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Trả lời
\(A=\frac{11}{12+13}+\frac{12}{13+14}+\frac{1}{14+15}\)
Hay
\(A=\frac{11}{12+13}+\frac{12}{13+14}+\frac{13}{14+15}\)
mong xem lại hộ cái
a: \(\frac79-\frac{4}{15}+\frac61\)
\(=\frac{35}{45}-\frac{12}{45}+6\)
\(=6+\frac{23}{45}=\frac{270}{45}+\frac{23}{45}=\frac{293}{45}\)
b: \(\frac{44}{21}-\left(\frac34+\frac{2}{21}\right)\)
\(=\frac{44}{21}-\frac{2}{21}-\frac34\)
\(=2-\frac34=\frac54\)
c: \(\frac{17}{12}+\frac{13}{7}-\frac67+\frac{7}{12}\)
\(=\frac{17}{12}+\frac{7}{12}+\left(\frac{13}{7}-\frac67\right)\)
=2+1
=3
\(\frac{379-x}{12}=21,7\) Đ/S : 118,6
7/12-2/7+1/12=7/12+1/12-2/7=8/12-2/7=2/3+2/7=14/21+6/21=20/21
12/17-5/17-4/17=3/17
Bài 1 :
a) \(\frac{6}{10}\)
Bài 2 :
c) \(\frac{8}{18}\)
Bài 1:
Kết quả:\(\frac{6}{10}\)
Bài 2:
Kết quả:\(\frac{8}{18}\)
K CHO MK NHA:
KÍ TÊN
\(!@#HUYDEPZAI\%\&\)
\(=66\frac{5}{12}+37+25\frac{1}{2}\)
\(\frac{797}{12}+\frac{444}{12}+\frac{51}{2}=\frac{1241}{12}+\frac{306}{12}=\frac{1547}{12}=128\frac{11}{12}\)
**** **** ****
\(66\frac{5}{12}+36\frac{12}{12}+25\frac{12}{24}=66\frac{5}{12}+36+1+25\frac{6}{12}=\left(66+37+25\right)+\left(\frac{5}{12}+\frac{6}{12}\right)=128+\frac{11}{12}=128\frac{11}{12}\)
a) \(\frac{5}{1.4}+\frac{5}{4.7}+\frac{5}{7.10}+.....+\frac{5}{27.30}\)
\(=\frac{5}{3}\left(\frac{1}{1.4}+\frac{1}{4.7}+........+\frac{1}{27.30}\right)\)
\(=\frac{5}{3}\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+.....+\frac{1}{27}-\frac{1}{30}\right)\)
\(=\frac{5}{3}\left(1-\frac{1}{30}\right)\)
\(=\frac{5}{3}.\frac{29}{30}=\frac{29}{36}\)
Đặt \(A=\frac{12}{3\cdot5}+\frac{12}{5\cdot7}+\frac{12}{7\cdot9}+....+\frac{12}{97\cdot99}\)
\(2A=\frac{12}{3}-\frac{12}{5}+\frac{12}{5}-\frac{12}{7}+...+\frac{12}{97}-\frac{12}{99}\)
\(2A=\frac{12}{3}-\frac{12}{99}\)
\(A=\frac{128}{33}\cdot\frac{1}{2}=\frac{64}{33}\)
3.167
heeeee
3,167
(18,817+19,187):12=38,004:12=3,167
=38,004:12=3,167