(2^3 . 9^4 + 9^3 . 45) : (9^2 . 10 - 9^2)
Các bạn nhanh tay giúp mình với, mình cảm ơn rất nhiều!
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Câu a: xem lại đề bài
Câu b:
3^9 : 3^7 + 5.2^3
= 3^2 + 5.8
= 9 + 40
= 49
Câu c:
2^3.3^2 - 5^16 : 5^14
= 8.9 - 5^2
= 72 - 25
= 47
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 45 + 10 = 55
* Hok tốt !
=(1+9)+(2+8)+(3+7)+(4+6)+10+5
=10+10+10+10+10+5
=10.5+5
=50+5
=55
a: \(=\dfrac{-39+19+10}{12}=\dfrac{-10}{12}=\dfrac{-5}{6}\)
b: \(=\dfrac{2^{30}\cdot3^{16}\cdot7-2^{34}\cdot3^{15}}{2^{28}\cdot3^{21}-2^{28}\cdot3^{17}}\)
\(=\dfrac{2^{30}\cdot3^{15}\left(3\cdot7-2^4\right)}{2^{28}\cdot3^{17}\left(3^4-1\right)}=\dfrac{2^2}{3^2}\cdot\dfrac{21-16}{80}=\dfrac{4}{9}\cdot\dfrac{5}{80}\)
\(=\dfrac{20}{720}=\dfrac{1}{36}\)
TL
= (39 (3 -1)) : 29 : 310 = 2 : 29 x 1/3 = 1/28 x 1/3
Khi nào rảnh vào kênh H-EDITOR xem vid nha!!! Thanks!
\(\dfrac{9}{10}\times2+3\times\dfrac{9}{10}+\dfrac{9}{10}:\dfrac{1}{5}\)
\(=\dfrac{9}{10}\times2+\dfrac{9}{10}\times3+\dfrac{9}{10}\times5\)
\(=\dfrac{9}{10}\times\left(2+3+5\right)\)
\(=\dfrac{9}{10}\times10\)
\(=\dfrac{90}{10}\)
\(=9\)
a)=1/2 . 8/15 - 3/4.47/9
=4/15 - 47/12
=-73/20
b)=2-1/3 . -21/20
=2+7/20
=47/20
Câu b:
1/5 : 1/10 - 1/3.(6/5 - 9/4)
= 1/5 x 10 - 1/3.(24/20 - 45/20)
= 2 - 1/3.(-21/20)
= 2 + 7/20
= 40/20 + 7/20
= 47/20
\(\dfrac{-1}{9}.\dfrac{-3}{5}+\dfrac{5}{-6}.\dfrac{-3}{5}-\dfrac{7}{2}.\dfrac{3}{5}\)
\(=\dfrac{3}{5}.\left(\dfrac{1}{9}+\dfrac{5}{6}-\dfrac{7}{2}\right)\)
\(=\dfrac{3}{5}.\left(\dfrac{2}{18}+\dfrac{15}{18}-\dfrac{63}{18}\right)\)
\(=\dfrac{3}{5}.\left(-\dfrac{23}{9}\right)\)
\(=-\dfrac{69}{45}\)
\(\frac{2^3.9^4+9^3.45}{9^2.10-9^2}=\frac{9^3\left(72+45\right)}{9^3}=72+45=117\)
\(\frac{1}{2}+\frac{1}{2}.\frac{1}{3}+\frac{1}{3}.\frac{1}{4}+\frac{1}{4}.\frac{1}{5}+...+\frac{1}{9}.\frac{1}{10}\)
\(=\frac{1}{2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\)
\(=\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\)
\(=\frac{1}{2}+\frac{1}{2}-\frac{1}{10}\)
\(=\frac{9}{10}\)
45.17558299
\(\frac{\left(2^3\cdot9^4+9^3\cdot45\right)}{9^2\cdot10-9^2}\)
\(=\frac{2^3\cdot9^4+9^4\cdot5}{9^2\cdot\left(10-1\right)}=\frac{9^4\cdot\left(2^3+5\right)}{9^2\cdot9}=9\left(2^3+5\right)\)
\(=9\cdot\left(8+5\right)=9\cdot13=117\)