt{180}-\dfrac{2}{7}\sqrt{245}\)

\(=2\sqrt{5^2\cdot5}+\dfrac{3}{2}\sqrt{4^2\cdot5}-\sqrt{6^2\cdot5}-\dfrac{2}{7}\sqrt{7^2\cdot5}\)

\(=10\sqrt{5}+\dfrac{3\cdot4}{2}\sqrt{5}-6\sqrt{5}-\dfrac{2\cdot7}{7}\sqrt{5}\)

\(=10\sqrt{5}+6\sqrt{6}-6\sqrt{5}-2\sqrt{5}\)

\(=8\sqrt{5}\)

b) \(\sqrt{11-4\sqrt{7}}-\sqrt{16+6\sqrt{7}}\)

\(=\sqrt{\left(\sqrt{7}\right)^2-2\cdot2\cdot\sqrt{7}+2^2}-\sqrt{\left(\sqrt{7}\right)^2+2\cdot3\cdot\sqrt{7}+3^2}\)

\(=\sqrt{\left(\sqrt{7}-2\right)^2}-\sqrt{\left(\sqrt{7}+3\right)^2}\)

\(=\sqrt{7}-2-\sqrt{7}-3\)

\(=-5\)

\(2a,\\ 2\sqrt{125}+\dfrac{3}{2}.\sqrt{80}-\sqrt{180}-\dfrac{2}{7}\sqrt{245}\\ =2\sqrt{5^2.5}+\dfrac{3}{2}.\sqrt{4^2.5}-\sqrt{6^2.5}-\dfrac{2}{7}.\sqrt{7^2.5}\\ =2.5.\sqrt{5}+\dfrac{3}{2}.4.\sqrt{5}-6\sqrt{5}-\dfrac{2}{7}.7\sqrt{5}\\ =10\sqrt{5}+6\sqrt{5}-6\sqrt{5}-2\sqrt{5}=8\sqrt{5}\)

25 : x= 16:10

25:x=1,6

     x=25:1,6

     x=15,625

25 : x = 16 : 10

25 : x = 1,6

  x = 25 : 1,6

  x = 15,625

\(\frac{-2}{x}=\frac{-x}{\frac{8}{25}}\)

=>\(\left(-x\right)x=\left(-2\right).\frac{8}{25}\)

=>\(-x^2=-\frac{16}{25}\)

=>\(x^2=\frac{16}{25}\)

=>\(x=-\frac{4}{5}\) hoặc \(x=\frac{4}{5}\)

\(-\frac{2}{x}=-\frac{x}{\frac{8}{25}}\Rightarrow-2.-\frac{8}{25}=x^2\Rightarrow\frac{16}{25}=x^2\Rightarrow x=\frac{\sqrt{16}}{\sqrt{25}}=\frac{4}{5}\)