đáp án: c

;

C \(\frac{4}{1}\)nhé bn 

Đáp án C; 4/1

\(\left(x-\frac{2}{3}\right)\times3=\frac{3}{4}\)

\(x-\frac{2}{3}=\frac{3}{4}\div3\)

\(x-\frac{2}{3}=\frac{1}{4}\)

\(x=\frac{1}{4}+\frac{2}{3}\)

\(x=\frac{11}{12}\)

Chưa làm xong bài tập hả Thanh

\(\left(x-\frac{2}{3}\right)\cdot3=\frac{3}{4}\)

\(x-\frac{2}{3}\)         \(=\frac{3}{4}:3\)

\(x-\frac{2}{3}\)          \(=\frac{1}{4}\)

                          \(x=\frac{1}{4}+\frac{2}{3}\)

                          \(x=\frac{11}{12}\)

\(1\frac{3}{5}x2\frac{4}{3}+\frac{2}{5}=\frac{8}{5}x\frac{10}{3}+\frac{2}{5}=\frac{16}{3}+\frac{2}{5}=\frac{86}{15}\)

<br class="Apple-interchange-newline"><div></div>2³+3²+1¹+2¹+40² 

\(=8+9+1+2+1600\)

\(=\left(8+2\right)+\left(9+1\right)+1600\)

\(=10+10+1600\)

\(=20+1600\)

\(=1620\)

\(2^3+3^2+1^1+2^1+40^2\)

\(=8+9+1+2+1600\)

\(=1620\)

\(\frac{2}{3}+\frac{9}{6}=\frac{4}{6}+\frac{9}{6}=\frac{4+9}{6}=\frac{13}{6}\)

\(\frac{4}{5}+\frac{25}{15}=\frac{12}{15}+\frac{25}{15}=\frac{12+25}{15}=\frac{37}{15}\)

\(\frac{20}{10}+\frac{8}{2}=2+4=6\)

\(\frac{2}{3}+\frac{9}{6}=\frac{2}{3}+\frac{3}{2}=\frac{4+9}{6}=\frac{15}{6}=\frac{5}{2}\)

\(\frac{4}{5}+\frac{25}{16}=\frac{64+125}{80}=\frac{189}{80}\)

a=1+2+3+4+5+6

a=6+4+5+6

a=10+11

a=21

t tôi tôi t lại nha bn

\(A=21\)

\(2^2+3^2+4^2+5^2\)

\(=4+9+16+25\)

\(=54\)

~~~~!!!

2^3 + 3^2 + 4^2 + 5^2

= 8 + 9 + 16 + 25

= 54

3*3=9

2*2=4

7+10=17

3x3=9

2x2=4

7=10=17

k mik nha