Tìm a,b biết :
a x b = 125
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a x b = 125
Suy ra ; 125 chia hết cho a, b
125 = 5 x 25
Vậy nếu a = 5 thì b = 25
nếu b = 25 thì a = 5
Bài 10:
a: x-5=-1
=>x=-1+5
=>x=4
b: x+30=-4
=>x=-4-30
=>x=-34
c: x-(-24)=3
=>x+24=3
=>x=3-24
=>x=-21
d: 22-(-x)=12
=>22+x=12
=>x=12-22
=>x=-10
e: (x+5)+(x-9)=x+2
=>x+5+x-9=x+2
=>2x-4=x+2
=>2x-x=4+2
=>x=6
f: (27-x)+(15+x)=x-24
=>x-24=27-x+15+x=42
=>x=42+24
=>x=66
Bài 9:
a: 15-(4-x)=6
=>4-x=15-6=9
=>x=4-9=-5
b: -30+(25-x)=-1
=>-30+25-x=-1
=>-5-x=-1
=>x+5=1
=>x=1-5
=>x=-4
c: x-(12-25)=-8
=>x-(-13)=-8
=>x+13=-8
=>x=-8-13
=>x=-21
d: (x-29)-(17-38)=-9
=>x-29-(-21)=-9
=>x-29+21=-9
=>x-8=-9
=>x=-9+8
=>x=-1
Bài 8:
a: (17-229)+(17-25+229)
=17-229+17-25+229
=34-25
=9
b: (125-679+145)-(125-679)
=125-679+145-125+679
=145
a, x x 34 = 98982 – 75692
x x 34 = 23290
x = 23290 : 34
x = 685
b, x + 38758 = 754 x 125
x + 38758 = 94250
x = 94250 – 38758
x = 55492
Ta có: \(\overline{7ab}\times125=\overline{937ab}\)
=>\(125\times\left(700+\overline{ab}\right)=93700+\overline{ab}\)
=>\(125\times\overline{ab}+87500=93700+\overline{ab}\)
=>\(124\times\overline{ab}=6200\)
=>\(\overline{ab}=50\)
=>a=5; b=0
a) 2016 - 100.(x+31)=27:23
<=> 2016 - 100.(x+31) = 24 = 16
<=> 100.(x+31) = 2016 - 16 = 2000
<=> x+31 = 2000:100 = 20
<=> x = 20 - 31 = -11
b) (x+8)3 = 125
<=> (x+8)3 = 53
<=> x+8 = 5
<=> x = 5 - 8
<=> x = -3
a) \(\left(2x+1\right)^3=125\)
\(\left(2x+1\right)^3=5^3\)
\(2x+1=5\)
\(2x=4\)
\(x=2\)
b) \(3^x+25=26\times2^2+2\times3^0\)
\(3^x+25=26\times4+2\times1\)
\(3^x+25=106\)
\(3^x=106-25\)
\(3^x=81\)
\(3^x=3^4\)
\(x=4\)
(2x+1)3 = 125
a)<=> (2x+1)3 = 53
<=> 2x+1 = 5
<=> 2x = 4
<=> x = 2
3^x+25=26 . 2^2 + 2. 3^0
b)3^x+25=104 +2
3^x+25=106
3^x=106+25
3^x=81=3^4
=> x=4
a) \(\left(2x-1\right)^4=16\)
\(\)TH1: \(\left(2x-1\right)^4=2^4\)
\(=>2x-1=2\)
\(2x=2+1\)
\(2x=3\)
\(x=\dfrac{3}{2}\)
TH2: \(\left(2x-1\right)^4=\left(-2\right)^4\)
\(=>2x-1=-2\)
\(2x=-2+1\)
\(2x=-1\)
\(x=\dfrac{-1}{2}\)
Vậy x = \(\dfrac{3}{2}\) hoặc x = \(\dfrac{-1}{2}\)
________--
b) \(\left(2x+1\right)^3=125\) ( mình nghĩ đề bài đúng là vầy )
\(\left(2x+1\right)^3=5^3\)
\(=>2x+1=5\)
\(2x=5-1\)
\(2x=4\)
\(x=4:2\)
\(x=2\)
Vậy x = \(2\)
a) 1 3 + 2 3 : x = − 7
⇔ 2 3 : x = − 7 − 1 3 ⇔ 2 3 : x = − 22 3 ⇔ x = 2 3 : − 22 3 ⇔ x = − 1 11
b) 2 3 : x = 1 , 4 − 12 5
⇔ 2 3 : x = − 7 5 ⇔ x = 2 3 : − 7 5 ⇔ x = − 10 21
c) 4 , 5 − 2 x .1 4 7 = 11 14
⇔ 4 , 5 − 2 x = 11 14 : 11 7 ⇔ 9 2 − 2 x = 1 2 ⇔ 2 x = 4 ⇔ x = 2
3:
a: 3^x*3=243
=>3^x=81
=>x=4
b; 2^x*16^2=1024
=>2^x=4
=>x=2
c: 64*4^x=16^8
=>4^x=4^16/4^3=4^13
=>x=13
d: 2^x=16
=>2^x=2^4
=>x=4