minh ko biet nua moi lop 4 thoi

\(250\times12-\left(242+302\times2,5\right)\)

\(=3000-997\)

\(=2003\)

ab x 101 = ab x ( 100 + 1 ) 

= ab x 100 + ab x 1

= ab00 + ab

= abab

b ) abc x 7 x 11 x 13 = abc x 1001

abc x ( 1000 + 1 )

= abc x 1000 + ab x 1

= abc000 + abc = abcabc

ab x 101 = ab x ( 100 + 1 ) 

= ab x 100 + ab x 1

= ab00 + ab

= abab

b ) abc x 7 x 11 x 13 = abc x 1001

abc x ( 1000 + 1 )

= abc x 1000 + ab x 1

= abc000 + abc = abcabc

a) X = 15

b) X = 4

c ) X= 23

d) X= 11

( Chỉ là ý kiến riêng thôi nhé, nhận gạch đá )

a) \(\frac{6+x}{33}=\frac{7}{11}\)

=> (6 + x). 11 = 33.7

=> 66 + 11x = 231

=> 11x = 231 - 66

=> 11x = 165

=> x = 165 : 11

=> x = 15

b) 15/26 + x/13 = 46/52

=> x/13 = 23/26 - 15/26

=> x/13 = 4/13

=> x = 4

c) 121/27 x 54/11 < x < 100/21 : 25/126

=> 22 < x < 24

=> x = 23 (vì x là số tự nhiên)

d) 1 < 11/x < 12

=> 11/x \(\in\){2; 3; 4 ; ...; 11}

=> x \(\in\) {11/2; 11/3; ...; 1}

Vì x là số tự nhiên => x = 1

1, a) Ta thấy : 2017>2010 ; 2917>2018

        Suy ra : 2017x2917 > 2010x2018

        hay A > B

     b) không so sánh được

2,

a) \(\frac{3}{5}+\frac{6}{11}+\frac{7}{13}+\frac{5}{11}+\frac{2}{5}+\frac{19}{13}=\left(\frac{3}{5}+\frac{2}{5}\right)+\left(\frac{6}{11}+\frac{5}{11}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)=1+1+2=4\)

b) \(\frac{6}{5}\times\frac{3}{8}+\frac{5}{8}\times\frac{6}{5}-\frac{4}{5}=\frac{6}{5}\times\left(\frac{3}{8}+\frac{5}{8}\right)-\frac{4}{5}=\frac{6}{5}-\frac{4}{5}=\frac{2}{5}\)

c) \(\frac{4\times5\times6\times7\times8}{8\times10\times12\times14\times16}=\frac{1}{2\times2\times2\times2\times2}=\frac{1}{32}\)

a, \(\frac{3}{5}+\frac{6}{11}+\frac{7}{13}+\frac{6}{11}+\frac{2}{5}+\frac{19}{13}\)

\(=\left(\frac{3}{5}+\frac{2}{5}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)+\left(\frac{6}{11}+\frac{6}{11}\right)\)

\(=1+2+\frac{12}{11}\)

\(=3+\frac{12}{11}\)

\(=\frac{45}{11}\)

toán lớp 5 khó thế bạn

5/13 x 11/19 + 11/19 x 21/13

=11/19 x ( 5/13 + 21/13 )

=11/19 x 26/13

=11/19 x 2

=22/19