a/ Với \(x=2016\Rightarrow2017=x+1\)

\(A=x^6-\left(x+1\right)x^5+\left(x+1\right)x^4-\left(x+1\right)x^3+\left(x+1\right)x^2-\left(x+1\right)x+2025\)

\(A=x^6-x^6-x^5+x^5+x^4-x^4-x^3+x^3+x^2-x^2-x+2025\)

\(A=2025-x=9\)

b/ Với \(x=-1\Rightarrow\left\{{}\begin{matrix}x^{2k}=1\\x^{2k+1}=-1\end{matrix}\right.\) ta có:

\(Q=2017-2016+2015-2014+...+3-2+1\)

\(Q=1+1+1+...+1+1\) (có \(\frac{2016}{2}+1=1009\) số 1)

\(Q=1009\)

a: \(=\left(1+\dfrac{4}{23}-\dfrac{4}{23}\right)+\left(\dfrac{5}{21}+\dfrac{16}{21}\right)+\dfrac{1}{2}\)

\(=1+1+\dfrac{1}{2}=2+\dfrac{1}{2}=\dfrac{5}{2}\)

b: \(=\left(\dfrac{1}{25}+\dfrac{5}{25}+\dfrac{25}{25}\right):\left(\dfrac{1}{25}-\dfrac{5}{25}-\dfrac{25}{25}\right)\)

\(=\dfrac{31}{25}:\dfrac{-29}{25}=\dfrac{-31}{29}\)

c: \(=\dfrac{\dfrac{1}{9}-\dfrac{1}{7}-\dfrac{1}{11}}{\dfrac{4}{9}-\dfrac{4}{7}-\dfrac{4}{11}}+\dfrac{\dfrac{3}{5}-\dfrac{3}{25}-\dfrac{3}{125}-\dfrac{3}{625}}{\dfrac{4}{5}-\dfrac{4}{25}-\dfrac{4}{125}-\dfrac{4}{625}}\)

=1/4+3/4

=1

sao nhìn nó lạ lắm ko giống x đâu bn nên bn ghi lại đi để mik nhìn rõ hơn nha :))

\(x\in\left\lbrace45,46\right\rbrace\) nhé

Ta có: \(\left(3x-2\right)^{2024}\ge0\forall x\)

=>\(4\left(3x-2\right)^{2024}\ge0\forall x\)

mà \(\left(y+1\right)^{10}\ge0\forall y\)

nên \(4\left(3x-2\right)^{2024}+\left(y+1\right)^{10}\ge0\forall x,y\)

=>\(4\left(3x-2\right)^{2024}+\left(y+1\right)^{10}+2025\ge2025\forall x,y\)

Dấu '=' xảy ra khi \(\begin{cases}3x-2=0\\ y+1=0\end{cases}\Rightarrow\begin{cases}x=\frac23\\ y=-1\end{cases}\)

không

Ta có: \(\left(3x-2\right)^{2024}\ge0\forall x\)

=>\(4\left(3x-2\right)^{2024}\ge0\forall x\)

mà \(\left(y+1\right)^{10}\ge0\forall y\)

nên \(4\left(3x-2\right)^{2024}+\left(y+1\right)^{10}\ge0\forall x,y\)

=>\(4\left(3x-2\right)^{2024}+\left(y+1\right)^{10}+2025\ge2025\forall x,y\)

Dấu '=' xảy ra khi \(\begin{cases}3x-2=0\\ y+1=0\end{cases}\Rightarrow\begin{cases}x=\frac23\\ y=-1\end{cases}\)

5) \(\left(-2\right)^2+\sqrt{36}-\sqrt{9}+\sqrt{25}\)

=\(4+6-3+5\)

=\(12\)

2) \(\dfrac{11}{25}.\left(-24,8\right)-\dfrac{11}{25}.75,2\)

=\(\dfrac{11}{25}.\left(-24,8-75,2\right)\)

=\(\dfrac{11}{25}.\left(-100\right)\)

=\(-44\)

bằ ?

Nhiều lắm ko bt