Tìm số tự nhiên x, biết
( 3. x -24 ) . 73 = 2.74
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\(\left(5x-24\right).73=2.74\)
\(\Leftrightarrow\left(5x-24\right).73=148\)
\(\Leftrightarrow5x-24=\frac{148}{73}\)
\(\Leftrightarrow5x=\frac{148}{73}+24\)
\(\Leftrightarrow5x=\frac{1900}{73}\)
\(\Leftrightarrow x=\frac{1900}{73}.\frac{1}{5}\)
\(\Leftrightarrow x=\frac{380}{73}\)
a: \(x^3=27\)
=>\(x^3=3^3\)
=>x=3
b: \(\left(2x-1\right)^3=8\)
=>\(\left(2x-1\right)^3=2^3\)
=>2x-1=2
=>2x=2+1=3
=>\(x=\frac32=1,5\)
c: \(\left(x-2\right)^2=16\)
=>\(\left[\begin{array}{l}x-2=4\\ x-2=-4\end{array}\right.\Rightarrow\left[\begin{array}{l}x=4+2=6\\ x=-4+2=-2\end{array}\right.\)
d: \(\left(2x-3\right)^2=9\)
=>\(\left[\begin{array}{l}2x-3=3\\ 2x-3=-3\end{array}\right.\Longrightarrow\left[\begin{array}{l}2x=6\\ 2x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=3\\ x=0\end{array}\right.\)
e: \(2x+5=3^4:3^2\)
=>\(2x+5=3^2=9\)
=>2x=9-5=4
=>\(x=\frac42=2\)
f: \(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)
=>\(3x-16=2\cdot\frac{7^4}{7^3}=2\cdot7=14\)
=>3x=16+14=30
=>\(x=\frac{30}{3}=10\)
a: \(x^3=27\)
=>\(x^3=3^3\)
=>x=3
b: \(\left(2x-1\right)^3=8\)
=>\(\left(2x-1\right)^3=2^3\)
=>2x-1=2
=>2x=2+1=3
=>\(x=\frac32=1,5\)
c: \(\left(x-2\right)^2=16\)
=>\(\left[\begin{array}{l}x-2=4\\ x-2=-4\end{array}\right.\Rightarrow\left[\begin{array}{l}x=4+2=6\\ x=-4+2=-2\end{array}\right.\)
d: \(\left(2x-3\right)^2=9\)
=>\(\left[\begin{array}{l}2x-3=3\\ 2x-3=-3\end{array}\right.\Longrightarrow\left[\begin{array}{l}2x=6\\ 2x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=3\\ x=0\end{array}\right.\)
e: \(2x+5=3^4:3^2\)
=>\(2x+5=3^2=9\)
=>2x=9-5=4
=>\(x=\frac42=2\)
f: \(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)
=>\(3x-16=2\cdot\frac{7^4}{7^3}=2\cdot7=14\)
=>3x=16+14=30
=>\(x=\frac{30}{3}=10\)
a) \(58+7x=100\)
\(=>7x=100-58\)
\(=>7x=42\)
\(=>x=42:7\)
\(=>x=6\)
b) \(3x-7=28\)
\(=>3x=28+7\)
\(=>3x=35\)
\(=>x=35:3\)
\(=>x=\dfrac{35}{3}\)
c) \(x-56:4=16\)
\(=>x-14=16\)
\(=>x=16+14\)
\(=>x=30\)
d) \(101+\left(36-4x\right)=105\)
\(=>36-4x=105-101\)
\(=>36-4x=4\)
\(=>4x=36-4\)
\(=>4x=32\)
\(=>x=32:4\)
\(=>x=8\)
e) \(\left(x-12\right):12=12\)
\(=>x-12=12.12\)
\(=>x-12=144\)
\(=>x=144-12\)
\(=>x=132\)
f) \(\left(3x-2^4\right).7^3=2.7^4\)
\(=>3x-2^4=2.7^4:7^3\)
\(=>3x-16=2.7=14\)
\(=>3x=14+16\)
\(=>3x=30\)
\(=>x=30:3\)
\(=>x=10\)
i) \(\left(10+2x\right).4^{2011}=4^{2013}\)
\(=>10+2x=4^{2013}:4^{2011}\)
\(=>10+2x=4^2=16\)
\(=>2x=16-10\)
\(=>2x=6\)
\(=>x=6:2\)
\(=>x=3\)
\(#WendyDang\)
123 - 5(x + 4) = 38
=> 5(x + 4) = 85
=> x + 4 = 17
=> x = 13
vậy_
(3x - 24).73 = 2.7
=> (3x - 24).73 = 14
=> 3x - 24 = 1022
=> 3x = 1046
=> x = 1046/3
(3x − 24).73 = 2.74
3x − 24 = 2.74 : 73
3x − 24 = 2.74 - 1
3x – 16 = 2.7
3x – 16 = 14
3x = 14 + 16
3x = 30
x = 30 : 3
x = 10
Vậy x = 10
a: Ta có: \(100-7\left(x-5\right)=58\)
\(\Leftrightarrow7\left(x-5\right)=42\)
\(\Leftrightarrow x-5=6\)
hay x=11
b: Ta có: \(12\left(x-1\right):3=4^3+2^3\)
\(\Leftrightarrow12\left(x-1\right)=216\)
\(\Leftrightarrow x-1=18\)
hay x=19
3x = 2.7 + 16 = 30
x = 10
\(\left(3x-2^4\right)7^3=2\cdot7^4\)
\(3x-2^4=2\cdot7^4:7^3\)
\(3x-16=14\)
\(3x=30\)
\(x=10\)