0,(3) = 1/3

0,0(3) = 1/30

0,(384615) = 5/13 

ngô minh hoàng

\(\Leftrightarrow\dfrac{\dfrac{3}{10}+\dfrac{5}{13}+\dfrac{3}{13}x}{\dfrac{1}{30}+13}=\dfrac{50}{85}\)

\(\Leftrightarrow x\cdot\dfrac{3}{13}+\dfrac{89}{130}=\dfrac{23}{3}\)

=>3/13x=2723/390

hay x=2723/90

a) \(\left[0,\left(37\right)+0,\left(62\right)\right]\cdot x=10\)

=> \(\left[\frac{37}{99}+\frac{62}{99}\right]\cdot x=10\)

=> \(1\cdot x=10\Rightarrow x=10\)

b) \(\frac{0,\left(12\right)}{1,\left(6\right)}=\frac{\frac{12}{99}}{\frac{5}{3}}=\frac{12}{99}\cdot\frac{3}{5}=\frac{4}{55}\)

=> \(\frac{4}{55}=x:0,\left(4\right)\)

=> \(\frac{4}{55}=x:\frac{4}{9}\)

=> \(x:\frac{4}{9}=\frac{4}{55}\)

=> \(x=\frac{4}{55}\cdot\frac{4}{9}=\frac{16}{495}\)

Bài 1:

a) \(0,\left(3\right)+3\dfrac{1}{3}+0,4\left(2\right)\)

\(=\dfrac{1}{3}+\dfrac{10}{3}+\dfrac{19}{45}\)

\(=\dfrac{184}{45}\)

b) \(\dfrac{4}{9}+1,2\left(31\right)-0,\left(13\right)\)

\(=\dfrac{4}{9}+\dfrac{1219}{990}-\dfrac{13}{99}\)

\(=\dfrac{1789}{990}\)

Bài 2:

a) \(0,\left(37\right)x=1\)

\(\Leftrightarrow\dfrac{37}{99}.x=1\)

\(\Leftrightarrow x=1:\dfrac{37}{99}\)

\(\Leftrightarrow x=\dfrac{99}{37}\)

b) \(0,\left(26\right)x=1,2\left(31\right)\)

\(\Leftrightarrow\dfrac{26}{99}x=\dfrac{1219}{990}\)

\(\Leftrightarrow x=\dfrac{1219}{990}:\dfrac{26}{99}\)

\(\Leftrightarrow x=\dfrac{1219}{260}\)

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Bài 1:

a) \(0,\left(3\right)+3\frac{1}{3}+0,\left(31\right)\)

\(=\frac{1}{3}+\frac{10}{3}+\frac{31}{99}\)

\(=\frac{11}{3}+\frac{31}{99}\)

\(=\frac{394}{99}.\)

b) \(\frac{4}{9}+1,2\left(31\right)-0,\left(13\right)\)

\(=\frac{4}{9}+\frac{1219}{990}-\frac{13}{99}\)

\(=\frac{553}{330}-\frac{13}{99}\)

\(=\frac{139}{90}.\)

Bài 2:

\(0,\left(37\right).x=1\)

\(\Rightarrow\frac{37}{99}.x=1\)

\(\Rightarrow x=1:\frac{37}{99}\)

\(\Rightarrow x=\frac{99}{37}\)

Vậy \(x=\frac{99}{37}.\)

Chúc bạn học tốt!

Phương Nguyễn Mai Bạn thử xem ở đây nhé:

Đề bài là gì vậy bạn ??? Tính hay tìm x ?

\(\frac{0,\left(3\right)+0,\left(384615\right)+\frac{3}{13}x}{0,0\left(3\right)+13}\)

\(=\frac{\frac{1}{3}+\frac{5}{13}+\frac{3}{13}x}{\frac{1}{30}+13}=\frac{\frac{1}{3}+\frac{5+3x}{13}}{\frac{391}{30}}=\frac{\frac{13+3\left(5+3x\right)}{39}}{\frac{391}{30}}\)

\(=\frac{\frac{13+15+9x}{39}}{\frac{391}{90}}=\frac{\frac{28+9x}{39}}{\frac{391}{90}}=\frac{28+9x}{39}\cdot\frac{90}{391}\)

P/S : Sai đề trầm trọng

Tìm x nha