(3/8 - x)^3*1/16=50% 

=> (3/8 - x)^3=50% chia cho 1 phần 16 

=> (3/8 - x)^3=8 

=> (3/8 - x)^3=3^3 

=> 3/8 - x=8 

=> x=3/8 - 8 

=> x= - 61/8

nhớ k cho m nha

Xx4+(1/2+1/4+1/8+1/16)=23/16

Xx4=23/16-(1/2+1/4+1/8+1/16)

Xx4=1/2

X=1/2:4

X=1/8

1/8 nha bn

Thank you very much !!!!

a: \(x^2\cdot x-2x^3=x^3-2x^3=-x^3\)

b: \(6x^2y\cdot3xy-2y^2\left(x+y\right)=18x^3y^2-2xy^2-2y^3\)

c: \(\left(4x^2+5x-1\right)\left(2x^3-3x\right)\)

\(=8x^5-12x^3+10x^4-15x^2-2x^3+3x\)

\(=8x^5+10x^4-14x^3-15x^2+3x\)

Ta có: x + 8 chia hết x + 1

<=> (x + 1) + 7 chia hết cho x + 1 

=> 7 chia hetes cho x + 1

=> x + 1 thuộc Ư(7) = {-1;1;-7;7}

Ta có bảng sau:

Vậy x = {-8;-2;0;6}

Ta có: x + 8 chia hết x + 1

<=> (x + 1) + 7 chia hết cho x + 1 

=> 7 chia hết cho x + 1

=> x + 1 thuộc Ư(7) = {-1;1;-7;7}

Ta có bảng sau:

Vậy x = {-8;-2;0;6}

\(\left(\frac{1}{3x5}+\frac{1}{5x7}+\frac{1}{7x9}+\frac{1}{9x11}\right)xX=\frac{8}{11}\)

\(\Rightarrow\left(\frac{2}{3x5}+\frac{2}{5x7}+\frac{2}{7x9}+\frac{2}{9x11}\right)xX=\frac{16}{11}\)

\(\Rightarrow\left(\frac{5-3}{3x5}+\frac{7-5}{5x7}+\frac{9-7}{7x9}+\frac{11-9}{9x11}\right)xX=\frac{16}{11}\)

\(\Rightarrow\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)xX=\frac{16}{11}\)

\(\Rightarrow\left(\frac{1}{3}-\frac{1}{11}\right)xX=\frac{16}{11}\Rightarrow\frac{8}{33}xX=\frac{16}{11}\)

\(\Rightarrow X=\frac{16}{11}:\frac{8}{33}=\frac{16}{11}x\frac{33}{8}=6\)

đùa ak