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\(\frac{2}{7}=\frac{2.9}{7.9}=\frac{18}{63}\)

\(\frac{4}{9}=\frac{4.7}{9.7}=\frac{28}{63}\)

 \(Vì\frac{18}{63}<\frac{28}{63}nên\frac{2}{7}<\frac{4}{9}\)

Các câu khác tương tự !!

a; Cách một: 

     \(\dfrac{2}{9}\) = \(\dfrac{2\times2}{9\times2}\) = \(\dfrac{4}{18}\)  < \(\dfrac{4}{10}\) Vậy \(\dfrac{2}{9}\) < \(\dfrac{4}{10}\)

     \(\dfrac{4}{9}\) = \(\dfrac{4\times3}{9\times3}\) = \(\dfrac{12}{27}\); \(\dfrac{6}{10}\) = \(\dfrac{6\times2}{10\times2}\) = \(\dfrac{12}{20}\) 

 Vì \(\dfrac{12}{27}\) < \(\dfrac{12}{20}\) vậy \(\dfrac{4}{9}\) < \(\dfrac{12}{20}\)

     \(\dfrac{3}{8}\) = \(\dfrac{3\times4}{8\times4}\) = \(\dfrac{12}{24}\);   \(\dfrac{4}{7}\) = \(\dfrac{4\times3}{7\times3}\) = \(\dfrac{12}{21}\)

Vậy \(\dfrac{3}{8}\) < \(\dfrac{4}{7}\)

    \(\dfrac{5}{9}\) = \(\dfrac{5\times7}{9\times7}\) = \(\dfrac{35}{63}\); \(\dfrac{7}{10}\) = \(\dfrac{7\times5}{10\times5}\) = \(\dfrac{35}{50}\)

Vì \(\dfrac{35}{63}\) < \(\dfrac{35}{50}\) vậy \(\dfrac{5}{9}\) < \(\dfrac{7}{10}\)

     Cách hai:

a; \(\dfrac{2}{9}\) = \(\dfrac{2\times10}{9\times10}\) = \(\dfrac{20}{90}\); \(\dfrac{4}{10}\)  = \(\dfrac{4\times9}{10\times9}\) = \(\dfrac{36}{90}\) 

Vì \(\dfrac{20}{90}\) < \(\dfrac{36}{90}\) vậy \(\dfrac{2}{9}\) < \(\dfrac{4}{10}\)

b; \(\dfrac{4}{9}\) = \(\dfrac{4\times10}{9\times10}\) = \(\dfrac{40}{90}\); \(\dfrac{6}{10}\) = \(\dfrac{6\times9}{10\times9}\) = \(\dfrac{54}{90}\)

   Vì \(\dfrac{40}{90}\) < \(\dfrac{54}{90}\) vậy \(\dfrac{4}{9}\) < \(\dfrac{6}{10}\)

c; \(\dfrac{3}{8}\) = \(\dfrac{3\times7}{8\times7}\) = \(\dfrac{21}{56}\); \(\dfrac{4}{7}\) =  \(\dfrac{4\times8}{7\times8}\) = \(\dfrac{32}{56}\)

Vì \(\dfrac{21}{56}\) < \(\dfrac{32}{56}\) vậy \(\dfrac{3}{8}\) < \(\dfrac{4}{7}\)

d; \(\dfrac{5}{9}\) = \(\dfrac{5\times10}{9\times10}\) = \(\dfrac{50}{90}\); \(\dfrac{7}{10}\) = \(\dfrac{7\times9}{10\times9}\) = \(\dfrac{63}{90}\)

Vì \(\dfrac{50}{90}\) < \(\dfrac{63}{90}\) vậy \(\dfrac{5}{9}\) < \(\dfrac{7}{10}\) 

Bài làm

-)

\(-\frac{9}{4}=\frac{-9\cdot3}{4\cdot3}=\frac{-27}{12}\)

\(\frac{1}{3}=\frac{1\cdot4}{3\cdot4}=\frac{4}{12}\)

Vì -27 < 4 => -27/12 < 4/12

Do đó: \(-\frac{9}{4}< \frac{1}{3}\)

-)

\(-\frac{8}{3}=\frac{-8\cdot7}{3\cdot7}=\frac{-56}{21}\)

\(\frac{4}{-7}=\frac{4\cdot3}{-7\cdot3}=\frac{12}{-21}=\frac{12\cdot-1}{-21\cdot-1}=\frac{-12}{21}\)

Vì -56 < -12 => -56/21 < -12/21

Do đó: \(-\frac{8}{3}< \frac{4}{-7}\)

-)

\(\frac{9}{-5}=\frac{9\cdot2}{-5\cdot2}=\frac{18}{-10}=\frac{18\cdot-1}{-10\cdot-1}=\frac{-18}{10}\)

\(\frac{7}{-10}=\frac{7\cdot-1}{-10\cdot-1}=\frac{-7}{10}\)

Vì -18 < -7 => -18/10 < -7/10

Do đó: \(\frac{9}{-5}< \frac{7}{-10}\)

a -9/4 < 1/3

b -8/3< 4/-7

c 9/-5 < 7/-10 

ht

hơi dài một xíu

Ngoài đẹp hơn thì chẳng có gì cả

Còn lag hơn và bất tiện hơn

a; Cách một: 

