\(a,b\ge0\) , phân tích các biểu thức sau thành nhân tử.

a)  

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7 tháng 10 2021

a) \(3a-2\sqrt{ab}-b=3a-3\sqrt{ab}+\sqrt{ab}-b\)

\(=3\sqrt{a}\left(\sqrt{a}-\sqrt{b}\right)+\sqrt{b}\left(\sqrt{a}-\sqrt{b}\right)=\left(3\sqrt{a}+\sqrt{b}\right)\left(\sqrt{a}-\sqrt{b}\right)\)

b) \(5a+3\sqrt{ab}-8b=5a-5\sqrt{ab}+8\sqrt{ab}-8b\)

\(=5\sqrt{a}\left(\sqrt{a}-\sqrt{b}\right)+8\sqrt{b}\left(\sqrt{a}-\sqrt{b}\right)\)

\(=\left(5\sqrt{a}+8\sqrt{b}\right)\left(\sqrt{a}-\sqrt{b}\right)\)

7 tháng 10 2021

a) (\(\sqrt{a}-\sqrt{b}\))(3\(\sqrt{a}+b\))

b) \(\left(\sqrt{a}-\sqrt{b}\right)\left(5\sqrt{a}+8\sqrt{b}\right)\)

 

7 tháng 10 2021

a/\(\left(\sqrt{a}-\sqrt{b}\right)\left(3\sqrt{a}+\sqrt{b}\right)\)

b/ \(\left(\sqrt{a}-\sqrt{b}\right)\left(5\sqrt{a}+8\sqrt{b}\right)\)

7 tháng 10 2021

a) (\(\sqrt{a}-\sqrt{b}\))(\(3\sqrt{a}+\sqrt{b}\))
b) (\(\sqrt{a}-\sqrt{b}\))(5\(\sqrt{a}+8\sqrt{b}\))

7 tháng 10 2021

a)\(\left(\sqrt{a}-\sqrt{b}\right)\left(\sqrt{b}+3\sqrt{a}\right)\)

b)\(\left(\sqrt{a}-\sqrt{b}\right)\left(5\sqrt{a}+8\sqrt{b}\right)\)

7 tháng 10 2021

a) \(\left(3\sqrt{a}+b\right)\left(\sqrt{a}-\sqrt{b}\right)\)
b) \(\left(5\sqrt{a}+8\sqrt{b}\right)\left(\sqrt{a}-\sqrt{b}\right)\)

7 tháng 10 2021

a) \(\left(\sqrt{a}-\sqrt{b}\right)\left(3\sqrt{a}+\sqrt{b}\right)\)

b) \(\left(5\sqrt{a}+8\sqrt{b}\right)\left(\sqrt{a}-\sqrt{b}\right)\)

8 tháng 10 2021

a) 3a - 2\(\sqrt{ab}\) - b= 2a + a - 2\(\sqrt{ab}\) - b = 2\(\sqrt{a}\)\(\sqrt{a}\) - \(\sqrt{b}\) ) +(a - b )

  =2\(\sqrt{a}\)\(\sqrt{a}\) - \(\sqrt{b}\) )+(\(\sqrt{a}\) +\(\sqrt{b}\))(\(\sqrt{a}\) -\(\sqrt{b}\))= (\(\sqrt{a}\) -\(\sqrt{b}\))( 2\(\sqrt{a}\) +\(\sqrt{a}\) +\(\sqrt{b}\))=(\(\sqrt{a}\) -\(\sqrt{b}\))(3\(\sqrt{a}\) +\(\sqrt{b}\) )

b) 5a +3\(\sqrt{ab}\) - 8b= 5a + 8\(\sqrt{ab}\) - 5\(\sqrt{ab}\) - 8b= 5\(\sqrt{a}\)(\(\sqrt{a}\) - \(\sqrt{b}\)) +8\(\sqrt{b}\)\(\sqrt{a}\) - \(\sqrt{b}\))

     =(\(\sqrt{a}\) - \(\sqrt{b}\))(5\(\sqrt[]{a}\) +8\(\sqrt{b}\))

