Tính A
A=2.4 + 4.6 + ..... + 98.100
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\(2P=\frac{2}{2.4}+\frac{2}{4.6}+...+\frac{2}{98.100}\)
\(2P=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}+...+\frac{1}{98}-\frac{1}{100}\)
\(2P=\frac{1}{2}-\frac{1}{100}\)
=> P =\(\frac{49}{100}:2=\frac{49}{100}\cdot\frac{1}{2}=\frac{49}{200}\)
\(\frac{2.4+4.6+6.8+...+98.100}{1.2+2.3+3.4+...+49.50}=\frac{4.\left(1.2+2.3+3.4+...+49.50\right)}{1.2+2.3+3.4+...+49.50}=\frac{4}{1}=4\)
D = 2.4 + 3.5 + 4.6 + 5.7 + 6.8 + 7.9 + ...+ 97.99 + 98.100
D = (2.4 + 4.6 +...+ 98.100) + (3.5 + 5.7 + 7.9 + ..+ 97.99)
Đặt A = 2.4 + 4.6 +...+ 98.100
B = 3.5 + 5.7 + 7.9 + ..+ 97.99
Khi đó: D = A + B
Xét tổng A : A = 2.4 + 4.6 + ..+ 98.100
6A = 2.4.6 + 4.6.6 + ...+ 98.100.6
6A = 2.4.6 + 4.6.(8 - 2) +...+ 98.100.(102-96)
6A = 2.4.6 + 4.6.8 - 2.4.6 + ...+ 98.100.102 - 96.98.100
6A = 98.100.102
A = 98.100.102 : 6
A = 166600
Xét tổng B = 3.5 + 5.7 + ...+ 97.99
6B = 3.5.6 + 5.7.6 + ..+ 97.99.6
6B = 3.5.(7- 1) + 5.7.(9 - 3) + ...+ 97.99.(101 - 95)
6B = 3.5.7 - 1.3.5 + 5.7.9 - 3.5.7 + ... + 97.99.101 - 97.99.95
6B = - 1.3.5 + 97.99.101
6B = - 15 + 969903
6B = 969888
B = 969888 : 6
B = 161648
D = A + B
D = 166600 + 161648
D = 328248
1.3+2.4+3.5+4.6+.....+97.99+98.100
\(=2^2-1+3^2-1+....+99^2-1\)
\(=1^2+2^2+3^2+....+99^2-99\)
\(=\frac{99.100.196}{6}-99\)
\(=328251\)
D = 2.4 + 3.5 + 4.6 + 5.7 + 6.8 + 7.9 + ...+ 97.99 + 98.100
D = (2.4 + 4.6 +...+ 98.100) + (3.5 + 5.7 + 7.9 + ..+ 97.99)
Đặt A = 2.4 + 4.6 +...+ 98.100
B = 3.5 + 5.7 + 7.9 + ..+ 97.99
Khi đó: D = A + B
Xét tổng A : A = 2.4 + 4.6 + ..+ 98.100
6A = 2.4.6 + 4.6.6 + ...+ 98.100.6
6A = 2.4.6 + 4.6.(8 - 2) +...+ 98.100.(102-96)
6A = 2.4.6 + 4.6.8 - 2.4.6 + ...+ 98.100.102 - 96.98.100
6A = 98.100.102
A = 98.100.102 : 6
A = 166600
Xét tổng B = 3.5 + 5.7 + ...+ 97.99
6B = 3.5.6 + 5.7.6 + ..+ 97.99.6
6B = 3.5.(7- 1) + 5.7.(9 - 3) + ...+ 97.99.(101 - 95)
6B = 3.5.7 - 1.3.5 + 5.7.9 - 3.5.7 + ... + 97.99.101 - 97.99.95
6B = - 1.3.5 + 97.99.101
6B = - 15 + 969903
6B = 969888
B = 969888 : 6
B = 161648
D = A + B
D = 166600 + 161648
D = 328248
A=(1.2)(2.2)+(2.2)(3.2)+...+(50.2)(51.2)
A=1.2.4+2.3.4+...+50.51.4
A=4(1.2+2.3+...+50.51)
M= 1.2+2.3+...+50.51
3M=1.2.3+2.3.(4-1)+...+50.51.(52-49)
=1.2.3+2.3.4-1.2.3+...+50.51.52-49.50.51
= 50.51.52
=132600
=> M=44200
=> A=4M=176800
\(A=2.4+4.6+6.8+...+96.98+98.100\)
\(\Rightarrow6A=2.4.6+4.6.8-2.4.6+6.8.10-4.6.8+...+96.98.100-94.96.98+98.100.102-96.98.100\)
\(\Rightarrow6A=\left(2.4.6+4.6.8+6.8.10+...+96.98.100+98.100.102\right)-\left(2.4.6+4.6.8+...+94.96.98+96.98.100\right)\)\(\Rightarrow6A=98.100.102\)
\(\Rightarrow A=\frac{98.100.102}{6}=98.100.17=166600\)
P/s: Ko chắc
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Câu hỏi của Kanzaki Mizuki -toán lớp 6