Tính nhanh
\(67^2+33^2+66.67\)
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Bài 1:
a) \(3x^2-9x=3x\left(x-3\right)\)
b) \(x^2-4x+4=\left(x-2\right)^2\)
c) \(x^2+6x+9-y^2=\left(x+3\right)^2-y^2=\left(x-y+3\right)\left(x+y+3\right)\)
Bài 2:
a) \(101^2-1=\left(101-1\right)\left(101+1\right)=102.100=10200\)
b) \(67^2+66.67+33^2=67^2+2.33.67+33^2\)
\(=\left(67+33\right)^2=100^2=10000\)
Bài 3:
\(x\left(x-3\right)+2\left(x+3\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(x+2\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-3=0\\x+2=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=3\\x=-2\end{cases}}\)
Vậy \(x=-2\)hoặc \(x=3\)
B1:
a) \(3x^2-9x=3x.\left(x-3\right)\)
b) \(x^2-4x+4=\left(x-2\right)^2\)
c) \(x^2+6x+9-y^2=\left(x+3\right)^2-y^2=\left(x+3+y\right).\left(x+3-y\right)\)
B2:
a) \(101^2-1=\left(101+1\right).\left(101-1\right)=102.100=10200\)
b) \(67^2+66.67+33^2=67^2+2.33.67+33^2=\left(67+33\right)^2=100^2=10000\)
B3:
\(x\left(x-3\right)+2\left(x-3\right)=0\)
\(\left(x-3\right).\left(x+2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-3=0\\x+2=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=3\\x=-2\end{cases}}\)
= 167 x 67 + 167 x 30 + 161 x 1 + 167 x 2
= 167 x (67 +30 +1 + 2 )
=167 X 100
= 16 700
Ta có: \(-53\left(67-33\right)-67\cdot\left(33-53\right)\)
\(=-53\cdot67+53\cdot33-67\cdot33+67\cdot53\)
\(=53\cdot33-67\cdot33=33\cdot\left(53-67\right)=33\cdot\left(-14\right)=-462\)
\(=\left(-67\right).\left(-33\right)-67.77+\left(-67\right).33-77.33\)
\(=\left[\left(-67\right).\left(-33\right)+\left(-67\right).33\right]-66.77-77.33\)
\(=-77\left(66+33\right)=-77.99=-7623\)
(67/111+2/33-15/117) . (1/3-1/4-1/12)
= (67/111+2/33-15/117) . 0
= 2836/5291 . 0
= 0
\(\left(100+67\right).67+\left(200-33\right).33\)
\(=167.67+167.33\)
\(=167.\left(67+33\right)=167.100=16700\)
ĐỀ BẠN TỰ GHI À NHA
=167x67+167x33
=167x(67+33)
=167x100
=16700
Ta có: \(\left(100+67\right)\times67+\left(200-33\right)\times33\)
\(=167\times67+167\times33\)
\(=167\times\left(67+33\right)=167\times100=16700\)
ta có: 67^2 +33 ^2 +66.67
=67^2+2.33.67+33^2
=(67+33)^2
=100^2
=10000