Giúp mk nha mk cần gấp

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a: Xét ΔAMB và ΔAMC có
AM chung
MB=MC
AB=AC
Do đó: ΔAMB=ΔAMC
Bài 4:
a: \(A=2x^4+3x^3-5x^2+2x+5\)
\(B=x^4+3x^3-6x^2+2x+1\)
b: \(A+B=3x^4+6x^3-11x^2+4x+6\)
\(A-B=x^4+x^2+4\)
c: \(A-B=x^4+x^2+4>=4>0\forall x\)
went
are practicing
does-do-goes
to go
ask
watching
doing
to do
will become
was
1.went
2.are practicing
3.does-do-goes
4.to go
5.ask
6.watching
7.doing
8.to do
9.will become
10.was
Bài 4:
Gọi d=ƯCLN(2n+3;3n+4)
=>2n+3⋮d và 3n+4⋮d
=>6n+9⋮d và 6n+8⋮d
=>6n+9-6n-8⋮d
=>1⋮d
=>d=1
=>ƯCLN(2n+3;3n+4)=1
=>\(A=\frac{2n+3}{3n+4}\) là phân số tối giản
Bài 2:
a: \(x+\frac23=-\frac34\)
=>\(x=-\frac34-\frac23=-\frac{9}{12}-\frac{8}{12}=-\frac{17}{12}\)
b: \(\frac{x-3}{5}=\frac{20}{x-3}\) (ĐKXĐ: x<>3)
=>\(\left(x-3\right)\cdot\left(x-3\right)=5\cdot20=100\)
=>\(\left(x-3\right)^2=100\)
=>\(\left[\begin{array}{l}x-3=10\\ x-3=-10\end{array}\right.\Rightarrow\left[\begin{array}{l}x=10+3=13\left(nhận\right)\\ x=-10+3=-7\left(nhận\right)\end{array}\right.\)
c: \(\frac{x+7}{5}=\frac{x+2}{6}\)
=>6(x+7)=5(x+2)
=>6x+42=5x+10
=>6x-5x=10-42
=>x=-32
1. B
2. C
3. A
4. D
5. D
6. B
7. D
8. C
9. B
3. Did someone help you.....do..... this exercise?
4. That was one of the .....most expensive... things in my house.
6. Mai is looking at.....herself....in the mirror.
7. Students ....mustn't.... talk too much in class.
8. Hoa was late ...because....she stayed up late last night.
9. Romeo killed....himself... and Juliet killed....herself....as well.