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a) \(\left|\frac{-15}{6}\right|-\left|\frac{3}{18}\right|.\sqrt{81}+\sqrt{\frac{9}{64}}\)
\(=\frac{15}{6}-\frac{1}{6}.9+\frac{3}{8}\)
\(=\frac{15}{6}-\frac{9}{6}+\frac{3}{8}\)
\(=1+\frac{3}{8}\)
\(=\frac{11}{8}\)
b) \(\frac{6^{15}.9^{10}}{3^{34}.2^{13}}=\frac{\left(2.3\right)^{15}.\left(3^2\right)^{10}}{3^{34}.2^{13}}=\frac{2^{15}.3^{15}.3^{20}}{3^{34}.2^{13}}=2^2.3=12\)
a/ \(\left|\frac{-15}{6}\right|-\left|\frac{3}{18}\right|.\sqrt{81}+\sqrt{\frac{9}{64}}\)
= \(\frac{15}{6}-\frac{3}{18}.9+\frac{8}{8}\)
= \(\frac{15}{6}-\frac{3}{2}+\frac{3}{8}\)
= \(\frac{60-36+9}{24}=\frac{33}{24}=\frac{11}{8}\)
b/ \(\frac{6^{15}.9^{10}}{3^{34}.2^{13}}=\frac{\left(2.3\right)^{15}.\left(3^2\right)^{10}}{3^{34}.2^{13}}\) \(=\frac{2^{15}.3^{15}.3^{20}}{3^{34}.2^{13}}=\frac{2^2.3^{35}}{3^{34}}=\frac{4.3}{1}=12\)
\(\frac{2}{3}\sqrt{81}-\left(\frac{-3}{4}\right):\sqrt{\frac{9}{64}}-\left(\frac{\sqrt{5}}{2011}\right)^0\)
\(=\frac{2}{3}\cdot9+\frac{3}{4}\cdot\frac{8}{3}-1\)
\(=6+2-1\)
\(=7\)
\(\frac{2}{3}\sqrt{81}-\left(-\frac{3}{4}\right):\sqrt{\frac{9}{64}}-\left(\frac{\sqrt{5}}{2011}\right)^0=\frac{2}{3}.9-\left(-2\right)-1=6+2-1=7\)
\(a,\frac{-5}{9}.\left(\frac{3}{10}-\frac{2}{5}\right)\)
\(=\frac{-5}{9}.\frac{-1}{10}\)
\(=\frac{1}{18}\)
\(b,2^8:2^5+3^3.2-12\)
\(=2^3+9.2-12\)
\(=8+18-12\)
\(=26-12\)
\(=14\)
Câu c,d em chưa học nên không biết làm ạ, mong mọi người thông cảm!!!
Sửa lại câu b
\(=2^3+27.2-12\)
\(=8+54-12\)
\(=62-12\)
\(=50\)
1. a) 3+2=5
b) 0,5-0,1=0,4
c) 4/5-1/9=31/45
d) 2-0,6=1,4
2. a) 8-4+3=7
b) 11+5-3=13
c) 3/2-4/6-7-37/6
d) 4+5-6=3
a) \(\frac{15^{15}.5^{10}}{9^7.25^{13}}=\frac{3^{15}.5^{15}.5^{10}}{3^{14}.5^{26}}=\frac{3.5^{25}}{5^{26}}=\frac{3}{5}\)
b) \(\sqrt{\frac{4}{81}}:\sqrt{\frac{25}{81}}-1\frac{2}{5}\)
\(=\sqrt{\frac{2^2}{9^2}}:\sqrt{\frac{5^2}{9^2}}-\frac{7}{5}\)
\(=\frac{2}{9}:\frac{5}{9}-\frac{7}{5}\)
\(=\frac{2}{9}.\frac{9}{5}-\frac{7}{5}\)
\(=\frac{2}{5}-\frac{7}{5}\)
\(=\frac{-5}{5}=-1\)
c) \(\left(3^2\right)^2-625+64\)
\(=3^4-625+64\)
\(=81-625+64\)
\(=-480\)
d) \(\frac{\sqrt{3^2}-\sqrt{39^2}}{\sqrt{7^2}-\sqrt{91^2}}\)
\(=\frac{3-39}{7-91}\)
\(=\frac{-36}{-84}\)
\(=\frac{3}{7}\)
\(\sqrt{\frac{1}{9}+\frac{1}{16}}\)
\(=\frac{1}{3}+\frac{1}{4}\)
\(=\frac{7}{12}\)


toán tự giải đi nhá đừng để mng phải giải cho toán
Ta có: \(A=\frac{15}{6}-\frac{3}{18}\cdot\sqrt{81}+\sqrt{\frac{9}{64}}\)
\(=\frac52-\frac16\cdot9+\frac38\)
\(=\frac52-\frac32+\frac38=1+\frac38=\frac{11}{8}\)