\(\frac{x-1}{2018}+\frac{x-7}{503}=\frac{x-3}{1008}+\frac{x-9}{670}\)

\(\Leftrightarrow\frac{x-1}{2018}-1+\frac{x-7}{503}-4=\frac{x-3}{1008}-2+\frac{x-9}{670}-3\)

\(\Leftrightarrow\left(x-2019\right)\left(\frac{1}{2018}+\frac{1}{503}-\frac{1}{1008}-\frac{1}{670}\right)=0\)

\(\Rightarrow x=2019\)

#CBHT

Đặt A =1/2+1/4+1/8+...+1/1024

2A= 1+1/2+1/4+...+1/512

A= 1-1/1024

=>A<1hay ...

\(\left(\frac{4}{3}\right)^{2018}:\left(\frac{16}{9}\right)^{1008}-x=0,6^3:0,2^3\)

\(\Leftrightarrow\left[\left(\frac{4}{3}\right)^2\right]^{1009}:\left(\frac{16}{9}\right)^{1008}-x=27\)

\(\Leftrightarrow\left(\frac{16}{9}\right)^{1009}:\left(\frac{16}{9}\right)^{1008}-x=27\)

\(\Leftrightarrow\frac{16}{9}-x=27\)

\(\Leftrightarrow x=\frac{-227}{9}\)

Vậy x = \(\frac{-227}{9}\)

Bài 1:

a: Cách 1: \(\left(\frac23-\frac45\right)\times25\)

\(=\left(\frac{10}{15}-\frac{12}{25}\right)\times25\)

\(=-\frac{2}{25}\times15=-\frac{30}{15}=-\frac65\)

Cách 2: \(\left(\frac23-\frac45\right)\times25\)

\(=\frac23\times25-\frac45\times25\)

\(=\frac{50}{3}-20=\frac{50}{3}-\frac{100}{5}=\frac{50}{3}-20=\frac{50}{3}-\frac{60}{3}=-\frac{10}{3}\)

b: Sửa đề: \(\frac34\times\frac25+\frac34\times\frac27\)

Cách 1: \(\frac34\times\frac25+\frac34\times\frac27\)

\(=\frac34\times\left(\frac25+\frac27\right)\)

\(=\frac34\times\left(\frac{14}{35}+\frac{10}{35}\right)\)

\(=\frac34\times\frac{24}{35}=\frac{72}{140}=\frac{18}{35}\)

Cách 2:

\(\frac34\times\frac25+\frac34\times\frac27\)

\(=\frac{6}{20}+\frac{6}{28}\)

\(=\frac{42}{140}+\frac{30}{140}=\frac{72}{140}=\frac{18}{35}\)

Bài 2:

a: \(x:\frac25=\frac23\)

=>\(x=\frac23\times\frac25=\frac{4}{15}\)

b: \(x:\frac23=\frac49\)

=>\(x=\frac49\times\frac23=\frac{8}{27}\)

a = 2012 * 20 - 1006 * 2 * 18 - 503 * 4

= 2012 * 20 - 2012 * 18 - 2012

= 2012* 20 - 2012 * 18 - 2012 *1

= 2012* ( 20-18-1)

= 2012* 1 = 2012

             Đây nek

thank ban phuong pham nha

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