Bài 10:

a: x-5=-1

=>x=-1+5

=>x=4

b: x+30=-4

=>x=-4-30

=>x=-34

c: x-(-24)=3

=>x+24=3

=>x=3-24

=>x=-21

d: 22-(-x)=12

=>22+x=12

=>x=12-22

=>x=-10

e: (x+5)+(x-9)=x+2

=>x+5+x-9=x+2

=>2x-4=x+2

=>2x-x=4+2

=>x=6

f: (27-x)+(15+x)=x-24

=>x-24=27-x+15+x=42

=>x=42+24

=>x=66

Bài 9:

a: 15-(4-x)=6

=>4-x=15-6=9

=>x=4-9=-5

b: -30+(25-x)=-1

=>-30+25-x=-1

=>-5-x=-1

=>x+5=1

=>x=1-5

=>x=-4

c: x-(12-25)=-8

=>x-(-13)=-8

=>x+13=-8

=>x=-8-13

=>x=-21

d: (x-29)-(17-38)=-9

=>x-29-(-21)=-9

=>x-29+21=-9

=>x-8=-9

=>x=-9+8

=>x=-1

Bài 8:

a: (17-229)+(17-25+229)

=17-229+17-25+229

=34-25

=9

b: (125-679+145)-(125-679)

=125-679+145-125+679

=145

có ai giúp mình với 

alooooooooooooooooooo

`@` `\text {Ans}`

`\downarrow`

`x^3 = 125`

`=> x^3 = 5^3`

`=> x = 5`

Vậy, `x = 5`

_____

`4^5 \div 4^3`

`=`\(4^{5-3}\)

`= 4^2`

______

\(8^{12}\cdot8^3\div8^{15}\)

`=`\(8^{12+3-15}\)

`=`\(8^0=1\)

______

\(7^{15}\div7^{13}\)

`=`\(7^{15-13}\)

`=`\(7^2\)

_______

\(17^{15}\cdot17^{10}\div17^{22}\)

`=`\(17^{15+10-22}\)

`= 17^3`

_______

\(5^{10}\cdot25\div5^{11}\)

`=`\(5^{10}\cdot5^2\div5^{11}\)

`=`\(5^{10+2-11}\)

`= 5`

_______

\(15^{10}\cdot225\div15^{11}\)

`=`\(15^{10}\cdot15^2\div15^{11}\)

`=`\(15^{12}\div15^{11}\)

`= 15`

`@` `\text {Kaizuu lv uuu}`

\(x^3=125\)

\(\Rightarrow x^3=5^3\)

\(\Rightarrow x=3\)

___________________

\(4^5:4^3\)

\(=4^{5-3}\)

\(=4^2=16\)

___________________

\(8^{12}.8^3:8^{15}\)

\(=8^{15}:8^{15}\)

\(=1\)

___________________

\(7^{15}:7^{13}\)

\(=7^{15-13}\)

\(=7^2=49\)

___________________

\(17^{15}.17^{10}:17^{22}\)

\(=17^{25}:17^{22}\)

\(=17^3=4913\)

___________________

\(5^{10}.25:5^{11}\)

\(=5^{10}.5^2:5^{11}\)

\(=5^{12}:5^{11}\)

\(=5^1=5\)

___________________

\(15^{10}.225:15^{11}\)

\(=15^{10}.15^2:15^{11}\)

\(=15^{12}:15^{11}\)

\(=15^1=15\)

__________________

* aⁿ . a^m = a^n+m

 aⁿ : a^m = a^n-m

Chúc bạn học tốt

1) Ta có: \(\left(-\dfrac{2}{3}\right)^2\cdot\dfrac{-9}{8}-25\%\cdot\dfrac{-16}{5}\)

\(=\dfrac{4}{9}\cdot\dfrac{-9}{8}-\dfrac{1}{4}\cdot\dfrac{-16}{5}\)

\(=\dfrac{-1}{2}+\dfrac{4}{5}\)

\(=\dfrac{-5}{10}+\dfrac{8}{10}=\dfrac{3}{10}\)

2) Ta có: \(-1\dfrac{2}{5}\cdot75\%+\dfrac{-7}{5}\cdot25\%\)

\(=\dfrac{-7}{5}\cdot\dfrac{3}{4}+\dfrac{-7}{5}\cdot\dfrac{1}{4}\)

\(=\dfrac{-7}{5}\left(\dfrac{3}{4}+\dfrac{1}{4}\right)=-\dfrac{7}{5}\)

3) Ta có: \(-2\dfrac{3}{7}\cdot\left(-125\%\right)+\dfrac{-17}{7}\cdot25\%\)

\(=\dfrac{-17}{7}\cdot\dfrac{-5}{4}+\dfrac{-17}{7}\cdot\dfrac{1}{4}\)

\(=\dfrac{-17}{7}\cdot\left(\dfrac{-5}{4}+\dfrac{1}{4}\right)\)

\(=\dfrac{17}{7}\)

4) Ta có: \(\left(-2\right)^3\cdot\left(\dfrac{3}{4}\cdot0.25\right):\left(2\dfrac{1}{4}-1\dfrac{1}{6}\right)\)

\(=\left(-8\right)\cdot\left(\dfrac{3}{4}\cdot\dfrac{1}{4}\right):\left(\dfrac{9}{4}-\dfrac{7}{6}\right)\)

\(=\left(-8\right)\cdot\dfrac{3}{16}:\dfrac{54-28}{24}\)

\(=\dfrac{-3}{2}\cdot\dfrac{24}{26}\)

\(=\dfrac{-72}{52}=\dfrac{-18}{13}\)

dái wa      

Giúp mình đi mình đang cần gấp

x^3-1=(x-1)(x^2+x+1)

8x^3+1=(2x+1)(4x^2-2x+1)

x^3+1=(x+1)(x^2-x+1)

125-x^3=(5-x)(25+5x+x^2)

x^3+8y^3=x^3+(2y)^3

=(x+2y)(x^2-2xy+4y^2)

64y^3-125x^3

=(4y)^3-(5x)^3

=(4y-5x)(16y^2+20xy+25x^2)

\(27x^3-\dfrac{1}{8}=\left(3x\right)^3-\left(\dfrac{1}{2}\right)^3=\left(3x-\dfrac{1}{2}\right)\left(9x^2+\dfrac{3}{2}x+\dfrac{1}{4}\right)\)

\(a^6-b^3=\left(a^2\right)^3-b^3\)

\(=\left(a^2-b\right)\cdot\left(a^4+a^2b+b^2\right)\)

/ là dấu gì vậy bạn

Em nghĩ là 2/3 là phân số đok anh

\(25.5.4.125.20.8\)

\(=\left(25.4\right).\left(5.20\right).\left(125.8\right)\)

\(=100.100.1000\)

\(=10000000\)

25*(5+5)*4*20*8

=250*20+4+8

= 5000*12

=60000