 

8 tháng 10 2021

a. \(3a-2\sqrt{ab}-b=3a-3\sqrt{ab}+\sqrt{ab}-b=3\sqrt{a}\left(\sqrt{a}-\sqrt{b}\right)+\sqrt{b}\left(\sqrt{a}-\sqrt{b}\right)=\left(3\sqrt{a}+\sqrt{b}\right)\left(\sqrt{a}-\sqrt{b}\right)\)

b.\(5a+3\sqrt{ab}-8b=5a-5\sqrt{ab}+8\sqrt{ab}-8b=5\sqrt{a}\left(\sqrt{a}-\sqrt{b}\right)+8\sqrt{b}\left(\sqrt{a}-\sqrt{b}\right)=\left(5\sqrt{a}+8\sqrt{b}\right)\left(\sqrt{a}-\sqrt{b}\right)\)

8 tháng 10 2021

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9 tháng 10 2021

bài 3 e gửi thiếu nên e gửi vào đây luôn

 
10 tháng 10 2021

a) \(3a-2\sqrt{ab}-b=\left(\sqrt{a}-\sqrt{b}\right)\left(3\sqrt{a}+\sqrt{b}\right)\)

b) \(5a+3\sqrt{ab}-8b=\left(\sqrt{a}-\sqrt{b}\right)\left(5\sqrt{a}+8\sqrt{b}\right)\)

12 tháng 10 2021

a)\(3a-2\sqrt{ab}-b=3a-3\sqrt{ab}+\sqrt{ab}-b=\left(\sqrt{a}-\sqrt{b}\right)\left(3\sqrt{a}+\sqrt{b}\right)\)

b)\(5a+3\sqrt{ab}-8b=5a-5\sqrt{ab}+8\sqrt{ab}-8b=\left(\sqrt{a}-\sqrt{b}\right)\left(5\sqrt{a}+8\sqrt{b}\right)\)

12 tháng 10 2021

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12 tháng 10 2021

a)

  3a-2\sqrt{ab}-b=3a-3\sqrt{ab}+\sqrt{ab}-b\\ =3\sqrt{a}\left(\sqrt{a}-\sqrt{b}\right)+\sqrt{b}\left(\sqrt{a}-\sqrt{b}\right)\\ =\left(\sqrt{a}-\sqrt{b}\right)\left(3\sqrt{a}+\sqrt{b}\right)3a2abb=3a3ab+abb=3a(ab)+b(ab)=(ab)(3a+b)

b)

   5a+3\sqrt{ab}-8b=5a-5\sqrt{ab}+8\sqrt{ab}-8b\\ =5\sqrt{a}\left(\sqrt{a}-\sqrt{b}\right)+8\sqrt{b}\left(\sqrt{a}-\sqrt{b}\right)\\ =\left(\sqrt{a}-\sqrt{b}\right)\left(5\sqrt{a}+8\sqrt{b}\right)5a+3ab8b=5a5ab

12 tháng 10 2021
12 tháng 10 2021

a) \(\left(\sqrt{a}-\sqrt{b}\right)\left(3\sqrt{a}+\sqrt{b}\right)\)

b) \(\left(\sqrt{a}-\sqrt{b}\right)\left(5\sqrt{a}+\sqrt{b}\right)\)

16 tháng 10 2021

a) \(\left(\sqrt{a}-\sqrt{b}\right)\left(3\sqrt{a}+\sqrt{b}\right)\)

b) \(\left(\sqrt{a}-\sqrt{b}\right)\left(5\sqrt{a}+8\sqrt{b}\right)\)

21 tháng 10 2021

a) \(3a-2\sqrt{ab}-b=3a-3\sqrt{ab}+\sqrt{ab}-b=3\sqrt{a}\left(\sqrt{a}-\sqrt{b}\right)+\sqrt{b}\left(\sqrt{a}-\sqrt{b}\right)=\left(\sqrt{a}-\sqrt{b}\right)\left(3\sqrt{a}+\sqrt{b}\right)\)

b) \(5a+3\sqrt{ab}-8b=5a-5\sqrt{ab}+8\sqrt{ab}-8b=5\sqrt{a}\left(\sqrt{a}-\sqrt{b}\right)+8\sqrt{b}\left(\sqrt{a}-\sqrt{b}\right)=\left(\sqrt{a}-\sqrt{b}\right)\left(5\sqrt[]{a}+8\sqrt{b}\right)\)

