(-66)-(X-16)+150=2X-14
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Câu 1:
$150\vdots x; 84\vdots x, 30\vdots x$
$\Rightarrow x=ƯC(150,84,30)$
$\Rightarrow ƯCLN(150,84,30)\vdots x$
$\Rightarrow 6\vdots x$. Kết hợp với điều kiện $x<16$ suy ra:
$x\in \left\{1; -1; 2; -2; 3;-3;6;-6\right\}$
Câu 2:
$x\vdots 15; x\vdots 14; x\vdots 20$
$\Rightarrow x=BC(15,14,20)$
$\Rightarrow x\vdots BCNN(15,14,20)$
$\Rightarrow x\vdots 420$
$\Rightarrow x=420k$ với $k$ là số tự nhiên.
Mà $400\leq x\leq 1200$
$\Rightarrow 400\leq 420k\leq 1200$
$\Rightarrow 0< k< 3$
Mà $k$ là stn nên $k=1$ hoặc $k=2$
$\Rightarrow x=420.1=420$ hoặc $x=420.2=840$
a: Ta có: \(150=2\cdot3\cdot5^2;84=2^2\cdot3\cdot7;30=2\cdot3\cdot5\)
Do đó: ƯCLN(150;84;30)\(=2\cdot3=6\)
150⋮x; 84⋮x; 30⋮x
=>x∈ƯC(150;84;30)
=>x∈Ư(6)
mà x<16
nên x∈{1;-1;2;-2;3;-3;6;-6}
b: Ta có: \(15=3\cdot5;14=2\cdot7;20=2^2\cdot5\)
Do đó: BCNN(15;14;20)\(=2^2\cdot3\cdot5\cdot7=4\cdot3\cdot5\cdot7=20\cdot21=420\)
x⋮15; x⋮14; x⋮20
=>x∈BC(15;14;20)
=>x∈B(420)
mà 400<=x<=1200
nên x∈{420;840}
c: 9⋮x+1
=>x+1∈{1;-1;3;-3;9;-9}
=>x∈{0;-2;2;-4;8;-10}
d: 2x+7⋮x-2
=>2x-4+11⋮x-2
=>11⋮x-2
=>x-2∈{1;-1;11;-11}
=>x∈{3;1;13;-9}
a: Ta có: \(150=5^2\cdot2\cdot3;84=2^2\cdot3\cdot7;30=2\cdot3\cdot5\)
Do đó: ƯCLN(150;84;30)\(=2\cdot3=6\)
150⋮x; 84⋮x; 30⋮x
=>x∈ƯC(150;84;30)
=>x∈Ư(6)
mà x<16
nên x∈{1;-1;2;-2;3;-3;6;-6}
b: \(15=3\cdot5;14=2\cdot7;20=2^2\cdot5\)
Do đó: BCNN(15;14;20)\(=2^2\cdot3\cdot5\cdot7=4\cdot3\cdot5\cdot7=12\cdot35=420\)
x⋮15; x⋮14; x⋮20
=>x∈BC(15;14;20)
=>x∈B(420)
mà 400<=x<=1200
nên x∈{420;840}
c: 9⋮x+1
=>x+1∈{1;-1;3;-3;9;-9}
=>x∈{0;-2;2;-4;8;-10}
d: 2x+7⋮x-2
=>2x-4+11⋮x-2
=>11⋮x-2
=>x-2∈{1;-1;11;-11}
=>x∈{3;1;13;-9}
a: Ta có: \(150=5^2\cdot2\cdot3;84=2^2\cdot3\cdot7;30=2\cdot3\cdot5\)
Do đó: ƯCLN(150;84;30)\(=2\cdot3=6\)
150⋮x; 84⋮x; 30⋮x
=>x∈ƯC(150;84;30)
=>x∈Ư(6)
mà x<16
nên x∈{1;-1;2;-2;3;-3;6;-6}
b: \(15=3\cdot5;14=2\cdot7;20=2^2\cdot5\)
Do đó: BCNN(15;14;20)\(=2^2\cdot3\cdot5\cdot7=4\cdot3\cdot5\cdot7=12\cdot35=420\)
x⋮15; x⋮14; x⋮20
=>x∈BC(15;14;20)
=>x∈B(420)
mà 400<=x<=1200
nên x∈{420;840}
c: 9⋮x+1
=>x+1∈{1;-1;3;-3;9;-9}
=>x∈{0;-2;2;-4;8;-10}
d: 2x+7⋮x-2
=>2x-4+11⋮x-2
=>11⋮x-2
=>x-2∈{1;-1;11;-11}
=>x∈{3;1;13;-9}
\(\text{1,(-14)+(2x–4^2)=/-10/×/5/}\)
\(-14-16+2x=10.5\)
\(-30+2x=50\)
\(2x=50--30\)
\(2x=80\)
\(x=80:2\)
\(x=40\)
\(\text{2,(-100)–/x+20/=-150}\)
\(|x+20|=-100--150\)
\(|x+20|=50\)
\(\Rightarrow\orbr{\begin{cases}x+20=50\\x+20=-50\end{cases}\Leftrightarrow\orbr{\begin{cases}x=30\\x=-70\end{cases}}}\)
\(\Rightarrow x\in\left\{-70;30\right\}\)
\(\text{3)3x+16=4x–61}\)
\(3x-4x=-61-16\)
\(-x=-77\)
\(\Rightarrow x=77\)
\(\text{4,2(x–5)–3(x+6)=0}\)
\(2x-10-3x-18=0\)
\(2x-3x=0+18+10\)
\(-x=28\)
\(x=-28\)
chúc bạn học tốt
VT=-4(14x-39)
VP=12(2x-27)
pt trở thành -4(14x-39)=12(2x-27)
=>156-56x=24x-324
=>-80x=-480
=>x=6
\(\left(-66\right)-\left(x-16\right)+150=2x-14\Leftrightarrow-66-x+16+150=2x-14\Leftrightarrow-3x=-114\Leftrightarrow x=38\)
\(\left(-66\right)-\left(x-16\right)+150=2x-14\)
\(-66-x+16+150=2x-14\)
\(-x-2x=66-16-150-14\)
\(-3x=-114\)
\(x=\frac{114}{3}\)
\(x=38\)