\(\left(\frac{1}{25x27}+\frac{1}{27x29}+\frac{1}{29x31}+....+\frac{1}{73x75}\right)x\frac{3}{10}=x\)

\(< =>\frac{1}{2}x\left(\frac{2}{25x27}+\frac{2}{27x29}+\frac{2}{29x31}+....+\frac{2}{73x75}\right)x\frac{3}{10}=x\)

\(< =>\frac{1}{2}x\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+....+\frac{1}{73}-\frac{1}{75}\right)x\frac{3}{10}=x\)

\(< =>\frac{1}{2}x\left(\frac{1}{25}-\frac{1}{75}\right)x\frac{3}{10}=x< =>\frac{1}{2}x\frac{2}{25}x\frac{3}{10}=x< =>x=\frac{3}{250}\)

     25x47+25x126+25x27

=   25 x ( 47 + 126 + 27 )

=   25 x 200

=   5000

Tck mk nhé

25x47+25x126+25x27

=25x(47+126+27)

=25x199

=4975

k &kb mk nah

ai làm đúng mình sẽ pick cho người đấy

bằng -0,1848 nha bạn

=25 x 3 x 89 + 25 x  27 + 2 x 3 x 25

=25 x 267+25 x 27 +6 x 25

=25 x (267+27+6)

=25 x 300

=7500

mình nhanh nhất k mình nhé

Lời giải:

Gọi tổng trên là $A$
$A=2\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{25.27}\right)$

$=2\left(\frac{3-1}{1.3}+\frac{5-3}{3.5}+\frac{7-5}{5.7}+...+\frac{27-25}{25.27}\right)$

$=2\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+....+\frac{1}{25}-\frac{1}{27}\right)$

$=2\left(1-\frac{1}{27})=\frac{52}{27}$

a)75x89+25x27+2x75                            b)77x27+9x24+15x27

=25x3x89+25x27+2x3x25                      =77x27+9x3x8+15x27

=25x(267+27+6)                                    =77x27+27x8+15x27

=25x300                                                =27x(77+8+15)

=7500                                                   =27x100=2700

Mình trả lời đầu tiên mà

a, 75 x 89 + 25 x 27 + 2 x 75

= 75 ( 89 + 2) + 25 x 27 

= 3 x 25 x 91 + 25 x 27

= 25 x 273 + 25 x 27

= 25 x (273 + 27)

= 25 x 300

= 7500

mn cs bt câu này ko . 

=?

      \(\frac{1}{25.27}+\frac{1}{27.29}+.......+\frac{1}{77.79}\)

\(=\frac{1}{2}.\left(\frac{2}{25.27}+\frac{2}{27.29}+....+\frac{2}{77.79}\right)\)

\(=\frac{1}{2}.\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+......+\frac{1}{77}+\frac{1}{79}\right)\)

\(=\frac{1}{2}.\left(\frac{1}{25}-\frac{1}{79}\right)\)

\(=\frac{1}{2}.\frac{54}{1975}\)

\(=\frac{27}{1975}\)

\(A=\frac{1}{25.27}+\frac{1}{27.29}+...........+\frac{1}{75.79}\)

\(\Leftrightarrow2A=\frac{2}{25.27}+\frac{2}{27.29}+........+\frac{2}{75.79}\)

\(\Leftrightarrow2A=\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+.........+\frac{1}{75}-\frac{1}{79}\)

\(\Leftrightarrow2A=\frac{1}{25}-\frac{1}{79}\)

Tự tính tiếp! chúc b hk tốt

\(B=\frac{1}{25.27}+\frac{1}{27.29}+\frac{1}{29.31}+...+\frac{1}{73.75}\)

\(B=\frac{1}{2}\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+...+\frac{1}{73}-\frac{1}{75}\right)\)

\(B=\frac{1}{2}\left(\frac{1}{25}-\frac{1}{75}\right)\)

\(B=\frac{1}{2}\cdot\frac{2}{75}\)

\(B=\frac{1}{75}\)

\(B=\frac{1}{25.27}+\frac{1}{27.29}+\frac{1}{29.31}+....+\frac{1}{73.75}\)

\(B=\frac{1}{2}.\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+...+\frac{1}{73}-\frac{1}{75}\right)\)

\(B=\frac{1}{2}\cdot\left(\frac{1}{25}-\frac{1}{75}\right)\)

\(B=\frac{1}{2}\cdot\frac{2}{75}=\frac{1}{75}\)