Bài 1 :

a , x = 675

b , x = 1764

c , x = 0

Bài 2 :

a , x = 3 , 2 , 1 , 0

b , x = 6 , 5 , 4 , 3 , 2 , 1 , 0

c , x = 3 , 4

Bài 1:Tìm x

a, x:5=27\(x\)5

    x:5=135

    x  =135\(x\)5

    x  =675

b, x:7=36\(x\)7

    x:7=252

    x  =252\(x\)7

    x  =1764

c,x\(x\)132=312 x (5-3-2)

  x\(x\)132=312x0

x\(x\)132=0

x          =0:132

x          =0

[(1+9)+(2+8)+(3+7)+(4+6)+5]x2

=(10+10+10+10+5)x2

=45x2

=90

50x2+2x10

=2x(50+10)

=2x60

=120

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

a) x.4/5:2=6/7                                                              

    x.4/5=6/7*2

    x.4/5=12/7

    x=12/7:4/5

    x=15/7

b) 6/5:x:5/4=10/15

    6/5:x=10/15*5/4

    6/5:x=5/6

    x=6/5:5/6

    x=36/25

a)x+10=30

=>x=20

b)x+10-5=20+20

x+10-5=40

x+10=45

=>x=35

x + 10 = 50 - 20

x + 10 = 30

x = 20 

x + 10 - 5 = 20 + 20

x + 5 = 40

x = 35 

Tui không biết nha giúp tui làm

550 bạn nhé

C1: \(\left(\frac{3}{5}+\frac{4}{9}\right)\cdot\frac{3}{8}=\frac{47}{45}\cdot\frac{3}{8}=\frac{141}{360}=\frac{47}{120}\)

C2: \(\left(\frac{3}{5}+\frac{4}{9}\right)\cdot\frac{3}{8}=\frac{3}{5}\cdot\frac{3}{8}+\frac{4}{9}\cdot\frac{3}{8}=\frac{9}{40}+\frac{12}{72}=\frac{47}{120}\)

C1: ( \(\frac{3}{5}+\frac{4}{9}\) ) * \(\frac{3}{8}\) 

= \(\frac{47}{45}\) * \(\frac{3}{8}\) = \(\frac{47}{120}\) 

C2: Đề

= 3/5 * 3/8 + 4/9 * 3/8

= 9/40 + 1/6

= 47/120

15 x 5 + 3 x 5 + 5 x 2 - 10 x 5

= 5 x(15 + 3 + 2 - 10)

= 5 x 10

= 50

=5x(15+3+5+2-10)

=5x10

=50

bằng 115

= 115