?? = 444

? =445

\(\Rightarrow\) ? > ??

tk mik nha

nhanh tk cho

\(a=\left[\left(-\dfrac{1}{2}\right)^5\right]^{107}=\left(-\dfrac{1}{32}\right)^{107}\)

\(b=\left[\left(-\dfrac{1}{3}\right)^3\right]^{107}=\left(-\dfrac{1}{27}\right)^{107}\)

mà -1/32>-1/27

nên a>b

a>b

a: \(45^{10}\cdot5^{30}=45^{10}\cdot\left(5^3\right)^{10}\)

\(=\left(45\cdot5^3\right)^{10}=\left(3^2\cdot5^4\right)^{10}=3^{20}\cdot5^{40}\)

\(75^{19}=\left(5^2\cdot3\right)^{19}=5^{38}\cdot3^{19}\)

\(\frac{45^{10}\cdot5^{30}}{75^{19}}=\frac{3^{20}\cdot5^{40}}{5^{38}\cdot3^{19}}=5^2\cdot3=75>1\)

Do đó: \(45^{10}\cdot5^{30}>75^{19}\)

=>Đúng

b: Đúng

c: \(99^{20}=\left(99^2\right)^{10}=9801^{10}<9999^{10}\)

=>Sai

Tính bằng cách thuận tiện nhất nhé

123+132+213+231+312+321

=400+400+400

=1200

**** nha

a)  ( − 225 ) . ( − 336 ) > 0

b)  ( − 112 ) .2. ( − 26 ) . ( − 321 ) < 0

\(-\frac{231}{232}>-\frac{1320}{1321}\)

nha

chuc bn hoc gioi!

-231/232>-1320/1321

\(3^{21}=3^{20}.3=9^{10}.3\)

\(2^{31}=2^{30}.2=8^{10}.2\)

Do \(9^{10}>8^{10},3>2\)

\(\Rightarrow9^{10}.3>8^{10}.2\Rightarrow3^{21}>2^{31}\)

\(3^{21}=3^{20}\cdot3\)

\(2^{31}=2^{30}\cdot2\)

mà \(3^{20}>2^{30}\)

nên \(3^{21}>2^{31}\)

\(123+132+231+312+213+321=\left(123+321\right)+\left(132+231\right)+\left(312+213\right)=444+363+525=1332\)