a, ( 19x + 2.5² ) : 14 = ( 13 - 8 )² - 4²

    ( 19x + 2.5² ) : 14 = ( 13 - 8 )² - 16

    ( 19x + 2.5² ) : 14 = 5² - 16

    ( 19x + 2.5² ) : 14 = 25 - 16

     ( 19x + 2.5² ) : 14 = 9

     ( 19x + 2.25 ) : 14 = 9

     ( 19x + 2.25 )        = 9 . 14

     ( 19x + 2.25 )        = 126

     ( 19x + 50 )           = 126

       19x                      = 126 - 50

       19x                      = 76

           x                      = 76 : 19

           x                      = 4

       Vậy x = 4

b, 2 . 3^x = 10 . 3¹² + 8 . 27⁴

    2 . 3^x = 10 . 27⁴ + 8 . 27⁴

    2 . 3^x = 27⁴ . ( 10+8 )

    2 . 3^x = 27⁴ . 18

    2 . 3^x = 9565938

         3^x = 9565938 : 2

         3^x = 4782969

         3^x = 3¹⁴

=> x = 14

       Vậy x = 14

Đây nha bạn!!!

Chúc bạn học tốt!!!

a, ( 19x + 2.52 ) : 14 = ( 13 - 8 )2 - 42

    ( 19x + 2.52 ) : 14 = ( 13 - 8 )2 - 16

    ( 19x + 2.52 ) : 14 = 52 - 16

    ( 19x + 2.52 ) : 14 = 25 - 16

     ( 19x + 2.52 ) : 14 = 9

     ( 19x + 2.25 ) : 14 = 9

     ( 19x + 2.25 )        = 9 . 14

     ( 19x + 2.25 )        = 126

     ( 19x + 50 )           = 126

       19x                      = 126 - 50

       19x                      = 76

           x                      = 76 : 19

           x                      = 4

       Vậy x = 4

b, 2 . 3x = 10 . 312 + 8 . 274

    2 . 3x = 10 . 274 + 8 . 274

    2 . 3x = 274 . ( 10+8 )

    2 . 3x = 274 . 18

    2 . 3x = 9565938

         3x = 9565938 : 2

         3x = 4782969

         3x = 314

=> x = 14

       Vậy x = 14

a) \(\left(19x-2.52\right):14=\left(13-8\right).2-42\)

\(\left(19x-50\right):14=10-42\)

\(\left(19x-50\right):14=-32\)

\(19x-50=-448\)

\(19x=-398\)

\(x=-\dfrac{398}{19}\)

\(a,\Rightarrow12x-91=101\\ \Rightarrow12x=192\\ \Rightarrow x=16\\ b,\Rightarrow x:23+45=133\\ \Rightarrow x:23=88\\ \Rightarrow x=\dfrac{88}{23}\\ c,\Rightarrow\left(6x-39\right):7=3\\ \Rightarrow6x-39=21\\ \Rightarrow6x=60\\ \Rightarrow x=10\\ d,\Rightarrow3x-24=\dfrac{148}{73}\\ \Rightarrow3x=\dfrac{1900}{73}\\ \Rightarrow x=\dfrac{1900}{219}\\ e,\Rightarrow\left[{}\begin{matrix}x=0\\x=10\end{matrix}\right.\\ f,\Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\\ d,\left(9-x\right)^3=64=4^3\\ \Rightarrow9-x=4\\ \Rightarrow x=5\\ h,\Rightarrow x=27\\ i,\Rightarrow6x=312\cdot12=624\cdot6\\ \Rightarrow x=624\\ j,\Rightarrow\left(19x+104\right):14=25-42=-17\\ \Rightarrow19x+104=-238\\ \Rightarrow19x=-342\\ \Rightarrow x=-18\)

Hoc hành lớt phớt chỉ trưc trực hỏi bài người ta :)))

\(a,\Rightarrow2^{x-1}=24-\left(16-3\right)-3\\ \Rightarrow2^{x-1}=24-13-3\\ \Rightarrow2^{x-1}=8=2^3\\ \Rightarrow x-1=3\Rightarrow x=4\\ b,\Rightarrow\left(19x+50\right):14=25-16=9\\ \Rightarrow19x+50=126\\ \Rightarrow x=4\)

\(...\Rightarrow\left(19x+50\right):14=5^2-4\Rightarrow\left(19x+50\right):14=21\Rightarrow\left(19x+50\right)=21.14\)

\(\Rightarrow19x+50=294\Rightarrow19x=244\Rightarrow x=\dfrac{244}{19}\)

\(\left(19x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
\(\Rightarrow\left(19x+50\right):14=5^2-4^2\)
\(\Rightarrow\left(19x+50\right):14=9\)
\(\Rightarrow19x+50=126\)
\(\Rightarrow19x=76\)
\(\Rightarrow x=4\)
Vậy x = 4
#Kễnh

a: \(x^3=27\)

=>\(x^3=3^3\)

=>x=3

b: \(\left(2x-1\right)^3=8\)

=>\(\left(2x-1\right)^3=2^3\)

=>2x-1=2

=>2x=2+1=3

=>\(x=\frac32=1,5\)

c: \(\left(x-2\right)^2=16\)

=>\(\left[\begin{array}{l}x-2=4\\ x-2=-4\end{array}\right.\Rightarrow\left[\begin{array}{l}x=4+2=6\\ x=-4+2=-2\end{array}\right.\)

d: \(\left(2x-3\right)^2=9\)

=>\(\left[\begin{array}{l}2x-3=3\\ 2x-3=-3\end{array}\right.\Longrightarrow\left[\begin{array}{l}2x=6\\ 2x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=3\\ x=0\end{array}\right.\)

e: \(2x+5=3^4:3^2\)

=>\(2x+5=3^2=9\)

=>2x=9-5=4

=>\(x=\frac42=2\)

f: \(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)

=>\(3x-16=2\cdot\frac{7^4}{7^3}=2\cdot7=14\)

=>3x=16+14=30

=>\(x=\frac{30}{3}=10\)

a: \(x^3=27\)

=>\(x^3=3^3\)

=>x=3

b: \(\left(2x-1\right)^3=8\)

=>\(\left(2x-1\right)^3=2^3\)

=>2x-1=2

=>2x=2+1=3

=>\(x=\frac32=1,5\)

c: \(\left(x-2\right)^2=16\)

=>\(\left[\begin{array}{l}x-2=4\\ x-2=-4\end{array}\right.\Rightarrow\left[\begin{array}{l}x=4+2=6\\ x=-4+2=-2\end{array}\right.\)

d: \(\left(2x-3\right)^2=9\)

=>\(\left[\begin{array}{l}2x-3=3\\ 2x-3=-3\end{array}\right.\Longrightarrow\left[\begin{array}{l}2x=6\\ 2x=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=3\\ x=0\end{array}\right.\)

e: \(2x+5=3^4:3^2\)

=>\(2x+5=3^2=9\)

=>2x=9-5=4

=>\(x=\frac42=2\)

f: \(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)

=>\(3x-16=2\cdot\frac{7^4}{7^3}=2\cdot7=14\)

=>3x=16+14=30

=>\(x=\frac{30}{3}=10\)

\(\Leftrightarrow3x-16=2\cdot7=14\)

hay x=10