28 tháng 10 2021

a)3a-2√ab-b=3a-3√ab+√ab-b

=3√a.(√a-√b)+√b.(√a-√b)

=(3√a+√b).(√a-√b)

 

b)5a+3√ab-8b

=5a-5√ab+8√ab-8b

=5√a.(√a-√b)+8√b.(√a-√b)

=(√a-√b).(5√a+8√b)

28 tháng 10 2021

a,,\(3a-2\sqrt{ab}-b=3\sqrt{a}^2-3\sqrt{ab}+\sqrt{ab}-\sqrt{b}^2=3\sqrt{a}\left(\sqrt{a}-\sqrt{b}\right)+\sqrt{b}\left(\sqrt{a}-\sqrt{b}\right)=\left(\sqrt{a}-\sqrt{b}\right)\left(3\sqrt{a}+\sqrt{b}\right)\)

b,

\(5a+3\sqrt{ab}-8b=5\sqrt{a}^2-5\sqrt{ab}+8\sqrt{ab}-8b=\left(\sqrt{a}-\sqrt{b}\right)\left(5\sqrt{a}+8\sqrt{b}\right)\)

28 tháng 10 2021

\(b.=5a+3\sqrt{a}\sqrt{b}-8b\\ \\ \\ =5a+8\sqrt{a}\sqrt{b}-5\sqrt{a}\sqrt{b}-8b=\sqrt{a}\left(5\sqrt{a}+8\sqrt{b}\right)-\sqrt{b}\left(5\sqrt{a}+8\sqrt{b}\right)\\ \\ \\ \\ \\ \\ =\left(5\sqrt{a}+8\sqrt{b}\right)\left(\sqrt{a}-\sqrt{b}\right)\)\(a.=3a-2\sqrt{a}\sqrt{b}-b=3a+\sqrt{a}\sqrt{b}-3\sqrt{a}\sqrt{b}-b=\sqrt{a}\left(3\sqrt{a}+\sqrt{b}\right)-\sqrt{b}\left(3\sqrt{a}+\sqrt{b}\right)=\left(3\sqrt{a}+\sqrt{b}\right)\left(\sqrt{a}-\sqrt{b}\right)\)

28 tháng 10 2021

a)3a-2\(\sqrt{ab}\)-b=2a+a-2\(\sqrt{ab}\)-b=(2a-2\(\sqrt{ab}\))+(a-b)=2\(\sqrt{a}\)(\(\sqrt{a}\)-\(\sqrt{b}\))+(a-b)=(\(\sqrt{a}\)-\(\sqrt{b}\))(2\(\sqrt{a}\)+\(\sqrt{a}\)\(\sqrt{b}\))=(\(\sqrt{a}\)-\(\sqrt{b}\))(3\(\sqrt{a}\)+\(\sqrt{b}\))

b)5a+3\(\sqrt{ab}\)-8b=5a+8\(\sqrt{ab}\)-5\(\sqrt{ab}\)-8b=5\(\sqrt{a}\)(\(\sqrt{a}\)-\(\sqrt{b}\))+8\(\sqrt{b}\)(\(\sqrt{a}\)-\(\sqrt{b}\))=(5\(\sqrt{a}\)+8\(\sqrt{b}\))(\(\sqrt{a}\)-\(\sqrt{b}\))

28 tháng 10 2021

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28 tháng 10 2021

a) 3a - 2\(\sqrt{ab}\) - b 

= 3a -3\(\sqrt{ab}\)+\(\sqrt{ab}\)-b

=(\(\sqrt{a}-\sqrt{b}\))(\(3\sqrt{a}+\sqrt{b}\))

b) 5a + \(3\sqrt{ab}\) - 8b

= 5a - 5\(\sqrt{ab}\) + 8\(\sqrt{ab}\) - 8b

= (\(\sqrt{a}-\sqrt{b}\))(5\(\sqrt{a}+8\sqrt{b}\) )