     \(\dfrac{2}{9}\) = \(\dfrac{2\times2}{9\times2}\) = \(\dfrac{4}{18}\)  < \(\dfrac{4}{10}\) Vậy \(\dfrac{2}{9}\) < \(\dfrac{4}{10}\)

     \(\dfrac{4}{9}\) = \(\dfrac{4\times3}{9\times3}\) = \(\dfrac{12}{27}\); \(\dfrac{6}{10}\) = \(\dfrac{6\times2}{10\times2}\) = \(\dfrac{12}{20}\) 

 Vì \(\dfrac{12}{27}\) < \(\dfrac{12}{20}\) vậy \(\dfrac{4}{9}\) < \(\dfrac{12}{20}\)

     \(\dfrac{3}{8}\) = \(\dfrac{3\times4}{8\times4}\) = \(\dfrac{12}{24}\);   \(\dfrac{4}{7}\) = \(\dfrac{4\times3}{7\times3}\) = \(\dfrac{12}{21}\)

Vậy \(\dfrac{3}{8}\) < \(\dfrac{4}{7}\)

    \(\dfrac{5}{9}\) = \(\dfrac{5\times7}{9\times7}\) = \(\dfrac{35}{63}\); \(\dfrac{7}{10}\) = \(\dfrac{7\times5}{10\times5}\) = \(\dfrac{35}{50}\)

Vì \(\dfrac{35}{63}\) < \(\dfrac{35}{50}\) vậy \(\dfrac{5}{9}\) < \(\dfrac{7}{10}\)

       Cách hai:

a; \(\dfrac{2}{9}\) = \(\dfrac{2\times10}{9\times10}\) = \(\dfrac{20}{90}\); \(\dfrac{4}{10}\)  = \(\dfrac{4\times9}{10\times9}\) = \(\dfrac{36}{90}\) 

Vì \(\dfrac{20}{90}\) < \(\dfrac{36}{90}\) vậy \(\dfrac{2}{9}\) < \(\dfrac{4}{10}\)

b; \(\dfrac{4}{9}\) = \(\dfrac{4\times10}{9\times10}\) = \(\dfrac{40}{90}\); \(\dfrac{6}{10}\) = \(\dfrac{6\times9}{10\times9}\) = \(\dfrac{54}{90}\)

   Vì \(\dfrac{40}{90}\) < \(\dfrac{54}{90}\) vậy \(\dfrac{4}{9}\) < \(\dfrac{6}{10}\)

c; \(\dfrac{3}{8}\) = \(\dfrac{3\times7}{8\times7}\) = \(\dfrac{21}{56}\); \(\dfrac{4}{7}\) =  \(\dfrac{4\times8}{7\times8}\) = \(\dfrac{32}{56}\)

Vì \(\dfrac{21}{56}\) < \(\dfrac{32}{56}\) vậy \(\dfrac{3}{8}\) < \(\dfrac{4}{7}\)

d; \(\dfrac{5}{9}\) = \(\dfrac{5\times10}{9\times10}\) = \(\dfrac{50}{90}\); \(\dfrac{7}{10}\) = \(\dfrac{7\times9}{10\times9}\) = \(\dfrac{63}{90}\)

Vì \(\dfrac{50}{90}\) < \(\dfrac{63}{90}\) vậy \(\dfrac{5}{9}\) < \(\dfrac{7}{10}\) 

-2/3 và 3/4=8/12 và 9/12        8/12<9/12 hay 2/3<3/4

-7/10 và 3/4=28/40 và 30/40         28/40<30/40 hay 7/10<3/4

-7/8 và 9/10=70/80 và 72/80         70/80<72/80 hay 7/8<9/10

                  hok tốt nha

a, \(\frac{2}{3}\)và \(\frac{3}{4}\) MSC: 12

Ta có:

\(\frac{2}{3}=\frac{2.4}{3.4}=\frac{8}{12}\)

\(\frac{3}{4}=\frac{3.3}{4.3}=\frac{9}{12}\)

Vì \(\frac{8}{12}< \frac{9}{12}\Rightarrow\frac{2}{3}< \frac{3}{4}\)

b, \(\frac{7}{10}\)và \(\frac{3}{4}\) MSC: 20

Ta có:

\(\frac{7}{10}=\frac{7.2}{10.2}=\frac{14}{20}\)

\(\frac{3}{4}=\frac{3.5}{4.5}=\frac{15}{20}\)

Vì \(\frac{14}{20}< \frac{15}{20}\Rightarrow\frac{7}{10}< \frac{3}{4}\)

c, \(\frac{7}{8}\)và \(\frac{9}{10}\) MSC: 40

Ta có:

\(\frac{7}{8}=\frac{7.5}{8.5}=\frac{35}{40}\)

\(\frac{9}{10}=\frac{9.4}{10.4}=\frac{36}{40}\)

Vì \(\frac{35}{40}< \frac{36}{40}\Rightarrow\frac{7}{8}< \frac{9}{10}\)

P.s: Dấu "." là dấu nhân nhé em