:)

\(=1\times10^{19}\)

máy tính đâu bạn ơi

999999999,9999999999km2 k cho minh nha 

đảm bảo đúng 10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000% lun

9999999999999999999999999999999999999999999999999999999999999999999999999999999 nha đúng 1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000%

Số này bằng chính đề bài bạn cho ra nha

thì bằng đáp án đúng

−5.3738289202763664748594987263849957748405058737850506974839203948899999999999999999999999999999999999999999999

sybau 💔💔💔💔

GIÚP TỚ VỚI 

đăng ít thôi bạn! Nếu bạn đăng lẻ ra thì bn sẽ nhận đc sự trợ giúp nhanh hơn !

a) Ta có: \(\left|x-3\right|+\left|y-2x\right|=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}x-3=0\\y-2x=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=3\\y=2x=2\cdot3=6\end{matrix}\right.\)

a: \(\left(x-2\right)^2-\left(2x+3\right)^2=0\)

=>(x-2-2x-3)(x-2+2x+3)=0

=>(-x-5)(3x+1)=0

=>(x+5)(3x+1)=0

=>\(\left[\begin{array}{l}x+5=0\\ 3x+1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=-5\\ x=-\frac13\end{array}\right.\)

b: \(9\left(2x+1\right)^2-4\left(x+1\right)^2=0\)

=>\(\left\lbrack3\left(2x+1\right)\right\rbrack^2-\left\lbrack2\left(x+1\right)\right\rbrack^2=0\)

=>\(\left(6x+3\right)^2-\left(2x+2\right)^2=0\)

=>(6x+3+2x+2)(6x+3-2x-2)=0

=>(8x+5)(4x+1)=0

=>\(\left[\begin{array}{l}8x+5=0\\ 4x+1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=-\frac58\\ x=-\frac14\end{array}\right.\)

c: \(x^3-6x^2+9x=0\)

=>\(x\left(x^2-6x+9\right)=0\)

=>\(x\left(x-3\right)^2=0\)

=>\(\left[\begin{array}{l}x=0\\ \left(x-3\right)^2=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x-3=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=3\end{array}\right.\)

d: \(x^2\left(x+1\right)-x\left(x+1\right)+x\left(x-1\right)=0\)

=>\(\left(x+1\right)\left(x^2-x\right)+x\left(x-1\right)=0\)

=>x(x+1)(x-1)+x(x-1)=0

=>x(x-1)(x+1+1)=0

=>x(x-1)(x+2)=0

=>\(\left[\begin{array}{l}x=0\\ x-1=0\\ x+2=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=1\\ x=-2\end{array}\right.\)

e: \(\left(x-2\right)^2-\left(x-2\right)\left(x+2\right)=0\)

=>(x-2)(x-2-x-2)=0

=>-4(x-2)=0

=>x-2=0

=>x=2

g: \(x^4-2x^2+1=0\)

=>\(\left(x^2-1\right)^2=0\)

=>\(x^2-1=0\)

=>\(x^2=1\)

=>\(\left[\begin{array}{l}x=1\\ x=-1\end{array}\right.\)

h: \(4x^2+y^2-20x-2y+26=0\)

=>\(4x^2-20x+25+y^2-2y+1=0\)

=>\(\left(2x-5\right)^2+\left(y-1\right)^2=0\)

=>\(\begin{cases}2x-5=0\\ y-1=0\end{cases}\Rightarrow\begin{cases}x=\frac52\\ y=1\end{cases}\)

i: \(x^2-2x+5+y^2-4y=0\)

=>\(x^2-2x+1+y^2-4y+4=0\)

=>\(\left(x-1\right)^2+\left(y-2\right)^2=0\)

=>\(\begin{cases}x-1=0\\ y-2=0\end{cases}\Rightarrow\begin{cases}x=1\\ y=2\end{cases}\)