Cho , , . Ta có UCLN(36;60;72) là:
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2/25=.2../25 .27../36=3/4
3/.12..=9/36
15/27=5/..9..
..20..28=5/7
36/72=..1../2
\(\dfrac{2}{25}=\dfrac{2}{25}\)
\(\dfrac{27}{36}=\dfrac{3}{4}\)
\(\dfrac{3}{12}=\dfrac{9}{36}\)
\(\dfrac{15}{27}=\dfrac{5}{9}\)
\(\dfrac{20}{28}=\dfrac{5}{7}\)
\(\dfrac{36}{72}=\dfrac{1}{2}\)
a) -72.17+72.31 - 36 . 228
= -72.17 + 72. 31 - 36.2.114
= -72 .17 + 72 . 31 -72 . 114
= -72. ( 17-31+114)
= -72 . 100
= -7200
b) ..........
= -7 . ( 16-36.9) -(-125)
= -7 . ( 16-324) +125
=-7 . ( -308) +125
= 2156+125
= 2281
a)
�)−72.17+72.31−36.228-72.17+72.31-36.228
=−72.17+72.31−36.2.114=-72.17+72.31-36.2.114
=−72.17+72.31−72.114=-72.17+72.31-72.114
=72(31−17−114)=72(31-17-114)
=72.(−100)=−7200=72.(-100)=-7200
b)�)−7.[(−2)4+(−36):(−32)]−(−5)
Ta có: \(a=\frac13-\frac34-\frac35+\frac{1}{72}-\frac29-\frac{1}{36}+\frac{1}{15}\)
\(=\left(\frac13-\frac35+\frac{1}{15}\right)+\left(-\frac34-\frac29-\frac{1}{36}+\frac{1}{72}\right)\)
\(=\left(\frac{5}{15}-\frac{9}{15}+\frac{1}{15}\right)+\left(-\frac{54}{72}-\frac{16}{72}-\frac{2}{72}+\frac{1}{72}\right)\)
\(=\frac{-3}{15}+\frac{-71}{72}=\frac{-1}{5}-\frac{71}{72}=\frac{-72}{360}-\frac{355}{360}=-\frac{427}{360}\)
Đáp án cần chọn là: C