x + 5 . 2 - ( 32 + 16 . 3 : 6 - 15 ) = 0

  x + 10 - ( 32 + 8 - 15 ) = 0

  x + 10 - 25 = 0

  x - 15 = 0

  x = 15

  x - 6 : 2 - ( 48 - 24 ) : 2 : 6 - 3 = 0

  x - 3 - 24 : 2 : 6 - 3 = 0

  x - 3 - 2 = 0

  x - 5 = 0

  x = 5 

x + 5 . 2- (32+48:6-15)=0

x+5.2-(32+8-15)=0

x+5.2-25=0

x+10=0+25=25

x=25-10

x=15

cau sau cung tuong tu nhu zay

tự làm nha

nhớ k đó

X=15 nha

K mik nha

học tốt

^_^

x + 5 x 2 - ( 32 + 16 x 3 : 6 - 15 ) = 0
-> x + 10 - 25 = 0
-> x + ( - 15 ) = 0
-> x               = 0 - ( - 15 ) 
-> x               = 15

1: \(=x^2+1\)

3: \(=\left(x-y-z\right)^2\)

6: \(\left(2x^3-5x^2+6x-15\right):\left(2x-5\right)\)

\(=\frac{x^2\left(2x-5\right)+3\left(2x-5\right)}{2x-5}\)

\(=\frac{\left(2x-5\right)\left(x^2+3\right)}{2x-5}=x^2+3\)

2: \(\frac{2x^4-5x^2+x^3-3-3x}{x^2-3}\)

\(=\frac{2x^4-6x^2+x^3-3x+x^2-3}{x^2-3}\)

\(=\frac{2x^2\left(x^2-3\right)+x\cdot\left(x^2-3\right)+\left(x^2-3\right)}{x^2-3}=2x^2+x+1\)

5: \(\left(2x^3+5x^2-2x+3\right):\left(2x^2-x+1\right)\)

\(=\frac{2x^3-x^2+x+6x^2-3x+3}{2x^2-x+1}=\frac{\left(2x^2-x+1\right)\left(x+3\right)}{2x^2-x+1}\)

=x+3

3: \(\left(x-y-z\right)^5:\left(x-y-z\right)^3=\left(x-y-z\right)^{5-3}=\left(x-y-z\right)^2\)

1: \(\left(x^3-3x^2+x-3\right):\left(x-3\right)\)

\(=\frac{x^2\left(x-3\right)+\left(x-3\right)}{x-3}=x^2+1\)

3/4+2/3+5/12=11/6

7/8-7/16-11/32=3/32

3/5*2/7*5/6=1/7

15/16:3/8:3/4=10/3

bạn nhé

dấu* là nhân đó

x + 5 x 2 - ( 32 + 16 x 3 : 6 - 15 ) = 0

x + 5 x 2 - 25 = 0

x + 5 x 2 = 0 + 25

x + 5 x 2 = 25

x + 10 = 25

x = 25 - 10 

x = 15

390-(x-7)=169:13

390-(x-7)=13

X-7=390-13

X-7=377

X=377+7

X=384

phần a bạn ở dưới làm r nhé

phần b chép sai đề 

phần c : 

      x - 6 : 2 - ( 48 - 24 ) : 2 : 6 - 3 = 0

<=>x - 3 - 24 : 12 - 3 = 0 

<=>x - 3 - 2 - 3 = 0

<=>x=8

Vậy x = 8

phần d :

       x + 5 . 2 - ( 32 + 16 . 3 : 16 - 15 ) = 0

 <=>x + 10 - ( 32 + 3 - 15 ) = 0

<=> x + 10 - 20 = 0

<=>x = 10

Vậy x = 10

\(x=-\dfrac{3}{16}+\dfrac{1}{4}=\dfrac{1}{16}\)

bạn viết rõ đề nhé