29 tháng 10 2021

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29 tháng 10 2021

a)

  3a-2\sqrt{ab}-b=3a-3\sqrt{ab}+\sqrt{ab}-b\\ =3\sqrt{a}\left(\sqrt{a}-\sqrt{b}\right)+\sqrt{b}\left(\sqrt{a}-\sqrt{b}\right)\\ =\left(\sqrt{a}-\sqrt{b}\right)\left(3\sqrt{a}+\sqrt{b}\right)3a2abb=3a3ab+abb=3a(ab)+b(ab)=(ab)(3a+b)

b)

   5a+3\sqrt{ab}-8b=5a-5\sqrt{ab}+8\sqrt{ab}-8b\\ =5\sqrt{a}\left(\sqrt{a}-\sqrt{b}\right)+8\sqrt{b}\left(\sqrt{a}-\sqrt{b}\right)\\ =\left(\sqrt{a}-\sqrt{b}\right)\left(5\sqrt{a}+8\sqrt{b}\right)5a+3ab8b=5a5ab

29 tháng 10 2021


a)=(√a-√b)(3√a+√b)
b)=(√a-√b)(5√a+8√b)

31 tháng 3 2017

a) ĐS: ; b) ĐS: 26; c) ĐS: 12a

d) - = - 6a + 9 -

= - 6a + 9 - = - 6a + 9 - 6│a│.

Khi a ≥ 0 thì │a│= a.

Do đó - = - 6a + 9 -6a = - 12a + 9.

Khi a < 0 thì │a│= a.

Do đó - = - 6a + 9 + 6a = + 9.

\(A,ĐKXĐ:x;y\ge0\)

\(A=\sqrt{xy}-2\sqrt{y}-5\sqrt{x}+10\)

\(=\sqrt{y}\left(\sqrt{x}-2\right)-5\left(\sqrt{x}-2\right)\)

\(=\left(\sqrt{x}-2\right)\left(\sqrt{y}-5\right)\)

\(ĐKXĐ:x;y\ge0\)

\(B=a\sqrt{x}+b\sqrt{y}-\sqrt{xy}-ab\)

\(=\left(a\sqrt{x}-\sqrt{xy}\right)+\left(b\sqrt{y}-ab\right)\)

\(=\sqrt{x}\left(a-\sqrt{y}\right)+b\left(\sqrt{y}-a\right)\)

\(=\sqrt{x}\left(a-\sqrt{y}\right)-b\left(a-\sqrt{y}\right)\)

\(=\sqrt{x}\left(a-\sqrt{y}\right)-b\left(a-\sqrt{y}\right)\)

\(=\left(a-\sqrt{y}\right)\left(\sqrt{x}-b\right)\)

14 tháng 8 2019

\(\sqrt{ab}-\sqrt{a}-\sqrt{b}+1\)

\(=\sqrt{a}\left(\sqrt{b}-1\right)-\left(\sqrt{b}-1\right)\)

\(=\left(\sqrt{a}-1\right)\left(\sqrt{b}-1\right)\)

14 tháng 8 2019

\(\sqrt{ab}-\sqrt{a}-\sqrt{b}+1=\sqrt{a}\left(\sqrt{b}-1\right)-\left(\sqrt{b}-1\right)=\left(\sqrt{a}-1\right)\left(\sqrt{b}-1\right)\)

\(=\sqrt{a}\left(\sqrt{a}+1\right)+2\sqrt{b}\left(\sqrt{a}+1\right)=\left(\sqrt{a}+1\right)\left(\sqrt{a}+2\sqrt{b}\right)\)

20 tháng 6 2021

a) 2a−4b=2(a−2b)2a−4b=2(a−2b)

c) 2ax−2ay+2a=2a(x−y+1)2ax−2ay+2a=2a(x−y+1)

e) 3xy(x−4)−9x(4−x)=3x(x−4)(y+3)3xy(x−4)−9x(4−x)=3x(x−4)(y+3)

b,d xem lại đề

20 tháng 6 2021

không hiểu

 what are you doing?

