Thuwch hiện phép tính bằng cách hợp lý
(-32).(-25).(-123).125
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a: 45+432+155+168
=45+155+432+168
=200+600
=800
b: \(5\cdot135-5\cdot35+175\)
\(=5\cdot\left(135-35\right)+175\)
\(=5\cdot100+175\)
=500+175
=675
c: \(129\cdot172-73\cdot129+129\)
\(=129\cdot\left(172-73+1\right)\)
\(=129\cdot100=12900\)
d: \(29\cdot73+110\cdot71+37\cdot29\)
\(=29\cdot\left(73+37\right)+110\cdot71\)
\(=29\cdot110+71\cdot110=110\cdot100=11000\)
e: \(12:\left\lbrace390:\left\lbrack500-\left(125+35\cdot7\right)\right\rbrack\right\rbrace\)
\(=12:\left\lbrace390:\left\lbrack500-\left(125+245\right)\right\rbrack\right\rbrace\)
\(=12:\left\lbrace390:\left\lbrack500-370\right\rbrack\right\rbrace=12:\left\lbrace\frac{390}{130}\right\rbrace=12:3=4\)
f: \(375:\left\lbrace32-\left\lbrack4+\left(5\cdot9-42\right)\right\rbrack\right\rbrace-14\)
\(=375:\left\lbrace32-\left\lbrack4+45-42\right\rbrack\right\rbrace-14=375:\left\lbrace32-7\right\rbrace-14\)
=375:25-14
=15-14
=1
25.6.4.8.125
=(25.4).(125.8).6
=100.1000.6
=100000.6
=600000
\(25\cdot6\cdot4\cdot8\cdot125\)
\(=25\cdot4\cdot6\cdot8\cdot125\)
\(=100\cdot6\cdot1000\)
\(=100000\cdot6\)
\(=600000\)
1. Q=165+247+528+125+315
= 100+60+5+200+40+7+500+20+8+100+20+5+300+10+5
= ( 100+200+500+100+300) + ( 60+40+20+20+10 ) +( 5+7+8+5+5 )
= 1200+150+30
=1280
R=1234+5678+8+80
=1000+200+30+4+5000+600+70+8+8+80
= ( 1000+5000) + ( 200+600 ) + (30+70+80) + ( 4+8+8)
=6000+800+180+20
=7000
Bài 1
Tính : Q=165+247+528+125+315
=(165+125)+(247+315+528)
=290+1090
= 1380
R=1234+5678+8+80
=(1234+6)+(5678+2)+80
= 1240+5680+80
= (1240+60)+(5680+20)
=1300+5700=7000
Bài 2:
A= 243-97=(243+7)-(97-7)=250-90=160
B= 400-42-58=400-(42+58)=400-100=300
C=600-67-33=600-(67+33)=600-100=500
D=200-24-46=200-(24+46)=200-70=130
E=400-5-6-7-8=400-(5+6+7+8)=400-26=374
F= 764-115-268-43-32-20-85-37
=764-(115+85)-(268+32)-(43+37)-20
=764-200-300-80-20
=164
G=350-7-18-52-48-72
=350-(18+72)-(52+48)-7
=350-90-100-7
=160-7
=153
B3:
a. =-1250000
b. =-20000
c. =0
d. =-24000
B4:
a. =-4100
b. =-2700
c. =400
d. =1007
=123+124+125-113-114-115
=(123-113)+ (124-114)+ (125-115)
=10+10+10
=30
\(\text{(123+ 124 + 125) – (113 + 114 + 115)}\)
\(=123+124+125-113-114-115\)
\(=\left(123-113\right)+\left(124-114\right)+\left(125-115\right)\)
\(=10+10+10=30.\)