a) -48 + (-35 + 19) - (32 + 45 + 21)

= -48 - 35 + 19 - 32 - 45 - 21

= (-48 - 32) - (35 + 45) + (19 - 21)

= -80 - 80 - 2

= -162

b) -47 + (38 - 13) - (-52 + 31 - 91)

= -47 + 38 - 13 + 52 - 31 + 91

= (-47 - 13) + (38 + 52) - 31

= -60 + 90 - 31

= 30 - 31 = -1

c) 54 + (-37) - (+70) + (-163) - (-246) + (-230

= 54 - 37 - 70 - 163 + 246 - 230

= (54 + 246) - (37 + 163) - (70 + 230)

= 300 - 200 - 300

= -200

còn lại tự lm

Tính hợp lý :

A, (-48)+(-35+19)-(32+45+21)

B, (-47)+(38-13)-(-52+31-91)

C, 54+(-37)-(+70)+(-163)-(-246)+(-230

Tính hợp lý :

D, (-69)+(-14)+56-(-78)-(+97)-(-46) 

E, -35.(-14)+35.(-38)-35.46  

F, -86.42-42.(-18)+42.(-32

\(-35.-14+35.-38-35.46\)

=\(35.\left(-1.-14+-38-46\right)\)

\(=35.\left(14-38-46\right)\)

\(=35.\left(-70\right)=-2450\)

\(-86.42-42.-18+42.-32\)

\(=42\left(-86+18-32\right)\)

\(=42.-100=-4200\)

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:))))))))))))))))

5/7<7/6
17/13>45/52
4/3>99/100
34/56<42/53
97/252>85/163
73/97<91/95
 

5/7<7/6
17/13>45/52
4/3>99/100
34/56<42/53
97/252>85/163
73/97<91/95

ko có rảnh đâu nha con

\(565-13x=370\\ 13x=565-370=195\\x=\dfrac{195}{13}=15\)

\(105-\left(135-7x\right):9=97\\ \dfrac{135-7x}{9}=105-97=8\\ 135-7x=9.8=72\\ 7x=135-72=63\\ x=\dfrac{63}{7}=9\)

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2³⁸ > 3³²

Vi 2³⁸ có số mũ là 38 > số mũ 32

Sai rồi :v . Tính số mũ khii có cùng cơ số kia mà :v 

a) \(\dfrac{35}{101}=\dfrac{105}{303}< \dfrac{189}{303}\Rightarrow\dfrac{35}{101}< \dfrac{189}{303}\)

b) \(\dfrac{11}{13}< \dfrac{11+2}{13+2}=\dfrac{13}{15}< \dfrac{14}{15}\Rightarrow\dfrac{11}{-13}>\dfrac{-14}{15}\)

c) \(-\dfrac{32}{19}< 0< \dfrac{23}{32}\Rightarrow-\dfrac{32}{19}< \dfrac{23}{32}\)

d) \(1,561< 1,5661\Rightarrow-1,561>-1,5661\)

e) \(0,1=\dfrac{1}{10}=\dfrac{40}{400}< \dfrac{40+56}{400+56}=\dfrac{96}{456}< \dfrac{176}{456}\Rightarrow0,1< \dfrac{176}{456}\)

g) \(0,3=\dfrac{3}{10}=\dfrac{9}{30}< \dfrac{9+8}{30+8}=\dfrac{17}{38}< \dfrac{19}{38}\Rightarrow0,3< \dfrac{19}{38}\Rightarrow-0,3>\dfrac{-19}{38}\)

\(c)16^{20}\)và \(32^{15}\)

Ta có: \(16^{20}=\left(2^4\right)^{20}=2^{80}\)

          \(32^{15}=\left(2^5\right)15=2^{75}\)

Vì \(2^{80}>2^{75}\)

\(\Rightarrow16^{20}>32^{15}\)

Vậy \(16^{20}>32^{15}\)