Câu 1=2

Câu 2=0

tick cái nha

63x(64-62)+62x(62-64)

=63x2+62x2

=(63+62)x2

=125x2

=250

Do -2x = -5y => x = 5/2y

Ta có:

5x + 3y = 62

=> 5.5/2y + 3y = 62

=> 25/2y + 3y = 62

=> 31/2y = 62

=> y = 62 : 31/2

=> y = 62 . 2/31 = 4

=> x = 4.5/2 = 10

Cho minh hoi thêm:

Tìm $x$x và $y$y biết:

-2x=-5y

và   5x+3y=62

Đáp số:

x = 

y = 

\(5x-\dfrac{4}{5}=x+\dfrac{13}{15}\)

\(\Rightarrow5x-x=\dfrac{13}{15}+\dfrac{4}{5}\)

\(\Rightarrow4x=\dfrac{13}{15}+\dfrac{12}{15}\)

\(\Rightarrow4x=\dfrac{25}{15}\)

\(\Rightarrow4x=\dfrac{5}{3}\)

\(\Rightarrow x=\dfrac{5}{3}:4\)

\(\Rightarrow x=\dfrac{5}{12}\)

      5x-4/5=x+13/15

<=>5x-x=13/15+4/5

<=>4x=5/3

<=>x=5/12

vậy ...

\(a,12\left(x-1\right)=0\\ x-1=0\\ x=1\\ b,45+5\left(x-3\right)=70\\ 5\left(x-3\right)=25\\ x-3=5\\ x=8\\ c,3.x-18:2=12\\ 3.x-9=12\\ 3.x=21\\ x=7\)

12(x-1)=0

     (x-1)=0:12

      x-1=0

      x=0+1

      x= 1

Vậy x= 1

Voi \(x\ge-3\Rightarrow|x+3|=x+3\)

\(\Rightarrow PT\Leftrightarrow5x+6-\left(x+3\right)=13\)

\(\Leftrightarrow4x+3=13\)

\(\Leftrightarrow x=\frac{5}{2}\)(THOA MAN DK )

VAY X=5/2

pt là sao ạ

1: =>\(5^{x-2}-9=2^4-\left(6^2-6^2\right)\)

=>\(5^{x-2}=16+9=25\)

=>x-2=2

=>x=4

2: \(\Leftrightarrow3^x+16=19^6:19^5-3=19-3=16\)

=>3^x=0

=>x=0

3: \(\Leftrightarrow2^x+2^x\cdot16=272\)

=>2^x*17=272

=>2^x=16

=>x=4

4: \(\Leftrightarrow2^{x-1}+3=24-\left(4^2-2^2+1\right)=24-\left(16-4+1\right)\)

=>\(2^{x-1}+3=24-16+4-1=8+4-1=12-1=11\)

=>2^x-1=8

=>x-1=3

=>x=4

a) 5x – 36 : 18 = 13

5x – 2 = 13

5x = 13+2

5x = 15

x = 15 :5

x = 3

Vậy x = 3

c) (5x – 36) : 18 = 13

(5x – 36) = 13.18

(5x – 36) = 234

5x = 234 + 36

5x = 270

x = 270:5

x = 54

Vậy x = 54

x = ( o; 1; 2; 3 )