Ta có: \(30\cdot10^8\cdot5^4-25^6\cdot16^2\cdot3\)

\(=2\cdot3\cdot5\cdot2^8\cdot5^8\cdot5^4-5^{12}\cdot2^8\cdot3\)

\(=2^9\cdot3\cdot5^{13}-2^8\cdot3\cdot5^{12}=2^8\cdot3\cdot5^{12}\left(2\cdot5-1\right)=2^8\cdot3^3\cdot5^{12}\)

\(75^3\cdot20^4+3^3\cdot5^{10}\cdot32^2\)

\(=\left(5^2\cdot3\right)^3\cdot\left(2^2\cdot5\right)^4+3^3\cdot5^{10}\cdot2^{10}\)

\(=5^6\cdot3^3\cdot2^8\cdot5^4+3^3\cdot5^{10}\cdot2^{10}=3^3\cdot2^8\cdot5^{10}\left(1+5^2\right)=3^3\cdot2^9\cdot5^{10}\cdot13\)

Ta có: \(\frac{30\cdot10^8\cdot5^4-25^6\cdot16^2\cdot3}{75^3\cdot20^4+3^3\cdot5^{10}\cdot32^2}\)

\(=\frac{2^8\cdot3^3\cdot5^{12}}{3^3\cdot2^9\cdot5^{10}\cdot13}=\frac12\cdot\frac{5^2}{13}=\frac12\cdot\frac{25}{13}=\frac{25}{26}\)

a.

\(\frac{11^4\times6-11^5}{11^4-11^5}=\frac{11^4\times\left(6-11\right)}{11^4\times\left(1-11\right)}=\frac{-5}{-10}=\frac{1}{2}\)

b.

\(\frac{9^8\times3-3^{18}}{9^8\times5+9^8\times7}=\frac{9^8\times3-\left(3^2\right)^9}{9^8\times\left(5+7\right)}=\frac{9^8\times3-9^9}{9^8\times12}=\frac{9^8\times\left(3-9\right)}{9^8\times12}=-\frac{6}{12}=-\frac{1}{2}\)

c.

\(\frac{10^5-10^5\times3}{10^5\times11}=\frac{10^5\times\left(1-3\right)}{10^5\times11}=-\frac{2}{11}\)

Chúc bạn học tốt

thanks bn

\(a.\frac{4^3.1^5}{9^2.8^2}=\frac{2^6.1}{3^4.2^6}=\frac{1}{81}\)

\(b.\frac{25^2.2^2.4^1}{3^3.2^3.224}=\frac{5^4.2^4}{3^3.2^8.7}=\frac{5^4}{3^3.2^4.7}=\frac{625}{3024}\)

\(c.\frac{25^3.5^6.5^2}{9^4.10^2}=\frac{5^{14}}{3^8.2^2.5^2}=\frac{5^{10}}{3^8.2^2}\)

=-1

=2/5

=38/43

= 3/2

các bạn đâu hết rồi, làm đi để sáng mai mình còn nộp!