tìm x,y biết
a 10x:5y=20y
b)2x+1*3y=12x
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2x−3y/5=5y−2z/3=3z−5x/2=10x-15y/25=15y-6z/9=6z-10x/4=...+..+..../25+9+4=0/31=0
=> 2x=3y; 5y=2z ; 3z=5x => x/3=y/2; y/2=z/5
=> x/3=y/2 =z/5 = 12x/36=5y/10=3z/15= (12x+5y-3z)/31
x/3 = 3y/6=2z/10 = (x-3y+2z)/7
=> (12x+5y-3z)/ (x-3y+2z)=31/7
\(a.\left(8x^4-4x^3+x^2\right):2x^2=4x^2-2x+\frac{1}{2}\)
\(b.\left(2x^4-x^3+3x^2\right):\left(-\frac{1}{3x^2}\right)=-6x^6+3x^5-9x^4\)
\(c.\left(-18x^3y^5+12x^2y^2-6xy^3\right):6xy=-3x^2y^4+2xy-y^2\)
\(d.\left(\frac{3}{4x^3y^6}+\frac{6}{5x^4y^5}-\frac{9}{10x^5y}\right):-\frac{3}{5x^3y}=-\frac{5}{4y^5}-\frac{2}{xy^4}-\frac{3}{2x^2}\)
a: =>12x-64=32
=>12x=96
=>x=8
b: =>x-1=5
=>x=6
c: =>2^x*3=96
=>2^x=32
=>x=5
\(A=\frac{2x-y}{3x-y}+\frac{5y-x}{3x+y}\)
\(=\frac{\left(2x-y\right)\left(3x+y\right)+\left(5y-x\right)\left(3x-y\right)}{\left(3x-y\right)\left(3x+y\right)}\)
\(=\frac{3x^2+15xy-6y^2}{9x^2-y^2}\)
\(=\frac{3\left(x^2+5xy-2y^2\right)}{9x^2-y^2}\)
\(=\frac{3\left(10x^2+5xy-3y^2-9x^2+y^2\right)}{9x^2-y^2}\)
\(=-\frac{3\left(9x^2-y^2\right)}{9x^2-y^2}\)
= - 3 (đpcm)
~~~
\(A=\frac{1}{x}+\frac{1}{x+2}+\frac{x-2}{x^2+2x}\)
\(=\frac{x+2+x+x-2}{x^2+2x}\)
\(=\frac{3x}{x\left(x+2\right)}\)
\(=\frac{3}{x+2}\)
\(A\in Z\)
\(\Leftrightarrow3⋮x+2\)
\(\Leftrightarrow x+2\in\text{Ư}\left(3\right)=\left\{-3:-1;1;3\right\}\)
\(\Leftrightarrow x\in\left\{-5;-3;-1;1\right\}\)
2.
a. 3x(12x - 4) - 9x(4x - 3) = 30
<=> 36x2 - 12x - 36x2 + 27x = 30
<=> 36x2 - 36x2 - 12x + 27x = 30
<=> 15x = 30
<=> x = 2
b. x(5 - 2x) + 2x(x - 1) = 15
<=> 5x - 2x2 + 2x2 - 2x = 15
<=> -2x2 + 2x2 + 5x - 2x = 15
<=> 3x = 15
<=> x = 5
a) x2 ( 5x3 - x - 1212)= 5x5-x3-1212x
b) ( 3xy - x2 + y ) 2323x2y= 6969x3y2- 2323x4y+ 2323x2y2
c) x2 ( 4x3 - 5xy + 2x ) ( -1212 xy )=(4x5-5x3y+2x3).(-1212xy)
= -4848x6y +6060x4y2-2424x4y
2/ Tìm x, biết
a) 3x( 12x - 4 ) - 9x (4x - 3 ) = 30
=> 36x2-12x-36x2+27x=30
=> -12x +27x=30
=> 15x = 30
=>x =2
b ) x( 5 - 2x ) + 2x ( x - 1 )= 15
=> 5x-2x2+2x2-2x=15
=> 3x=15
=>x=5