( -1,5x - 15 ) x \(\frac{2}{3}\)=\(-\frac{2}{5}\)
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a) \(\left(\frac{2x}{3}-3\right):\left(-10\right)=\frac{2}{5}\)
<=> \(\frac{2x}{3}-3=\frac{2}{5}.\left(-10\right)\)
<=> \(\frac{2x}{3}-3=-4\)
<=> \(\frac{2x}{3}=-4+3=-1\)
<=> \(2x=-1.3=-3\)
<=> \(x=\frac{-3}{2}\)
Vậy \(x=\frac{-3}{2}\)
b) \(1,5x-2\frac{1}{3}x=1,5-\frac{2}{3}\)
\(x.\left(1,5-2\frac{1}{3}\right)=\frac{5}{6}\)
\(x.\left(\frac{-5}{6}\right)=\frac{5}{6}\)
\(x=\frac{5}{6}:\left(\frac{-5}{6}\right)=\frac{5}{6}.\left(\frac{-6}{5}\right)=-1\)
Vậy \(x=-1\)
Nếu đúng thì cho mình nhé, chúc bạn học tốt !
a. \(0,5x-\frac{1}{3}x=\frac{1}{3}\)
\(\left(0,5-\frac{1}{3}\right)x=\frac{1}{3}\)
\(\frac{1}{6}x=\frac{1}{3}\)
\(x=\frac{1}{3}:\frac{1}{6}\)
\(x=2\)
b. \(x:3\frac{1}{2}=-1,5\)
\(x=-1,5\times3\frac{1}{2}\)
\(x=-5,25\)
c. \(1,5x=\frac{11}{5}\)
\(x=\frac{22}{15}\)
\(a,\)\(2x+3>5\)
\(\Rightarrow2x>5-3\)
\(\Rightarrow2x>2\)
\(\Rightarrow x>1\)
\(\frac{3}{5}x+\frac{12}{15}< 0\)
\(\Rightarrow\frac{3}{5}x+\frac{4}{5}< 0\)
\(\Rightarrow3x+4< 0\)
\(\Rightarrow3x< -4\)
\(\Rightarrow x>\frac{-4}{3}\)
a) Ta có: \(\frac{7}{8}x-5\left(x-9\right)=\frac{20x+1,5}{6}\)
\(\Leftrightarrow\frac{7x}{8}-5x+45-\frac{20x+1,5}{6}=0\)
\(\Leftrightarrow\frac{21x}{24}-\frac{120x}{24}+\frac{1080}{24}-\frac{4\left(20x+1,5\right)}{24}=0\)
\(\Leftrightarrow-99x+1080-4\left(20x+1,5\right)=0\)
\(\Leftrightarrow-99x+1080-80x-6=0\)
\(\Leftrightarrow1074-179x=0\)
\(\Leftrightarrow179x=1074\)
hay x=6
Vậy: x=6
b) Ta có: \(4\left(0,5-1,5x\right)=-\frac{5x-6}{3}\)
\(\Leftrightarrow2-6x=\frac{6-5x}{3}\)
\(\Leftrightarrow\frac{3\left(2-6x\right)}{3}-\frac{6-5x}{3}=0\)
\(\Leftrightarrow6-18x-6+5x=0\)
\(\Leftrightarrow-13x=0\)
mà -13≠0
nên x=0
Vậy: x=0
c) Ta có: \(\frac{x+4}{5}-x+4=\frac{x}{3}-\frac{x-2}{2}\)
\(\Leftrightarrow\frac{6\left(x+4\right)}{30}+\frac{30\left(-x+4\right)}{30}-\frac{10x}{30}+\frac{15\left(x-2\right)}{30}=0\)
\(\Leftrightarrow6\left(x+4\right)+30\left(4-x\right)-10x+15\left(x-2\right)=0\)
\(\Leftrightarrow6x+24+120-30x-10x+15x-30=0\)
\(\Leftrightarrow-19x+114=0\)
\(\Leftrightarrow-19x=-114\)
hay x=6
Vậy: x=6
d) Ta có: \(\frac{4x+3}{5}-\frac{6x-2}{7}=\frac{5x+4}{3}+3\)
\(\Leftrightarrow\frac{21\left(4x+3\right)}{105}-\frac{15\left(6x-2\right)}{105}-\frac{35\left(5x+4\right)}{105}-\frac{315}{105}=0\)
\(\Leftrightarrow84x+63-90x+30-175x-140-315=0\)
\(\Leftrightarrow-181x-362=0\)
\(\Leftrightarrow-181x=362\)
hay x=-2
Vậy: x=-2
e) Ta có: \(\frac{1}{4}\left(x+3\right)=3-\frac{1}{2}\left(x+1\right)-\frac{1}{3}\left(x+2\right)\)
\(\Leftrightarrow\frac{x+3}{4}=3-\frac{x+1}{2}-\frac{x+2}{3}\)
\(\Leftrightarrow\frac{3\left(x+3\right)}{12}-\frac{36}{12}+\frac{6\left(x+1\right)}{12}+\frac{4\left(x+2\right)}{12}=0\)
\(\Leftrightarrow3x+9-36+6x+6+4x+8=0\)
\(\Leftrightarrow13x-13=0\)
\(\Leftrightarrow13x=13\)
hay x=1
Vậy: x=1
Câu a:
(1/5 - 3/4).x - 1,52 = - 0,48
(4/20 - 15/20)x = -0,48 + 1,52
- 11/20x = 1,04
x = 1,04 : (-11/20)
x = - 104/55
Vậy x = - 104/55
Câu b:
|x - 2| - 1,5x = 3/4 + 5/4x -25/7
|x -2| = 5/4x + 1,5x + 3/4
|x -2| = 1,25x + 1,5x + 0,75
|x -2| = 2,75x + 0,75
|x -2| ≥ 0 ∀ x
⇒ 2,75x + 0,75 ≥ 0
2,75x ≥ - 0,75
x ≥ - 0,75 : 2,75
x ≥ -3/11
Với x ≥ -3/11 ta có:
|x - 2| = 2,75x + 0,75
x - 2 = 2,75x + 0,75 hoặc x - 2 = - 2,75x - 0,75
Th1:
x - 2 = 2,75x + 0,75
2,75x - x = - 2 - 0,75
1,75x = - 2,75
x = -2,75 : 1,75
x = - 11/7 < -3/7 (tm)
Th2:
x - 2 = - 2,75x - 0,75
x + 2,75x = 2 - 0,75
3,75x = 1,25
x = 1,75 : 3,75
x = 1/3 (ktm)
Vậy x = -11/7
( - 1,5x - 15 ) x \(\frac{2}{3}=\frac{-2}{5}\)
\(\Rightarrow\left(-1,5x-15\right)=\frac{-2}{5}:\frac{2}{3}\)
\(\Rightarrow\left(-1,5x-15\right)=\frac{-3}{5}\)
\(\Rightarrow-1,5x=\frac{-3}{5}+15\)
\(\Rightarrow-1,5x=14,4\)
\(\Rightarrow x=14,4:\left(-1,5\right)=\frac{-48}{5}=-9,6\)
LIKE nha!