các bạn giúp mình với A=5/3+5/3^2+5/3^3...+5/3^20
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\(a,x+\dfrac{3}{7}=\dfrac{2}{5}+\dfrac{3}{10}\)
\(x+\dfrac{3}{7}=\dfrac{4}{10}+\dfrac{3}{10}\)
\(x+\dfrac{3}{7}=\dfrac{7}{10}\)
\(x=\dfrac{7}{10}-\dfrac{3}{7}\)
\(x=\dfrac{49}{70}-\dfrac{30}{70}\)
\(x=\dfrac{19}{70}\)
\(b,\dfrac{19}{20}-x=\dfrac{8}{5}-\dfrac{3}{4}\)
\(\dfrac{19}{20}-x=\dfrac{32}{20}-\dfrac{15}{20}\)
\(\dfrac{19}{20}-x=\dfrac{17}{20}\)
\(x=\dfrac{19}{20}-\dfrac{17}{20}\)
\(x=\dfrac{2}{20}\)
\(x=\dfrac{1}{10}\)
#Urushi☕
a: \(0,25x:3=\frac56\)
=>\(\frac14x=\frac56\cdot3=\frac52\)
=>\(x=\frac52:\frac14=\frac52\cdot4=10\)
b: \(-\frac25x=\left(-\frac25\right)^3\)
=>\(x=\left(-\frac25\right)^3:\left(-\frac25\right)=\left(-\frac25\right)^2=\frac{4}{25}\)
nè
a: Ta có: 0.25x3=5.60.1250.25x3=5.60.125
⇔x⋅14=134.4⇔x⋅14=134.4
hay x=537,6
b: Ta có: 2.57.5=x:352.57.5=x:35
⇔x:35=13⇔x:35=13
hay x=15x=15
15 : (-3) + (-7) . (-2) - (-20) : (-5)
= (-5) + 14 - 4
= 9 - 4
= 5
A) \(\frac{1}{2}\cdot\left(\frac{2}{9}+\frac{3}{7}-\frac{5}{27}\right)\)
\(=\frac{1}{2}\cdot\frac{1}{2}\)
\(=\frac{1}{4}\)
B) \(\left(\frac{-5}{28}+1.75+\frac{8}{35}\right):\left(-3\frac{9}{20}\right)\)
\(=\left(\frac{-5}{28}+\frac{7}{4}+\frac{8}{35}\right):\frac{-69}{20}\)
\(=\frac{14}{5}:\frac{-69}{20}\)
\(=\frac{-56}{69}\)
a) \(\dfrac{13}{20}+\dfrac{3}{5}+x=\dfrac{5}{6}\)
\(\Rightarrow\dfrac{5}{4}+x=\dfrac{5}{6}\)
\(\Rightarrow x=\dfrac{5}{6}-\dfrac{5}{4}\)
\(\Rightarrow x=\dfrac{-5}{12}\)
b) \(x+\dfrac{1}{3}=\dfrac{2}{5}-\dfrac{-1}{3}\)
\(\Rightarrow x+\dfrac{1}{3}=\dfrac{11}{15}\)
\(\Rightarrow x=\dfrac{11}{15}-\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{2}{5}\)
c)\(\dfrac{-5}{8}-x=\dfrac{-3}{20}-\dfrac{-1}{6}\)
\(\dfrac{-5}{8}-x=\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-5}{8}-\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-77}{120}\)
d) \(\dfrac{3}{5}-x=\dfrac{1}{4}+\dfrac{7}{10}\)
\(\Rightarrow\dfrac{3}{5}-x=\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{3}{5}-\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{-7}{20}\)
e) \(\dfrac{-3}{7}-x=\dfrac{4}{5}+\dfrac{-2}{3}\)
\(\Rightarrow\dfrac{-3}{7}-x=\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-3}{7}-\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-59}{105}\)
g) \(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)
\(\Rightarrow\dfrac{-5}{6}-x=\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-5}{6}-\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-13}{12}\)
(-6) + (-5) + (-4) + (-3) + (-2)
= [(-6) + (-4)] + [(-5) + (-3) + (-2)]
= (-10) + (-10)
= (-20)
P/s: Cái bước thứ 3 bạn ghi kết quả ra luôn giống như ở trên mình làm đó, không cần phải dài dòng nhé!
Chúc bạn học tốt!! ^^
Ta có: \(\left(-6\right)+\left(-5\right)+\left(-4\right)+\left(-3\right)+\left(-2\right)\)
\(=-\left(2+3+4+5+6\right)\)
=-20
ý là ai hỏi 2007
nếu còn tai phạm thì bn sẽ bj khóa tk đó