9999/10000 + 9999/10000

= 19998/10000

\(\frac{19998}{10000}\)

 (  3434/3535 + 3434/6363 + 3434/9999 ) × 55

= (  34/35 + 34/63 + 34/99 ) × 55

= 34 × ( 1/35 + 1/63 + 1/99 ) × 55

=  34 × 3/55 × 55

= 102/55 × 55

= 102

Mình ko chắc lắm đâu nhá

Mình giải theo kiểu lớp 6 nhá !

=\(33.\left(\frac{34}{15}+\frac{34}{35}+\frac{34}{63}+\frac{34}{99}\right)\)

=\(33.\left[34.\left(\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}\right)\right]\)

=\(33.\left[34.\left(\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}\right)\right]\)

=\(33.\left[34.\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right).\frac{1}{2}\right]\)

=\(33.\left[34\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right).\frac{1}{2}\right]\)

=\(33.\left[34.\left(\frac{1}{3}-\frac{1}{11}\right).\frac{1}{2}\right]\)

=\(33.\left(34.\frac{8}{33}.\frac{1}{2}\right)\)

=\(33.\frac{136}{33}\)

=\(\frac{33.136}{33}\)(*)

=\(136\)

(Bạn có thể bỏ bước có dấu *)

\(\frac{3}{4}+\frac{2}{3}=\frac{9}{12}+\frac{8}{12}=\frac{17}{12}\)

\(\frac{9}{2}-4=\frac{9}{2}-\frac{8}{2}=\frac{1}{2}\)

\(\frac{4}{5}\times\frac{3}{2}=\frac{4\times3}{5\times2}=\frac{12}{10}=\frac{6}{5}\)

\(\frac{5}{6}:\frac{6}{5}=\frac{5}{6}\times\frac{5}{6}=\frac{25}{36}\)

1) \(\frac{4}{5}.\frac{8}{3}.\frac{x}{7}=\frac{96}{105}\)

\(\frac{32.x}{105}=\frac{96}{105}\)

\(32x=96\)

\(x=3\)

Bài 1: Tìm \(x\)

\(\frac45\times\frac83\times\) \(\frac{x}{7}\) = \(\frac{96}{105}\)

\(\frac{32}{15}\) x \(\frac{x}{7}\) = \(\frac{32}{35}\)

\(\frac{x}{7}\) = \(\frac{32}{35}\) : \(\frac{32}{15}\)

\(\frac{x}{7}\) = \(\frac{32}{35}\) x \(\frac{15}{32}\)

\(\frac{x}{7}\) = \(\frac37\)

\(x=\frac37\times7\)

\(x=3\)

b; \(\frac74\times\frac{3}{x}\times\) \(\frac{11}{5}\) = \(\frac{231}{200}\)

\(\frac74\) x \(\frac{3}{x}\) = \(\frac{231}{200}\) : \(\frac{11}{5}\)

\(\frac74\times\frac{3}{x}\) = \(\frac{231}{200}\) x \(\frac{5}{11}\)

\(\frac74\) x \(\frac{3}{x}\) = \(\frac{21}{40}\)

\(\frac{3}{x}\) = \(\frac{21}{40}\) : \(\frac74\)

\(\frac{3}{x}\) = \(\frac{21}{40}\) x \(\frac47\)

\(\frac{3}{x}\) = \(\frac{3}{10}\)

\(x=3:\frac{3}{10}\)

\(x=3\times\frac{3}{10}\)

\(x=10\)

số số hạng của dãy số trên là:

(92 - 4) : 4 + 1 = 23 (số hạng)

tổng của dãy số trên là:

(92 + 4) x 23 : 2 = 1104

\(\frac{12}{20}\)= \(\frac{6}{10}\)= \(\frac{3}{5}\)

\(\frac{3}{4}\)= \(\frac{9}{12}\)= \(\frac{12}{16}\)= \(\frac{15}{20}\)

\(\frac{75}{45}\)= \(\frac{15}{9}\)= \(\frac{5}{3}\)

\(\frac{3}{4}\)= \(\frac{18}{24}\)= \(\frac{12}{16}\)

12/20 = 6/10 = 3/5

3/4 = 9/12 = 12/16 = 15/20

75/45 = 15/9 = 5/3

3/4 = 18/24 = 12/16

Tk mk nha

a ) -33/56

b )-17/63

c ) 18/5

a ) - 33/56

b ) - 17/63

c ) 18/5

\(a.\frac{3}{7}.\frac{5}{6}+\frac{5}{6}.\frac{4}{7}=\left(\frac{3}{7}+\frac{4}{7}\right).\frac{5}{6}=1.\frac{5}{6}=\frac{5}{6}\)

\(b.\frac{1}{6}:\frac{4}{5}+\frac{1}{8}:\frac{4}{5}=\left(\frac{1}{6}+\frac{1}{8}\right):\frac{4}{5}=\left(\frac{4}{24}+\frac{3}{24}\right):\frac{4}{5}=\frac{7}{24}:\frac{4}{5}=\frac{7.5}{24.4}\)\(=\frac{35}{96}\)

\(c.\frac{1}{6}:\frac{4}{5}-\frac{1}{8}:\frac{4}{5}=\left(\frac{1}{6}-\frac{1}{8}\right):\frac{4}{5}=\left(\frac{4}{24}-\frac{3}{24}\right):\frac{4}{5}\)\(=\frac{1}{24}:\frac{4}{5}=\frac{1.5}{24.4}=\frac{5}{96}\)

a) \(\frac{3}{7}\cdot\frac{5}{6}+\frac{5}{6}\cdot\frac{4}{7}\)

\(=\left(\frac{3}{7}+\frac{4}{7}\right)\cdot\frac{5}{6}\)

\(=1\cdot\frac{5}{6}\)

\(=\frac{5}{6}\)

b) \(\frac{1}{6}:\frac{4}{5}+\frac{1}{8}:\frac{4}{5}\)

\(=\left(\frac{1}{6}+\frac{1}{8}\right):\frac{4}{5}\)

\(=\frac{7}{24}:\frac{4}{5}\)

\(=\frac{35}{96}\)

c) \(\frac{1}{6}:\frac{4}{5}-\frac{1}{8}:\frac{4}{5}\)

\(=\left(\frac{1}{6}-\frac{1}{8}\right):\frac{4}{5}\)

\(=\frac{1}{24}:\frac{4}{5}\)

\(=\frac{5}{96}\)

\(\frac{5}{8}:x=\frac{3}{4}\)

\(x=\frac{5}{8}:\frac{3}{4}\)

\(x=\frac{5}{6}\)

\(\frac{2}{4}+\frac{3}{4}:\frac{1}{2}\)

\(=\frac{2}{4}+\frac{6}{4}\)

\(\frac{8}{4}=2\)

Hok tốt