16 tháng 7 2019

\(\text{a)}x\sqrt{x}+\sqrt{x}-x-1\)

\(=\left(x\sqrt{x}+\sqrt{x}\right)-\left(x+1\right)\)

\(=\sqrt{x}\left(x+1\right)-\left(x+1\right)\)

\(=\left(x+1\right)\left(\sqrt{x}-1\right)\)

\(\text{b)}\sqrt{ab}+2\sqrt{a}+3\sqrt{b}+6\)

\(=\left(\sqrt{ab}+2\sqrt{a}\right)+\left(3\sqrt{b}+6\right)\)

\(=\sqrt{a}\left(\sqrt{b}+2\right)+3\left(\sqrt{b}+2\right)\)

\(=\left(\sqrt{b}+2\right)\left(\sqrt{a}+3\right)\)

\(\text{c)}\left(1+\sqrt{x}\right)^2-4\sqrt{x}\)

\(=\left(1+\sqrt{x}\right)^2-\left(2\sqrt{\sqrt{x}}\right)^2\)

\(=\left(1+\sqrt{x}+2\sqrt{\sqrt{x}}\right)\left(1+\sqrt{x}-2\sqrt{\sqrt{x}}\right)\)

\(\text{d)}\sqrt{ab}-\sqrt{a}-\sqrt{b}+1\)

\(=\left(\sqrt{ab}-\sqrt{a}\right)-\left(\sqrt{b}-1\right)\)

\(=\sqrt{a}\left(\sqrt{b}-1\right)-\left(\sqrt{b}-1\right)\)

\(=\left(\sqrt{b}-1\right)\left(\sqrt{a}-1\right)\)

\(\text{e)}a+\sqrt{a}+2\sqrt{ab}+2\sqrt{b}\)

\(=\left(a+\sqrt{a}\right)+\left(2\sqrt{ab}+2\sqrt{b}\right)\)

\(=\left[\left(\sqrt{a}\right)^2+\sqrt{a}\right]+\left(2\sqrt{ab}+2\sqrt{b}\right)\)

\(=\sqrt{a}\left(\sqrt{a}+1\right)+2\sqrt{b}\left(\sqrt{a}+1\right)\)

\(=\left(\sqrt{a}+1\right)\left(\sqrt{a}+2\sqrt{b}\right)\)

\(\text{f)}x-2\sqrt{x-1}-a^2\)

\(=\left(\sqrt{x-2}\right)^2\left(\sqrt{\sqrt{x-1}}\right)^2-a^2\)

\(=\left(\sqrt{x-2}\sqrt{\sqrt{x-1}}\right)^2-a^2\)

\(=\left(\sqrt{x-2\sqrt{x-1}}\right)^2-a^2\)

\(=\left(\sqrt{x-2\sqrt{x-1}}+a\right)\left(\sqrt{x-2\sqrt{x-1}}-a\right)\)

22 tháng 6 2019

\(ab+b\sqrt{a}+\sqrt{a}+1\)

(đk: \(a\ge0\))

\(=b\sqrt{a}\left(\sqrt{a}+1\right)+\sqrt{a}+1=\left(\sqrt{a}+1\right)\left(b\sqrt{a}+1\right)\)

22 tháng 6 2019

ĐK: \(x,y\ge0\)

\(\sqrt{x^3}-\sqrt{y^3}+\sqrt{x^2y}-\sqrt{xy^2}=x\left(\sqrt{x}+\sqrt{y}\right)-y\left(\sqrt{x}+\sqrt{y}\right)=\left(\sqrt{x}+\sqrt{y}\right)\left(x-y\right)\)

\(=\left(\sqrt{x}+\sqrt{y}\right)^2\left(\sqrt{x}-\sqrt{y}\right)\)

1 tháng 4 2017

Để học tốt Toán 9 | Giải bài tập Toán 9